Anonymous user
Perfect numbers: Difference between revisions
→E: new example
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Line 202:
}
</lang>
=={{header|E}}==
<lang e>pragma.enable("accumulator")
def isPerfectNumber(x :int) {
var sum := 0
for d ? (x % d <=> 0) in 1..!x {
sum += d
if (sum > x) { return false }
}
return sum <=> x
}</lang>
=={{header|Forth}}==
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