Longest common subsequence: Difference between revisions
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Define a strict Cartesian product-order (<) over these ordered pairs, such that (i1, j1) < (i2, j2) iff i1 < j1 and i2 < j2.
Given such a product-order over a set of matches '''M''', a chain '''C''' is any subset of '''M''' where either p1 < p2 or p2 < p1, for distinct pairs p1 and p2 in '''C'''.
Finding an '''LCS''' can then be
This set of matches can be represented as an m*n bit matrix, where each bit '''M[i, j]''' is True iff there is a match at the corresponding positions of strings x and y.
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