Perfect numbers: Difference between revisions
Content added Content deleted
(Add lambda version) |
(Remove unnecessary iteration and logically redundant test (if [sum == 2 * num] then [sum - num == num] for all positive num anyway).) |
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Line 154:
{
int sum = 0;
for (int i = 1; i < num
{
if (num % i == 0)
Line 160:
}
return
}
</lang>
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