Perfect numbers: Difference between revisions

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(updated FunL)
(updated FunL)
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=={{header|FunL}}==
=={{header|FunL}}==
<lang funl>~~def perfect( n ) = sum( d | d <- 1..n if d|n ) == 2n
<lang funl>def perfect( n ) = sum( d | d <- 1..n if d|n ) == 2n


println( (1..500).filter(perfect) )~~</lang>
println( (1..500).filter(perfect) )</lang>


{{out}}
{{out}}