Rename a file: Difference between revisions

From Rosetta Code
Content added Content deleted
(→‎{{header|Python}}: Use OS-portable directory separator)
m (Fixed lang tags.)
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=={{header|Ada}}==
=={{header|Ada}}==
<lang ada>with Ada.Directories; use Ada.Directories;
<lang ada>
with Ada.Directories; use Ada.Directories;
...
...
Rename ("input.txt", "output.txt");
Rename ("input.txt", "output.txt");
Rename ("docs", "mydocs");
Rename ("docs", "mydocs");
Rename ("/input.txt", "/output.txt");
Rename ("/input.txt", "/output.txt");
Rename ("/docs", "/mydocs");
Rename ("/docs", "/mydocs");</lang>
</lang>
The behavior depends on the concrete [[OS | operating system]] regarding:
The behavior depends on the concrete [[OS | operating system]] regarding:
* file name encoding issues;
* file name encoding issues;
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<!-- {{does not work with|ELLA ALGOL 68|Any (with appropriate job cards) - tested with release 1.8.8d.fc9.i386 - ''get directory'' and'' grep in string'' not available in any library ... yet}} -->
<!-- {{does not work with|ELLA ALGOL 68|Any (with appropriate job cards) - tested with release 1.8.8d.fc9.i386 - ''get directory'' and'' grep in string'' not available in any library ... yet}} -->
Note: <tt>reidf</tt> does not appear to be included in [[ALGOL 68G]]. Also note that file names would be Operating System dependent.
Note: <tt>reidf</tt> does not appear to be included in [[ALGOL 68G]]. Also note that file names would be Operating System dependent.
<lang algol>
<lang algol68>main:(
main:(
PROC rename = (STRING source name, dest name)INT:
PROC rename = (STRING source name, dest name)INT:
BEGIN
BEGIN
Line 49: Line 46:
=={{header|AWK}}==
=={{header|AWK}}==
Awk allows to call operating system commands with the ''system()'' function. However, the awk script won't get its output, only the return code. But this task is simple enough for the trivial implementation to work:
Awk allows to call operating system commands with the ''system()'' function. However, the awk script won't get its output, only the return code. But this task is simple enough for the trivial implementation to work:
$ awk 'BEGIN{system("mv input.txt output.txt"}'
<lang awk>$ awk 'BEGIN{system("mv input.txt output.txt"}'
$ awk 'BEGIN{system("mv docs mydocs")}'
$ awk 'BEGIN{system("mv docs mydocs")}'
$ awk 'BEGIN{system("mv /input.txt /output.txt")}'
$ awk 'BEGIN{system("mv /input.txt /output.txt")}'
$ awk 'BEGIN{system("mv docs mydocs")}'
$ awk 'BEGIN{system("mv docs mydocs")}'</lang>




=={{header|AutoHotkey}}==
=={{header|AutoHotkey}}==
<lang AutoHotkey>
<lang AutoHotkey>FileMove, oldname, newname</lang>
FileMove, oldname, newname
</lang>
=={{header|C}}==
=={{header|C}}==
<lang c>#include <stdio.h>
<lang c>#include <stdio.h>
Line 73: Line 68:
=={{header|C++}}==
=={{header|C++}}==
{{trans|C}}
{{trans|C}}
<lang cpp>
<lang cpp>#include <cstdio>
#include <cstdio>


int main()
int main()
Line 82: Line 76:
std::rename("/input.txt", "/output.txt");
std::rename("/input.txt", "/output.txt");
std::rename("/docs", "/mydocs");
std::rename("/docs", "/mydocs");
}</lang>
}
</lang>


=={{header|C sharp|C#}}==
=={{header|C sharp|C#}}==
Line 109: Line 102:


=={{header|D}}==
=={{header|D}}==
<lang d>std.file.rename("input.txt","output.txt");
<lang d>
std.file.rename("input.txt","output.txt");
std.file.rename("/input.txt","/output.txt");
std.file.rename("/input.txt","/output.txt");
std.file.rename("docs","mydocs");
std.file.rename("docs","mydocs");
std.file.rename("/docs","/mydocs");
std.file.rename("/docs","/mydocs");</lang>
</lang>


=={{header|DOS Batch File}}==
=={{header|DOS Batch File}}==
Line 130: Line 121:


=={{header|Forth}}==
=={{header|Forth}}==
s" input.txt" s" output.txt" rename-file throw
<lang forth> s" input.txt" s" output.txt" rename-file throw
s" /input.txt" s" /output.txt" rename-file throw
s" /input.txt" s" /output.txt" rename-file throw</lang>


=={{header|Groovy}}==
=={{header|Groovy}}==
Using File
Using File
<lang groovy>['input.txt':'output.txt', 'docs':'mydocs'].each { src, dst ->
<lang groovy>
['input.txt':'output.txt', 'docs':'mydocs'].each { src, dst ->
['.', ''].each { dir ->
new File("$dir/$src").renameTo(new File("$dir/$dst"))
['.', ''].each { dir ->
}
new File("$dir/$src").renameTo(new File("$dir/$dst"))
}</lang>
}
}
</lang>


Using Ant
Using Ant
<lang groovy>['input.txt':'output.txt', 'docs':'mydocs'].each { src, dst ->
<lang groovy>
['input.txt':'output.txt', 'docs':'mydocs'].each { src, dst ->
['.', ''].each { dir ->
new AntBuilder().move(file:"$dir/$src", toFile:"$dir/$dst")
['.', ''].each { dir ->
}
new AntBuilder().move(file:"$dir/$src", toFile:"$dir/$dst")
}</lang>
}
}</lang>


=={{header|Haskell}}==
=={{header|Haskell}}==
<lang haskell> import System.IO
<lang haskell>import System.IO
import System.Directory
import System.Directory

main = do
main = do
renameFile "input.txt" "output.txt"
renameFile "input.txt" "output.txt"
renameDirectory "docs" "mydocs"
renameDirectory "docs" "mydocs"
renameFile "/input.txt" "/output.txt"
renameFile "/input.txt" "/output.txt"
renameDirectory "/docs" "/mydocs"</lang>
renameDirectory "/docs" "/mydocs"</lang>


=={{header|J}}==
=={{header|J}}==
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'kernel32 MoveFileA i *c *c' 15!:0 y;x
'kernel32 MoveFileA i *c *c' 15!:0 y;x
end.
end.
)</lang>
)
</lang>


Useage:
Useage:
<lang j> 'output.txt' frename 'input.txt'
<lang j>'output.txt' frename 'input.txt'
'/output.txt' frename '/input.txt'
'/output.txt' frename '/input.txt'
'mydocs' frename 'docs'
'mydocs' frename 'docs'
'/mydocs' frename '/docs'
'/mydocs' frename '/docs'</lang>
</lang>


=={{header|Java}}==
=={{header|Java}}==
<lang java> import java.util.File;
<lang java>import java.util.File;
public class FileRenameTest {
public class FileRenameTest {
public static boolean renameFile(String oldname, String newname) {
public static boolean renameFile(String oldname, String newname) {
// File (or directory) with old name
// File (or directory) with old name
File file = new File(oldname);
File file = new File(oldname);
// File (or directory) with new name
// File (or directory) with new name
File file2 = new File(newname);
File file2 = new File(newname);
// Rename file (or directory)
// Rename file (or directory)
boolean success = file.renameTo(file2);
boolean success = file.renameTo(file2);
return sucess;
return sucess;
}
}
public static void test(String type, String oldname, String newname) {
public static void test(String type, String oldname, String newname) {
System.out.println("The following " + type + " called " + oldname +
System.out.println("The following " + type + " called " + oldname +
( renameFile(oldname, newname) ? " was renamed as " : " could not be renamed into ")
( renameFile(oldname, newname) ? " was renamed as " : " could not be renamed into ")
+ newname + "."
+ newname + "."
);
);
}
}
public static void main(String args[]) {
public static void main(String args[]) {
test("file", "input.txt", "output.txt");
test("file", "input.txt", "output.txt");
test("file", File.seperator + "input.txt", File.seperator + "output.txt");
test("file", File.seperator + "input.txt", File.seperator + "output.txt");
test("directory", "docs", "mydocs");
test("directory", "docs", "mydocs");
test("directory", File.seperator + "docs" + File.seperator, File.seperator + "mydocs" + File.seperator);
test("directory", File.seperator + "docs" + File.seperator, File.seperator + "mydocs" + File.seperator);
}
}
}</lang>
}</lang>


=={{header|JavaScript}}==
=={{header|JavaScript}}==
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=={{header|Mathematica}}==
=={{header|Mathematica}}==
<lang Mathematica> SetDirectory[NotebookDirectory[]]
<lang Mathematica>SetDirectory[NotebookDirectory[]]
RenameFile["input.txt", "output.txt"]
RenameFile["input.txt", "output.txt"]
RenameDirectory["docs", "mydocs"]
RenameDirectory["docs", "mydocs"]
SetDirectory[$RootDirectory]
SetDirectory[$RootDirectory]
RenameFile["input.txt", "output.txt"]
RenameFile["input.txt", "output.txt"]
RenameDirectory["docs", "mydocs"]</lang>
RenameDirectory["docs", "mydocs"]</lang>


=={{header|MAXScript}}==
=={{header|MAXScript}}==
MAXScript has no folder rename method
MAXScript has no folder rename method
-- Here
<lang maxscript>-- Here
renameFile "input.txt" "output.txt"
renameFile "input.txt" "output.txt"
-- Root
-- Root
renameFile "/input.txt" "/output.txt"
renameFile "/input.txt" "/output.txt"</lang>


=={{header|Objective-C}}==
=={{header|Objective-C}}==
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=={{header|OCaml}}==
=={{header|OCaml}}==
<lang ocaml> Sys.rename "input.txt" "output.txt";;
<lang ocaml>Sys.rename "input.txt" "output.txt";;
Sys.rename "docs" "mydocs";;
Sys.rename "docs" "mydocs";;
Sys.rename "/input.txt" "/output.txt";;
Sys.rename "/input.txt" "/output.txt";;
Sys.rename "/docs" "/mydocs";;</lang>
Sys.rename "/docs" "/mydocs";;</lang>


=={{header|Pascal}}==
=={{header|Pascal}}==
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=={{header|Perl}}==
=={{header|Perl}}==
<lang perl> use File::Copy qw(move);
<lang perl>use File::Copy qw(move);
use File::Spec::Functions qw(catfile rootdir);
use File::Spec::Functions qw(catfile rootdir);
# here
# here
move 'input.txt', 'output.txt';
move 'input.txt', 'output.txt';
move 'docs', 'mydocs';
move 'docs', 'mydocs';
# root dir
# root dir
move (catfile rootdir, 'input.txt'), (catfile rootdir, 'output.txt');
move (catfile rootdir, 'input.txt'), (catfile rootdir, 'output.txt');
move (catfile rootdir, 'docs'), (catfile rootdir, 'mydocs');</lang>
move (catfile rootdir, 'docs'), (catfile rootdir, 'mydocs');</lang>


=={{header|PHP}}==
=={{header|PHP}}==
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=={{header|Pop11}}==
=={{header|Pop11}}==


sys_file_move('inputs.txt', 'output.txt');
<lang pop11>sys_file_move('inputs.txt', 'output.txt');
sys_file_move('docs', 'mydocs');
sys_file_move('docs', 'mydocs');
sys_file_move('/inputs.txt', '/output.txt');
sys_file_move('/inputs.txt', '/output.txt');
sys_file_move(/'docs', '/mydocs');
sys_file_move(/'docs', '/mydocs');</lang>


Note that notion of the root of filesystem is Unix specific, so above we
Note that notion of the root of filesystem is Unix specific, so above we
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=={{header|PowerShell}}==
=={{header|PowerShell}}==
<lang powershell> Rename-Item input.txt output.txt
<lang powershell>Rename-Item input.txt output.txt


# The Rename-item has the alias ren
# The Rename-item has the alias ren
ren input.txt output.txt</lang>
ren input.txt output.txt</lang>


=={{header|Python}}==
=={{header|Python}}==


<lang python>
<lang python>import os

import os
os.rename("input.txt", "output.txt")
os.rename("input.txt", "output.txt")
os.rename("docs", "mydocs")

os.rename("docs", "mydocs")
os.rename(os.sep + "input.txt", os.sep + "output.txt")
os.rename(os.sep + "input.txt", os.sep + "output.txt")
os.rename(os.sep + "docs", os.sep + "mydocs")</lang>
os.rename(os.sep + "docs", os.sep + "mydocs")
</lang>


=={{header|R}}==
=={{header|R}}==
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The <tt>FileUtils#move</tt> method has some more flexibility than the core <tt>File#rename</tt> method (not really demonstrated here).
The <tt>FileUtils#move</tt> method has some more flexibility than the core <tt>File#rename</tt> method (not really demonstrated here).


<lang ruby> require 'fileutils'
<lang ruby>require 'fileutils'
moves = { "input.txt" => "output.txt", "/input.txt" => "/output.txt", "docs" => "mydocs","/docs" => "/mydocs"}
moves = { "input.txt" => "output.txt", "/input.txt" => "/output.txt", "docs" => "mydocs","/docs" => "/mydocs"}
moves.each{ |src, dest| FileUtils.move( src, dest, :verbose => true ) }</lang>
moves.each{ |src, dest| FileUtils.move( src, dest, :verbose => true ) }</lang>


=={{header|Slate}}==
=={{header|Slate}}==
<lang slate>(File newNamed: 'input.txt') renameTo: 'output.txt'.
<lang slate>
(File newNamed: 'input.txt') renameTo: 'output.txt'.
(File newNamed: '/input.txt') renameTo: '/output.txt'.
(File newNamed: '/input.txt') renameTo: '/output.txt'.
(Directory newNamed: 'docs') renameTo: 'mydocs'.
(Directory newNamed: 'docs') renameTo: 'mydocs'.
(Directory newNamed: '/docs') renameTo: '/mydocs'.
(Directory newNamed: '/docs') renameTo: '/mydocs'.</lang>
</lang>


=={{header|Smalltalk}}==
=={{header|Smalltalk}}==
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=={{header|Standard ML}}==
=={{header|Standard ML}}==
OS.FileSys.rename {old = "input.txt", new = "output.txt"};
<lang sml>OS.FileSys.rename {old = "input.txt", new = "output.txt"};
OS.FileSys.rename {old = "docs", new = "mydocs"};
OS.FileSys.rename {old = "docs", new = "mydocs"};
OS.FileSys.rename {old = "/input.txt", new = "/output.txt"};
OS.FileSys.rename {old = "/input.txt", new = "/output.txt"};
OS.FileSys.rename {old = "/docs", new = "/mydocs"};
OS.FileSys.rename {old = "/docs", new = "/mydocs"};</lang>


=={{header|Tcl}}==
=={{header|Tcl}}==
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=={{header|Toka}}==
=={{header|Toka}}==
needs shell
<lang toka>needs shell
" input.txt" " output.txt" rename
" input.txt" " output.txt" rename
" /input.txt" " /output.txt" rename
" /input.txt" " /output.txt" rename

" docs" " mydocs" rename
" docs" " mydocs" rename
" /docs" " /mydocs" rename
" /docs" " /mydocs" rename</lang>


=={{header|UNIX Shell}}==
=={{header|UNIX Shell}}==
mv input.txt output.txt
<lang bash>mv input.txt output.txt
mv /input.txt /output.txt
mv /input.txt /output.txt
mv docs mydocs
mv docs mydocs
mv /docs /mydocs
mv /docs /mydocs</lang>


=={{header|Vedit macro language}}==
=={{header|Vedit macro language}}==
Vedit allows using either '\' or '/' as directory separator character, it is automatically converted to the one used by the operating system.
Vedit allows using either '\' or '/' as directory separator character, it is automatically converted to the one used by the operating system.
<lang vedit>
<lang vedit>// In current directory
// In current directory
File_Rename("input.txt", "output.txt")
File_Rename("input.txt", "output.txt")
File_Rename("docs", "mydocs")
File_Rename("docs", "mydocs")
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// In the root directory
// In the root directory
File_Rename("/input.txt", "/output.txt")
File_Rename("/input.txt", "/output.txt")
File_Rename("/docs", "/mydocs")
File_Rename("/docs", "/mydocs")</lang>
</lang>


=={{header|Visual Basic .NET}}==
=={{header|Visual Basic .NET}}==
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{{works with|Visual Basic .NET|9.0+}}
{{works with|Visual Basic .NET|9.0+}}
<lang vbnet> 'Current Directory
<lang vbnet>'Current Directory
IO.Directory.Move("docs", "mydocs")
IO.Directory.Move("docs", "mydocs")
IO.File.Move("input.txt", "output.txt")
IO.File.Move("input.txt", "output.txt")

'Root
'Root
IO.Directory.Move("\docs", "\mydocs")
IO.Directory.Move("\docs", "\mydocs")
IO.File.Move("\input.txt", "\output.txt")
IO.File.Move("\input.txt", "\output.txt")

'Root, platform independent
'Root, platform independent
IO.Directory.Move(IO.Path.DirectorySeparatorChar & "docs", _
IO.Directory.Move(IO.Path.DirectorySeparatorChar & "docs", _
IO.Path.DirectorySeparatorChar & "mydocs")
IO.Path.DirectorySeparatorChar & "mydocs")
IO.File.Move(IO.Path.DirectorySeparatorChar & "input.txt", _
IO.File.Move(IO.Path.DirectorySeparatorChar & "input.txt", _
IO.Path.DirectorySeparatorChar & "output.txt")</lang>
IO.Path.DirectorySeparatorChar & "output.txt")</lang>


{{omit from|TI-83 BASIC}} {{omit from|TI-89 BASIC}} <!-- Does not have a filesystem, just namespaced variables. -->
{{omit from|TI-83 BASIC}} {{omit from|TI-89 BASIC}} <!-- Does not have a filesystem, just namespaced variables. -->

Revision as of 13:04, 20 November 2009

Task
Rename a file
You are encouraged to solve this task according to the task description, using any language you may know.

In this task, the job is to rename the file called "input.txt" into "output.txt" and a directory called "docs" into "mydocs". This should be done twice: once "here", i.e. in the current working directory and once in the filesystem root.

Ada

<lang ada>with Ada.Directories; use Ada.Directories;

  ...

Rename ("input.txt", "output.txt"); Rename ("docs", "mydocs"); Rename ("/input.txt", "/output.txt"); Rename ("/docs", "/mydocs");</lang> The behavior depends on the concrete operating system regarding:

  • file name encoding issues;
  • file path notation (directory separator, directory syntax etc);
  • file extension syntax;
  • file system root (provided there is any).

ALGOL 68

Works with: ALGOL 68 version Standard - no extensions to language used

Note: reidf does not appear to be included in ALGOL 68G. Also note that file names would be Operating System dependent. <lang algol68>main:(

 PROC rename = (STRING source name, dest name)INT:
 BEGIN
   FILE actual file;
   INT errno = open(actual file, source name, stand back channel);
   IF errno NE 0 THEN
     errno
   ELSE
     IF reidf possible(actual file) THEN
       reidf(actual file, dest name); # change the identification of the book #
       errno
     ELSE
       close(actual file);
       -1
     FI
   FI
 END;
 rename("input.txt", "output.txt");
 rename("/input.txt", "/output.txt");
 rename("docs", "mydocs");
 rename("/docs", "/mydocs")

)</lang>

AWK

Awk allows to call operating system commands with the system() function. However, the awk script won't get its output, only the return code. But this task is simple enough for the trivial implementation to work: <lang awk>$ awk 'BEGIN{system("mv input.txt output.txt"}' $ awk 'BEGIN{system("mv docs mydocs")}' $ awk 'BEGIN{system("mv /input.txt /output.txt")}' $ awk 'BEGIN{system("mv docs mydocs")}'</lang>


AutoHotkey

<lang AutoHotkey>FileMove, oldname, newname</lang>

C

<lang c>#include <stdio.h>

int main() {

 rename("input.txt", "output.txt");
 rename("docs", "mydocs");
 rename("/input.txt", "/output.txt");
 rename("/docs", "/mydocs");
 return 0;

}</lang>

C++

Translation of: C

<lang cpp>#include <cstdio>

int main() {

 std::rename("input.txt", "output.txt");
 std::rename("docs", "mydocs");
 std::rename("/input.txt", "/output.txt");
 std::rename("/docs", "/mydocs");

}</lang>

C#

<lang csharp>using System; using System.IO;

class Program {

   static void Main(string[] args) {
       File.Move("input.txt","output.txt");
       File.Move(@"\input.txt",@"\output.txt");
       Directory.Move("docs","mydocs");
       Directory.Move(@"\docs",@"\mydocs");
   }

}</lang>

Common Lisp

rename-file

<lang lisp>(rename-file "input.txt" "output.txt") (rename-file "docs" "mydocs") (rename-file "/input.txt" "/output.txt") (rename-file "/docs" "/mydocs")</lang>

D

<lang d>std.file.rename("input.txt","output.txt"); std.file.rename("/input.txt","/output.txt"); std.file.rename("docs","mydocs"); std.file.rename("/docs","/mydocs");</lang>

DOS Batch File

<lang dos>ren input.txt output.txt ren \input.txt output.txt ren docs mydocs ren \docs mydocs</lang>

E

<lang e>for where in [<file:.>, <file:///>] {

 where["input.txt"].renameTo(where["output.txt"], null)
 where["docs"].renameTo(where["mydocs"], null)

}</lang>

Forth

<lang forth> s" input.txt" s" output.txt" rename-file throw s" /input.txt" s" /output.txt" rename-file throw</lang>

Groovy

Using File <lang groovy>['input.txt':'output.txt', 'docs':'mydocs'].each { src, dst ->

 ['.', ].each { dir ->
   new File("$dir/$src").renameTo(new File("$dir/$dst"))
 }

}</lang>

Using Ant <lang groovy>['input.txt':'output.txt', 'docs':'mydocs'].each { src, dst ->

 ['.', ].each { dir ->
   new AntBuilder().move(file:"$dir/$src", toFile:"$dir/$dst")
 }

}</lang>

Haskell

<lang haskell>import System.IO import System.Directory

main = do

 renameFile "input.txt" "output.txt"
 renameDirectory "docs" "mydocs"
 renameFile "/input.txt" "/output.txt"
 renameDirectory "/docs" "/mydocs"</lang>

J

J does not ship with a built-in utility for renaming files. The following will work on Windows, Linux and Macs:

<lang j>frename=: 4 : 0

if. x -: y do. return. end.
if. IFUNIX do.
  hostcmd=. [: 2!:0 '('"_ , ] , ' || true)'"_
  hostcmd 'mv "',y,'" "',x,'"'
else.
  'kernel32 MoveFileA i *c *c' 15!:0 y;x
end.

)</lang>

Useage: <lang j>'output.txt' frename 'input.txt' '/output.txt' frename '/input.txt' 'mydocs' frename 'docs' '/mydocs' frename '/docs'</lang>

Java

<lang java>import java.util.File; public class FileRenameTest {

  public static boolean renameFile(String oldname, String newname) {
      // File (or directory) with old name
      File file = new File(oldname);
  
      // File (or directory) with new name
      File file2 = new File(newname);
  
      // Rename file (or directory)
      boolean success = file.renameTo(file2);
      return sucess;
  }
  public static void test(String type, String oldname, String newname) {
      System.out.println("The following " + type + " called " + oldname +
          ( renameFile(oldname, newname) ? " was renamed as " : " could not be renamed into ")
          + newname + "."
      );
  }
  public static void main(String args[]) {
       test("file", "input.txt", "output.txt");
       test("file", File.seperator + "input.txt", File.seperator + "output.txt");
       test("directory", "docs", "mydocs");
       test("directory", File.seperator + "docs" + File.seperator, File.seperator + "mydocs" + File.seperator);
  }

}</lang>

JavaScript

Works with: JScript

Throws an error if the destination file/folder exists. <lang javascript>var fso = new ActiveXObject("Scripting.FileSystemObject"); fso.MoveFile('input.txt', 'output.txt'); fso.MoveFile('c:/input.txt', 'c:/output.txt'); fso.MoveFolder('docs', 'mydocs'); fso.MoveFolder('c:/docs', 'c:/mydocs');</lang>

Mathematica

<lang Mathematica>SetDirectory[NotebookDirectory[]] RenameFile["input.txt", "output.txt"] RenameDirectory["docs", "mydocs"] SetDirectory[$RootDirectory] RenameFile["input.txt", "output.txt"] RenameDirectory["docs", "mydocs"]</lang>

MAXScript

MAXScript has no folder rename method <lang maxscript>-- Here renameFile "input.txt" "output.txt" -- Root renameFile "/input.txt" "/output.txt"</lang>

Objective-C

Works with: Cocoa
Works with: GNUstep

<lang objc>NSFileManager *fm = [NSFileManager defaultManager];

[fm movePath:@"input.txt" toPath:@"output.txt" handler:nil]; [fm movePath:@"docs" toPath:@"mydocs" handler:nil];</lang>

OCaml

<lang ocaml>Sys.rename "input.txt" "output.txt";; Sys.rename "docs" "mydocs";; Sys.rename "/input.txt" "/output.txt";; Sys.rename "/docs" "/mydocs";;</lang>

Pascal

<lang pascal> var

   f : file ; // Untyped file
begin

 // as current directory
 AssignFile(f,'input.doc');
 Rename(f,'output,doc');

 // as root directory
 AssignFile(f,'\input.doc');
 Rename(f,'\output,doc');

 // rename a directory 
 AssignFile(f,'docs');
 Rename(f,'mydocs');

 //rename a directory off the root

 AssignFile(f,'\docs');
 Rename(f,'\mydocs');

end;</lang>

Perl

<lang perl>use File::Copy qw(move); use File::Spec::Functions qw(catfile rootdir);

  1. here

move 'input.txt', 'output.txt'; move 'docs', 'mydocs';

  1. root dir

move (catfile rootdir, 'input.txt'), (catfile rootdir, 'output.txt'); move (catfile rootdir, 'docs'), (catfile rootdir, 'mydocs');</lang>

PHP

<lang php><?php rename('input.txt', 'output.txt'); rename('docs', 'mydocs'); rename('/input.txt', '/output.txt'); rename('/docs', '/mydocs'); ?></lang>

Pop11

<lang pop11>sys_file_move('inputs.txt', 'output.txt'); sys_file_move('docs', 'mydocs'); sys_file_move('/inputs.txt', '/output.txt'); sys_file_move(/'docs', '/mydocs');</lang>

Note that notion of the root of filesystem is Unix specific, so above we do not try to suport other systems.

PowerShell

<lang powershell>Rename-Item input.txt output.txt

  1. The Rename-item has the alias ren

ren input.txt output.txt</lang>

Python

<lang python>import os

os.rename("input.txt", "output.txt") os.rename("docs", "mydocs")

os.rename(os.sep + "input.txt", os.sep + "output.txt") os.rename(os.sep + "docs", os.sep + "mydocs")</lang>

R

<lang R>file.rename("input.txt", "output.txt") file.rename("/input.txt", "/output.txt") file.rename("docs", "mydocs") file.rename("/docs", "/mydocs")</lang>

Ruby

<lang ruby>File.rename('input.txt', 'output.txt') File.rename('/input.txt', '/output.txt') File.rename('docs', 'mydocs') File.rename('/docs', '/mydocs')</lang>

Library: fileutils.rb

The FileUtils#move method has some more flexibility than the core File#rename method (not really demonstrated here).

<lang ruby>require 'fileutils' moves = { "input.txt" => "output.txt", "/input.txt" => "/output.txt", "docs" => "mydocs","/docs" => "/mydocs"} moves.each{ |src, dest| FileUtils.move( src, dest, :verbose => true ) }</lang>

Slate

<lang slate>(File newNamed: 'input.txt') renameTo: 'output.txt'. (File newNamed: '/input.txt') renameTo: '/output.txt'. (Directory newNamed: 'docs') renameTo: 'mydocs'. (Directory newNamed: '/docs') renameTo: '/mydocs'.</lang>

Smalltalk

<lang smalltalk>File rename: 'input.txt' to: 'output.txt'. File rename: 'docs' to: 'mydocs'. "as for other example, this works on systems

where the root is / ..."

File rename: '/input.txt' to: '/output.txt'. File rename: '/docs' to: '/mydocs'</lang>

Standard ML

<lang sml>OS.FileSys.rename {old = "input.txt", new = "output.txt"}; OS.FileSys.rename {old = "docs", new = "mydocs"}; OS.FileSys.rename {old = "/input.txt", new = "/output.txt"}; OS.FileSys.rename {old = "/docs", new = "/mydocs"};</lang>

Tcl

Assuming that the Bash example shows what is actually meant with this task (one file and one directory here, one file and one directory in the root) and further assuming that this is supposed to be generic (i.e. OS agnostic): <lang tcl>file rename inputs.txt output.txt file rename docs mydocs

file rename [file nativename /inputs.txt] [file nativename /output.txt] file rename [file nativename /docs] [file nativename /mydocs]</lang> Without the need to work on unusual platforms like Mac OS 9, the code could be just: <lang tcl>file rename inputs.txt output.txt file rename docs mydocs

file rename /inputs.txt /output.txt file rename /docs /mydocs</lang>

Toka

<lang toka>needs shell " input.txt" " output.txt" rename " /input.txt" " /output.txt" rename

" docs" " mydocs" rename " /docs" " /mydocs" rename</lang>

UNIX Shell

<lang bash>mv input.txt output.txt mv /input.txt /output.txt mv docs mydocs mv /docs /mydocs</lang>

Vedit macro language

Vedit allows using either '\' or '/' as directory separator character, it is automatically converted to the one used by the operating system. <lang vedit>// In current directory File_Rename("input.txt", "output.txt") File_Rename("docs", "mydocs")

// In the root directory File_Rename("/input.txt", "/output.txt") File_Rename("/docs", "/mydocs")</lang>

Visual Basic .NET

Platform: .NET

Works with: Visual Basic .NET version 9.0+

<lang vbnet>'Current Directory IO.Directory.Move("docs", "mydocs") IO.File.Move("input.txt", "output.txt")

'Root IO.Directory.Move("\docs", "\mydocs") IO.File.Move("\input.txt", "\output.txt")

'Root, platform independent IO.Directory.Move(IO.Path.DirectorySeparatorChar & "docs", _

IO.Path.DirectorySeparatorChar & "mydocs")

IO.File.Move(IO.Path.DirectorySeparatorChar & "input.txt", _

 IO.Path.DirectorySeparatorChar & "output.txt")</lang>