Largest product in a grid: Difference between revisions

add FreeBASIC
(Added AutoHotkey)
(add FreeBASIC)
Line 186:
51267216
</pre>
 
=={{header|FreeBASIC}}==
<lang freebasic>data 08,02,22,97,38,15,00,40,00,75,04,05,07,78,52,12,50,77,91,08
data 49,49,99,40,17,81,18,57,60,87,17,40,98,43,69,48,04,56,62,00
data 81,49,31,73,55,79,14,29,93,71,40,67,53,88,30,03,49,13,36,65
data 52,70,95,23,04,60,11,42,69,24,68,56,01,32,56,71,37,02,36,91
data 22,31,16,71,51,67,63,89,41,92,36,54,22,40,40,28,66,33,13,80
data 24,47,32,60,99,03,45,02,44,75,33,53,78,36,84,20,35,17,12,50
data 32,98,81,28,64,23,67,10,26,38,40,67,59,54,70,66,18,38,64,70
data 67,26,20,68,02,62,12,20,95,63,94,39,63,08,40,91,66,49,94,21
data 24,55,58,05,66,73,99,26,97,17,78,78,96,83,14,88,34,89,63,72
data 21,36,23,09,75,00,76,44,20,45,35,14,00,61,33,97,34,31,33,95
data 78,17,53,28,22,75,31,67,15,94,03,80,04,62,16,14,09,53,56,92
data 16,39,05,42,96,35,31,47,55,58,88,24,00,17,54,24,36,29,85,57
data 86,56,00,48,35,71,89,07,05,44,44,37,44,60,21,58,51,54,17,58
data 19,80,81,68,05,94,47,69,28,73,92,13,86,52,17,77,04,89,55,40
data 04,52,08,83,97,35,99,16,07,97,57,32,16,26,26,79,33,27,98,66
data 88,36,68,87,57,62,20,72,03,46,33,67,46,55,12,32,63,93,53,69
data 04,42,16,73,38,25,39,11,24,94,72,18,08,46,29,32,40,62,76,36
data 20,69,36,41,72,30,23,88,34,62,99,69,82,67,59,85,74,04,36,16
data 20,73,35,29,78,31,90,01,74,31,49,71,48,86,81,16,23,57,05,54
data 01,70,54,71,83,51,54,69,16,92,33,48,61,43,52,01,89,19,67,48
 
dim as integer grid(1 to 20, 1 to 20), row, col, prod
dim as integer champ = 0, cr, cc
dim as boolean across = false
for row = 1 to 20
for col = 1 to 20
read grid(row, col)
next col
next row
 
'search down
for row = 1 to 17
for col = 1 to 20
prod = grid(row, col)*grid(row + 1, col)*grid(row + 2, col)*grid(row + 3, col)
if prod > champ then
cr = row
cc = col
champ = prod
end if
next col
next row
 
'search across
for row = 1 to 20
for col = 1 to 17
prod = grid(row, col)*grid(row, col + 1)*grid(row, col + 2)*grid(row, col + 3)
if prod > champ then
cr = row
cc = col
champ = prod
across = true
end if
next col
next row
 
print "The largest product was ";champ;" at row ";cr;" and column ";cc;", reading ";
if across then print "across." else print "down."</lang>
{{out}}<pre>The largest product was 51267216 at row 7 and column 16, reading down.</pre>
 
 
=={{header|Go}}==
781

edits