Longest common subsequence: Difference between revisions

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(Undo revision 65653 by Briantrice (Talk) — Don't add empty {{header sections; they incorrectly categorize the task as completed)
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result.reverse
end</lang>
 
=={{header|Slate}}==
We define this on the <tt>Sequence</tt> type since there is nothing string-specific about the concept.
 
===Recursion===
=={{trans|Java}}==
<lang slate>
s1@(Sequence traits) longestCommonSubsequenceWith: s2@(Sequence traits)
[
s1 isEmpty \/ s2 isEmpty ifTrue: [^ {}].
s1 last = s2 last
ifTrue: [(s1 allButLast longestCommonSubsequenceWith: s2 allButLast) copyWith: s1 last]
ifFalse: [| x y |
x: (s1 longestCommonSubsequenceWith: s2 allButLast).
y: (s1 allButLast longestCommonSubsequenceWith: s2).
x length > y length ifTrue: [x] ifFalse: [y]]
].
</lang>
 
===Dynamic Programming===
=={{trans|Ruby}}==
<lang slate>
s1@(Sequence traits) longestCommonSubsequenceWith: s2@(Sequence traits)
[| lengths |
lengths: (ArrayMD newWithDimensions: {s1 length `cache. s2 length `cache} defaultElement: 0).
s1 doWithIndex: [| :elem1 :index1 |
s2 doWithIndex: [| :elem2 :index2 |
elem1 = elem2
ifTrue: [lengths at: {index1 + 1. index2 + 1} put: (lengths at: {index1. index2}) + 1]
ifFalse: [lengths at: {index1 + 1. index2 + 1} put:
((lengths at: {index1 + 1. index2}) max: (lengths at: {index1. index2 + 1}))]]].
([| :result index1 index2 |
index1: s1 length.
index2: s2 length.
[index1 isPositive /\ index2 isPositive]
whileTrue:
[(lengths at: {index1. index2}) = (lengths at: {index1 - 1. index2})
ifTrue: [index1: index1 - 1]
ifFalse: [(lengths at: {index1. index2}) = (lengths at: {index1. index2 - 1})]
ifTrue: [index2: index2 - 1]
ifFalse: ["assert: (s1 at: index1 - 1) = (s2 at: index2 - 1)."
result nextPut: (s1 at: index1 - 1).
index1: index1 - 1.
index2: index2 - 1]]
] writingAs: s1) reverse
].
</lang>
 
=={{header|Tcl}}==