Largest proper divisor of n: Difference between revisions

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=={{header|Julia}}==
<lang julia>largestpd(n) = (for i in n-1:-1:1 n % i == 0 && return i; end; 1)

foreach(n -> print(rpad(largestpd(n), 3), n % 10 == 0 ? "\n" : ""), 1:100)
</lang>{{out}}
<pre>
1 1 1 2 1 3 1 4 3 5
1 6 1 7 5 8 1 9 1 10
7 11 1 12 5 13 9 14 1 15
1 16 11 17 7 18 1 19 13 20
1 21 1 22 15 23 1 24 7 25
17 26 1 27 11 28 19 29 1 30
1 31 21 32 13 33 1 34 23 35
1 36 1 37 25 38 11 39 1 40
27 41 1 42 17 43 29 44 1 45
13 46 31 47 19 48 1 49 33 50
</pre>


=={{header|MAD}}==
=={{header|MAD}}==
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27 41 1 42 17 43 29 44 1 45
13 46 31 47 19 48 1 49 33 50</pre>
13 46 31 47 19 48 1 49 33 50</pre>

=={{header|Pascal}}==
=={{header|Pascal}}==
<lang pascal>
<lang pascal>