Perfect numbers: Difference between revisions
Content added Content deleted
(Remove unnecessary iteration and logically redundant test (if [sum == 2 * num] then [sum - num == num] for all positive num anyway).) |
(Remove unnecessary iteration and logically redundant test (if [sum == 2 * num] then [sum - num == num] for all positive num anyway).) |
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Line 202:
bool is_perfect( int number ) {
int sum = 0 ;
for ( int i = 1 ; i < number
if ( number % i == 0 )
sum += i ;
return
}</lang>
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