Perfect numbers: Difference between revisions

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Inline

@@ Line 118: / Line 118: @@
 <python>def perf(n):
     sum = 0
-    for i in xrange(1,n):
+    for i in xrange(1, n):
         if n % i == 0:
             sum += i
     return sum == n</python>
+Functional style:
-Using functional form
+<python>perf = lambda n: n == sum(i for i in xrange(1, n) if n % i == 0)</python>
-<python>def perf(n):
-   return n == sum( i for i in xrange(1,n) if n % i == 0)</python>