Perfect numbers: Difference between revisions

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 =={{header|FunL}}==
+<lang funl>~~def perfect( n ) = sum( d | d <- 1..n if d|n ) == 2n
-<lang funl>import integers.factors
+println( (1..500).filter(perfect) )~~</lang>
-def perfect( n ) = sum( factors(n) ) == 2n
-for i <- 1..500
-  if perfect( i )
-    println( i )</lang>
 {{out}}