Rosetta Code/Rank languages by popularity: Difference between revisions

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(→‎{{header|Ruby}}: use the Programming_Languages category)
(added python fail-proof solution)
Line 453: Line 453:
for n, i in enumerate(sorted(result,key=key1,reverse=True)):
for n, i in enumerate(sorted(result,key=key1,reverse=True)):
print "%3d. %3d - %s" % (n+1, i[1], i[0])</lang>
print "%3d. %3d - %s" % (n+1, i[1], i[0])</lang>

Fail-proof solution

<lang python>import json
import urllib

result = []

langs = json.load(urllib.urlopen("http://www.rosettacode.org/w/api.php?\
action=query&list=categorymembers&cmtitle=Category:Programming_Languages\
&cmlimit=500&format=json"));

titles = [i['title'] for i in langs['query']['categorymembers']]

while titles:
t = '|'.join(titles[:50])
info = json.load(urllib.urlopen("http://www.rosettacode.org/w/api.php?\
action=query&prop=categoryinfo&format=json",
data=urllib.urlencode({"titles":t})))['query']['pages']
for i in info:
try:
result.append([info[i]['title'], info[i]['categoryinfo']['pages']])
except:
pass
del titles[:50]

c = 0
for i in sorted(result,key=lambda x: x[1],reverse=True):
c += 1
print "%d. %s - %d" % (c, i[0].replace("Category:",''), i[1])</lang>


=={{header|Ruby}}==
=={{header|Ruby}}==

Revision as of 01:54, 16 June 2009

Task
Rosetta Code/Rank languages by popularity
You are encouraged to solve this task according to the task description, using any language you may know.

Sort most popular programming languages based in number of members in Rosetta Code categories (from http://www.rosettacode.org/w/index.php?title=Special:Categories&limit=500)

Output:

1. 233 - Python
2. 222 - Ada
3. 203 - OCaml
4. 203 - C
5. 201 - Perl
6. 193 - Haskell
7. 182 - Java
8. 179 - D
9. 178 - ALGOL 68
10. 160 - Ruby
...

Filtering wrong results is optional. You can check against http://www.rosettacode.org/wiki/Special:MostLinkedCategories

Ada

Library: AWS

NB: The 'ASCII.Quotation' in the declaration of Title_Str is a rather clunky workaround to the Ada->HTML engine not being able to correctly colourize '"' properly.

<lang ada>with Ada.Integer_Text_IO; use Ada.Integer_Text_IO; with Ada.Strings.Fixed; use Ada.Strings.Fixed; with Ada.Strings.Unbounded; use Ada.Strings.Unbounded; with Ada.Text_IO; use Ada.Text_IO;

with Ada.Containers.Ordered_Sets; with Ada.Strings.Less_Case_Insensitive;

with AWS.Client; with AWS.Response;

procedure Test is

  use Ada.Strings;

  function "+" (S : String) return Unbounded_String renames To_Unbounded_String;

  type A_Language_Count is
     record
        Count    : Integer := 0;
        Language : Unbounded_String;
     end record;

  function "=" (L, R : A_Language_Count) return Boolean is
  begin
     return L.Count = R.Count;
  end "=";

  function "<" (L, R : A_Language_Count) return Boolean is
  begin
     -- Sort by 'Count' and then by Language name
     return L.Count < R.Count
       or else (L.Count = R.Count
                and then Less_Case_Insensitive (Left  => To_String (L.Language),
                                                Right => To_String (R.Language)));
  end "<";

  package Sets is new Ada.Containers.Ordered_Sets (A_Language_Count);
  use Sets;

  Counts : Set;

  procedure Find_Counts (S : String) is
     Title_Str : constant String  := "title=" & ASCII.Quotation & "Category:";
     End_A_Str : constant String  := "</a> (";

     Title_At   : constant Natural := Index (S, Title_Str);
     Bracket_At : constant Natural := Index (S (Title_At   + Title_Str'Length .. S'Last), ">");
     End_A_At   : constant Natural := Index (S (Bracket_At + 1                .. S'Last), End_A_Str);
     Space_At   : constant Natural := Index (S (End_A_At   + End_A_Str'Length .. S'Last), " ");
  begin
     if Title_At /= 0 and then Bracket_At /= 0 and then End_A_At /= 0 and then Space_At /= 0 then
        declare
           Count    : constant Natural := Natural'Value (S (End_A_At + End_A_Str'Length .. Space_At - 1));
           Language : constant String  :=                S (Title_At + Title_Str'Length .. Bracket_At - 2);
        begin
           Counts.Insert (New_Item => (Count, +Language));
        end;

        -- Recursively parse the string for languages and counts
        Find_Counts (S (Space_At + 1 .. S'Last));
     end if;
  exception
     when others =>
        null; -- Catch and ignore the error after the last language
  end Find_Counts;

  Place : Natural := 1;

  procedure Display (C : Cursor) is
  begin
     Put (Place, Width => 1);             Put (". ");
     Put (Element (C).Count, Width => 1); Put (" - ");
     Put_Line (To_String (Element (C).Language));
     Place := Place + 1;
  end Display;

  Http_Source : constant AWS.Response.Data :=
    AWS.Client.Get ("http://www.rosettacode.org/w/index.php?title=Special:Categories&limit=500");

begin

  Find_Counts (AWS.Response.Message_Body (Http_Source));
  Counts.Reverse_Iterate (Display'Access);

end Test;</lang>

ALGOL 68

Works with: ALGOL 68G version mk8+ for Unix and Linux - tested with release mk15-0.8b.fc9.i386 - uses non-standard library routines http content and grep in string.

Note: the routine http content is currently not available on Win32 systems. <lang algol>PROC good page = (REF STRING page) BOOL:

    IF grep in string("^HTTP/[0-9.]* 200", page, NIL, NIL) = 0
    THEN TRUE
    ELSE IF INT start, end;
             grep in string("^HTTP/[0-9.]* [0-9]+ [a-zA-Z ]*", page,
                            start, end) = 0
         THEN print (page[start : end])
         ELSE print ("unknown error retrieving page")
         FI;
         FALSE
    FI;

MODE LISTOFSTRING = STRUCT(REF LINK first, last, INT upb); MODE LINK = STRUCT(STRING value, REF LINK next);

PRIO LISTINIT = 1; OP LISTINIT = (REF LISTOFSTRING new, REF LINK first)REF LISTOFSTRING: (

 new := (first, first, (first IS REF LINK(NIL) | 0 | 1 ));
 new

);

OP +:= = (REF LISTOFSTRING list, []CHAR item)VOID: (

 HEAP LINK new := (STRING(item), REF LINK(NIL));
 IF first OF list IS REF LINK(NIL) THEN
   first OF list := new
 ELSE
   next OF last OF list := new
 FI;
 last OF list := new;
 upb OF list +:= 1

);

OP UPB = (LISTOFSTRING list)INT: upb OF list;

OP ARRAYOFSTRING = (LISTOFSTRING list)[]STRING:(

 [UPB list]STRING out;
 REF LINK this := first OF list;
 FOR i TO UPB list DO out[i] := value OF this; this := next OF this OD;
 out

);

INT match=0, no match=1, out of memory error=2, other error=3;

PROC re split = (STRING re split, REF STRING beetles)[]STRING:(

   LISTOFSTRING out := (NIL, NIL, 0); # LISTINIT REF LINK NIL; #
   INT start := 1, pos, end;
   WHILE grep in string(re split, beetles[start:], pos, end) = match DO
     out +:= beetles[start:start+pos-2];
     out +:= beetles[start+pos-1:start+end-1];
     start +:= end
   OD;
   IF start > UPB beetles THEN
     out +:= beetles[start:]
   FI;
   ARRAYOFSTRING(out)
 );


IF STRING reply;

  INT rc =
     http content (reply, "www.rosettacode.org", "http://www.rosettacode.org/w/index.php?title=Special:Categories&limit=500", 0);
  rc /= 0 OR NOT good page (reply)

THEN print (("Error:",strerror (rc))) ELSE

 STRING  # hack: HTML should be parsed by an official HTML parsing library #
   re html tag = "<[^>]*>",
   re a href category = "^<a href=""/wiki/Category:.*"" title=",
   re members = "([1-9][0-9]* members)";
 MODE STATISTIC = STRUCT(INT members, STRING category);
 FLEX[0]STATISTIC stats;
 OP +:=  = (REF FLEX[]STATISTIC in out, STATISTIC item)VOID:(
     [LWB in out: UPB in out+1]STATISTIC new;
     new[LWB in out: UPB in out]:=in out;
     new[UPB new]:=item;
     in out := new
   );
  1. hack: needs to be manually maintained #
 STRING re ignore ="Programming Tasks|WikiStubs|Maintenance/OmitCategoriesCreated|"+
                   "Unimplemented tasks by language|Programming Languages|"+
                   "Solutions by Programming Language|Implementations|"+
                   "Solutions by Library|Encyclopedia|Language users|"+
                   "Solutions by Programming Task|Basic language learning|"+
                   "RCTemplates|Language Implementations";
 FORMAT category fmt = $"<a href=""/wiki/Category:"g""" title=""Category:"g""""$;
 STRING encoded category, category;
 FORMAT members fmt = $" ("g" members)"$;
 INT members;
 FLEX[0]STRING tokens := re split(re html tag, reply);
 FOR token index TO UPB tokens DO
   STRING token := tokens[token index];
   FILE file;
   IF grep in string(re a href category, token, NIL, NIL) = match THEN
     associate(file, token);
     make term(file,"""");
     getf(file, (category fmt, encoded category, category));
     close(file)
   ELIF grep in string(re members, token, NIL, NIL) = match THEN
     IF grep in string(re ignore, category, NIL, NIL) /= match THEN
       associate(file, token);
       getf(file, (members fmt, members));
       stats +:= STATISTIC(members, category);
       close(file)
     FI
   FI
 OD;
 OP < = (STATISTIC a,b)BOOL:
   members OF a < members OF b;
 MODE SORTSTRUCT = STATISTIC;
 PR READ "prelude/sort.a68" PR;
 stats := in place shell sort reverse(stats);
 INT max = 10;
 FOR i TO (UPB stats > max | max | UPB stats) DO
   printf(($g(-0)". "g(-0)" - "gl$,i,stats[i]))
 OD

FI</lang> Output:

1. 233 - Python
2. 222 - Ada
3. 203 - OCaml
4. 203 - C
5. 201 - Perl
6. 193 - Haskell
7. 182 - Java
8. 179 - D
9. 178 - ALGOL 68
10. 160 - Ruby

AutoHotkey

<lang AutoHotkey> filedelete, url.txt urldownloadtofile, http://www.rosettacode.org/w/index.php?title=Special:Categories&limit=500, url.txt loop, read, url.txt {

if instr(A_LoopReadLine, "

  • ") { reg = title=\"Category:(.+?)" regexmatch(A_LoopReadLine, reg, name) regexmatch(A_LoopReadLine, "(\d*)\smembers", count) print = %count1% `- %name1% `n %print% } } sort, print, RN msgbox %print% </lang>

    AWK

    Works with: gawk

    This solution needs help from external tools to fetch the HTML from rosettacode.org, and also to do a numeric sort <lang sh>printf "GET %s HTTP/1.0\n\n" 'http://www.rosettacode.org/w/index.php?title=Special:Categories&limit=500' | nc www.rosettacode.org 80 | gawk '

       # ignore categories that are not languages
       /Basic language learning/            {next}
       /Encyclopedia/                       {next}
       /Implementations/                    {next}
       /Language Implementations/           {next}
       /Language users/                     {next}
       /Maintenance\/OmitCategoriesCreated/ {next}
       /Programming Languages/              {next}
       /Programming Tasks/                  {next}
       /RCTemplates/                        {next}
       /Solutions by Library/               {next}
       /Solutions by Programming Language/  {next}
       /Solutions by Programming Task/      {next}
       /Unimplemented tasks by language/    {next}
       /WikiStubs/                          {next}
    
       match($0, /<li.*>([^<]*)<\/a> \((digit:+) members?/, m) {
           lang[++i] = m[2] " - " m[1]
       }
    
       END {
           len = 0; for (i in lang) len++
           sorter = "sort -rn"
           for (i = 1; i <= len; i++) {
               print lang[i] |& sorter
           }
           close(sorter, "to")
           i = 1
           while((sorter |& getline line) > 0) {
               print i++ ". " line
           }
           close(sorter)
       }
    

    '</lang>

    C#

    Sorting only programming languages.

    <lang csharp>using System; using System.Net; using System.Linq; using System.Text; using System.Text.RegularExpressions; using System.Collections; using System.Collections.Generic;

    class Program {

       static void Main(string[] args)
       {
           string get1 = new WebClient().DownloadString("http://www.rosettacode.org/w/api.php?action=query&list=categorymembers&cmtitle=Category:Programming_Languages&cmlimit=500&format=json");
           string get2 = new WebClient().DownloadString("http://www.rosettacode.org/w/index.php?title=Special:Categories&limit=500");
    
           ArrayList langs = new ArrayList();
           Dictionary<string, int> qtdmbr = new Dictionary<string, int>();
    
           MatchCollection match1 = new Regex("\"title\":\"Category:(.+?)\"").Matches(get1);
           MatchCollection match2 = new Regex("title=\"Category:(.+?)\">.+?</a> \\((\\d+) members\\)").Matches(get2);
           
           foreach (Match lang in match1) langs.Add(lang.Groups[1].Value);
    
           foreach (Match match in match2) {
               if (langs.Contains(match.Groups[1].Value)) {
                   qtdmbr.Add(match.Groups[1].Value, Int32.Parse(match.Groups[2].Value));                 
               }
           }
           
           string[] test = qtdmbr.OrderByDescending(x => x.Value).Select(x => String.Format("{0} - {1}", x.Key, x.Value)).ToArray();
    
           int count = 1;
    
           foreach (string i in test)
           {
               Console.WriteLine("{0}. {1}",count,i);
               count++;
           }
       }
    

    }</lang>

    Object-orinted solution

    <lang csharp>using System; using System.Net; using System.Linq; using System.Text; using System.Text.RegularExpressions; using System.Collections.Generic;

    class Category {

       private string _title;
       private int _members;
    
       public Category(string title, int members) {
           _title = title;
           _members = members;
       }
    
       public string Title {
           get {
               return _title;
           }
       }
    
       public int Members {
           get {
               return _members;
           }
       }
    

    }

    class Program {

       static void Main(string[] args) {
           string get1 = new WebClient().DownloadString("http://www.rosettacode.org/w/api.php?action=query&list=categorymembers&cmtitle=Category:Programming_Languages&cmlimit=500&format=json");
           string get2 = new WebClient().DownloadString("http://www.rosettacode.org/w/index.php?title=Special:Categories&limit=500");
    
           MatchCollection match1 = new Regex("\"title\":\"Category:(.+?)\"").Matches(get1);
           MatchCollection match2 = new Regex("title=\"Category:(.+?)\">.+?</a> \\((\\d+) members\\)").Matches(get2);
    
           string[] valids = match1.Cast<Match>().Select(x => x.Groups[1].Value).ToArray();
           List<Category> langs = new List<Category>();
    
           foreach (Match match in match2) {
               string category = match.Groups[1].Value;
               int members = Int32.Parse(match.Groups[2].Value);
    
               if (valids.Contains(category)) langs.Add(new Category(category, members));
           }
    
           langs = langs.OrderByDescending(x  => x.Members).ToList();
           int count = 1;
    
           foreach (Category i in langs) {
               Console.WriteLine("{0}. {1} - {2}", count, i.Title, i.Members);
               count++;
           }
       }
    

    }</lang>

    Perl

    Sorting only programming languages.

    <lang perl>use LWP::Simple 'get';

    my $langs_url = 'http://www.rosettacode.org/w/api.php?action=query&list=categorymembers&cmtitle=Category:Programming_Languages&cmlimit=500&format=json'; my $cats_url = 'http://www.rosettacode.org/w/index.php?title=Special:Categories&limit=500';

    my %langs = map {/Category:(.+)/, 1}

       get($langs_url) =~ /"title":"(.+?)"}/g;
    
    get($cats_url) =~ m{
    • (.+?)
    }s;

    my @pairs =

       sort {$b->[1] <=> $a->[1]}
       grep {$langs{ $_->[0] }}
       map {[ m{>(\S.*?)</a> \((\d+) member} ]}
    
    split '
  • ', $1; for (my $n = 1 ; @pairs ; ++$n) {my ($lang, $tasks) = @{shift @pairs}; printf "%3d. %3d - %s\n", $n, $tasks, $lang;}</lang>

    Python

    Sorting only programming languages.

    <lang python>import urllib,re

    key1 = lambda x: int(x[1])

    get1 = urllib.urlopen("http://www.rosettacode.org/w/api.php?action=query&list=categorymembers&cmtitle=Category:Programming_Languages&cmlimit=500&format=json").read() get2 = urllib.urlopen("http://www.rosettacode.org/w/index.php?title=Special:Categories&limit=500").read()

    langs = re.findall("\"title\":\"Category:(.+?)\"",get1) qtdmbr = re.findall("title=\"Category:(.+?)\">.+?</a> \((\d+) members\)",get2)

    result = [(x,int(y)) for x,y in qtdmbr if x in langs]

    for n, i in enumerate(sorted(result,key=key1,reverse=True)):

       print "%3d. %3d - %s" % (n+1, i[1], i[0])</lang>
    

    Fail-proof solution

    <lang python>import json import urllib

    result = []

    langs = json.load(urllib.urlopen("http://www.rosettacode.org/w/api.php?\ action=query&list=categorymembers&cmtitle=Category:Programming_Languages\ &cmlimit=500&format=json"));

    titles = [i['title'] for i in langs['query']['categorymembers']]

    while titles: t = '|'.join(titles[:50])

    info = json.load(urllib.urlopen("http://www.rosettacode.org/w/api.php?\ action=query&prop=categoryinfo&format=json", data=urllib.urlencode({"titles":t})))['query']['pages']

    for i in info: try: result.append([info[i]['title'], info[i]['categoryinfo']['pages']]) except: pass

    del titles[:50]

    c = 0

    for i in sorted(result,key=lambda x: x[1],reverse=True): c += 1 print "%d. %s - %d" % (c, i[0].replace("Category:",), i[1])</lang>

    Ruby

    Now that there are more than 500 categories, the URL given in the task description is insufficient. I use the RC API to grab the categories, and then count the members of each category.

    Uses the RosettaCode module from Count programming examples#Ruby <lang ruby>require 'rosettacode'

    langs = Hash.new(0) RosettaCode.rc_tasks("Programming_Languages") do |lang|

     sleep 1   # don't kill the server
     lang = (lang.split(":"))[-1]
     RosettaCode.rc_tasks(lang) do |task|
       langs[lang] += 1
     end
    

    end

    puts "There are #{langs.length} languages" puts "the top 10:" langs.sort_by {|key,val| val}.reverse.each_with_index do |pair, i|

     lang, count = pair
     puts "#{i+1}. #{count} - #{lang}"
    

    end</lang>

    There are 139 languages
    the top 10:
    1. 313 - Tcl
    2. 270 - Python
    3. 236 - Ada
    4. 232 - Ruby
    5. 229 - C
    6. 222 - Perl
    7. 209 - OCaml
    8. 206 - Java
    9. 200 - Haskell
    10. 198 - ALGOL 68

    Tcl

    <lang tcl>package require Tcl 8.5 package require http

    set response [http::geturl http://www.rosettacode.org/w/index.php?title=Special:Categories&limit=500]

    array set ignore {

       "Basic language learning"           1
       "Encyclopedia"                      1
       "Implementations"                   1
       "Language Implementations"          1
       "Language users"                    1
       "Maintenance/OmitCategoriesCreated" 1
       "Programming Languages"             1
       "Programming Tasks"                 1
       "RCTemplates"                       1
       "Solutions by Library"              1
       "Solutions by Programming Language" 1
       "Solutions by Programming Task"     1
       "Unimplemented tasks by language"   1
       "WikiStubs"                         1
    

    }

    foreach line [split [http::data $response] \n] {

       if {[regexp {>([^<]+)</a> \((\d+) member} $line -> lang num]} {
           if { ! [info exists ignore($lang)]} {
               lappend langs [list $num $lang]
           }
       }
    

    }

    foreach entry [lsort -integer -index 0 -decreasing $langs] {

       lassign $entry num lang
       puts [format "%d. %d - %s" [incr i] $num $lang]
    

    }</lang> Produces this output on 24 May 2009 (top 15 entries only):

    1. 286 - Tcl
    2. 244 - Python
    3. 229 - Ada
    4. 221 - C
    5. 213 - Perl
    6. 204 - OCaml
    7. 198 - ALGOL 68
    8. 197 - Haskell
    9. 190 - Java
    10. 184 - D
    11. 163 - Ruby
    12. 159 - C++
    13. 159 - E
    14. 157 - Forth
    15. 147 - Fortran
    ……

    UnixPipes

    <lang bash> echo "GET http://www.rosettacode.org/w/index.php?title=Special:Categories&limit=500 HTTP/1.0\n\n"

     | nc www.rosettacode.org 80 
     | sed -n -e 's,<[^>]*>,,g' -e's,^\([^(]*\)(\([^)]*\) members*) *,\2 - \1,g' -e'/^[0-9]\+./p'
     | sort -rn</lang>