Perfect numbers: Difference between revisions

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@@ Line 2,313: / Line 2,313: @@
 =={{header|Python}}==
+===Procedural===
 <lang python>def perf(n):
     sum = 0
@@ Line 2,319: / Line 2,320: @@
             sum += i
     return sum == n</lang>
-Functional style:
+===Functional===
-<lang python>perf = lambda n: n == sum(i for i in xrange(1, n) if n % i == 0)</lang>
+<lang python>def perf(n):
+    return n == sum(i for i in range(1, n) if n % i == 0)
+print (
+    list(filter(perf, range(1, 10001)))
+)</lang>
-Or, a little faster (by restricting the search space):
+Or, an order of magnitude faster (by restricting the search space):
 <lang python>from itertools import (chain)