Rare numbers: Difference between revisions

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(Added Lua)
 
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It could look something like the following (ignoring whatever optimizations the other examples are using), if it was fast enough. I did not have the time/processor to test finding the first 5. The .israre() function appears to return the right answer, tested with individual numbers.
 
<syntaxhighlight lang="langur">val .perfectsquare = ffn(.n) isInteger{ (.n ^/ 2) div 1 }
{{works with|langur|0.8.11}}
<syntaxhighlight lang="langur">val .perfectsquare = f isInteger .n ^/ 2
 
val .israre = ffn(.n) {
val .r = reverse(.n)
if .n == .r: return false
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}
 
val .findfirst = ffn(.max) {
for[=[]] .i = 0; len(_for) < .max; .i += 1 {
if .israre(.i) {
_for ~= [.i]
if len(_for) == .max: break
}
}
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# if you have the time...
writeln "the first 5 rare numbers: ", .findfirst(5)</syntaxhighlight>
 
With 0.8.11, the built-in reverse() function will flip the digits of a number. Without this, you could write your own function to do so as follows (if not passed any negative numbers).
 
<syntaxhighlight lang="langur">val .reverse = f toNumber join reverse split .n</syntaxhighlight>
 
=={{header|Lua}}==
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621770
281089082</pre>
 
=={{header|Racket}}==
===naive===
<syntaxhighlight lang="racket" line>; 20231024 Racket programming naive solution
#lang racket
(require control)
(require text-block/text)
 
(define (is-palindrome n)
(define (digit-list n)
(if (zero? n)
'()
(cons (remainder n 10) (digit-list (quotient n 10)))))
(define (reverse-list lst)
(if (null? lst)
'()
(append (reverse-list (cdr lst)) (list (car lst)))))
(define digits (digit-list n))
(equal? digits (reverse-list digits)))
 
(define (perfect-square? n)
(if (rational? (sqrt n))
(= n (expt (floor (sqrt n)) 2))
false))
 
(define (reverse-number n)
(string->number (string-reverse (number->string n))))
 
(define (find-rare-numbers count)
(define rare-numbers '())
(define i 1)
(define (is-rare? n)
(and (not (is-palindrome n))
(let* ((r (reverse-number n))
if len (_for)sum ==(+ .max:n breakr))
(diff (- n r)))
(and (perfect-square? sum)
(perfect-square? diff)))))
 
(define start-time (current-inexact-milliseconds))
(while (< (length rare-numbers) count)
(cond [(is-rare? i)
(displayln (format "Number: ~a | Elapsed time: ~a ms" i (round (- (current-inexact-milliseconds) start-time))))
(set! rare-numbers (cons i rare-numbers))])
(set! i (+ i 1)))
(reverse rare-numbers))
 
(displayln "The first 5 rare numbers are:")
(for-each (λ (x) (display x) (display "\n")) (find-rare-numbers 5))
</syntaxhighlight>
 
=={{header|Raku}}==
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===Traditional===
About 9.5 minutes to find the first 25 rare numbers.
<syntaxhighlight lang="ecmascriptwren">import "./sort" for Sort
import "./fmt" for Fmt
 
class Term {
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===Turbo===
Ruffles the feathers a little with a time 5 times quicker than the 'traditional' version.
<syntaxhighlight lang="ecmascriptwren">import "./sort" for Sort
import "./fmt" for Fmt
import "./date" for Date
 
class Z2 {
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