Perfect numbers: Difference between revisions

</pre>

=={{header|zkl}}==

{{trans|D}}

<lang zkl>fcn isPerfectNumber1(n)

{ n == [1..n-1].filter('wrap(i){ n % i == 0 }).sum(); }</lang>

{{out}}

<pre>

[1..0d10_000].filter(isPerfectNumber1).println();

L(6,28,496,8128)