Perfect numbers: Difference between revisions

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@@ Line 490: / Line 490: @@
 <lang d>import std.stdio, std.algorithm, std.range;
-bool isPerfect(in int n) /*pure nothrow*/ {
+bool isPerfect(in uint n) pure nothrow
+in {
-    return n == iota(1, n - 1).reduce!((s, i) => n % i ? s : s + i);
+    assert(n > 0);
+} body {
+    return n == reduce!((s, i) => n % i ? s : s + i)(0, iota(1, n-1));
 }
 void main() {
-    iota(3, 10_000).filter!isPerfect.writeln;
+    iota(1, 10_000).filter!isPerfect.writeln;
 }</lang>