Minimum multiple of m where digital sum equals m: Difference between revisions
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m (Corrected spelling mistake.) |
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int k = 0; |
int k = 0; |
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while ( digitSum(k += n) != n ); |
while ( digitSum(k += n) != n ); |
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System.out.print(String.format("%8d%s",k / n, ( n % 10) == 0 ? "\n" : " ")); |
System.out.print(String.format("%8d%s", k / n, ( n % 10 ) == 0 ? "\n" : " ")); |
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} |
} |
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} |
} |
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