# Talk:Fibonacci sequence

## recursion too slow?

Solutions can be iterative or recursive (though recursive solutions are generally considered too slow and are mostly used as an exercise in recursion).

while the parenthetical comment is true, I'm wondering what to make of it. Is there any application of FIbonacci numbers where "computation time" is actually an issue? Do we care about computation time at all? If we do, I'd use neither an iterative nor a recursive approach but an analytic solution through phi (I added that to IDL, I see from a glance that at least the D solution has one of these as well).

Just for this RC task, speed shouldn't be an issue, I would think. As an aside, it would irk me to no end if I included an example that's slower than molassas in January. But many programmers who reuse (their) code and/or "borrow" code from others, and if there is a need to generate large amounts of Fibonacci numbers (or often), or test to see if some number is a Fibonacci number, then having a very fast version would be beneficial for those processes. I have one for my isFib function, for instance. -- Gerard Schildberger 22:51, 29 May 2012 (UTC)

I guess my question is: if we care about speed, why demand that the solution be iterative or recursive? Or, more generally, if performance is a concern, why demand any particular approach at all -- since the "best" approach for any one task is bound to be different for different languages. (Something with decent tail recursion might have recursive solutions faster than iterative ones and what-have-you).

And yet other way 'round: does performance matter here on RC? Almost all code samples I've ever contributed would have to be changed if I cared about speed of execution -- I've been trying to optimize for clarity of exposition instead. Is there some kind of guideline / a practical consensus / an ongoing discussion about this somewhere?Sgeier 14:16, 7 April 2008 (MDT)

I strongly doubt that the analytic version is actually faster than fast solutions using integer arithmetic (manipulating expression trees should be more expensive than manipulating integers). However, a fast solution wouldn't use the recursion formula directly, but use the fact that
/1 1\ n    /F<sub>n+1</sub> F<sub>n</sub>  \
(     )  = (                                 )
\1 0/      \F<sub>n</sub>   F<sub>n-1</sub>/
together with a fast exponentiation algorithm to calculate Fn in O(log n) time (in comparison, the naive iterative solution has O(n) time).
According to the general question if clarity or performance should be more important: I'd say clarity always wins over "programming tricks" performance (e.g. in C and C++ always use n/2 instead of n>>1 if your goal is to calculate the half of an integer), however algorithmic performance should be considered, if it doesn't conflict with the goals of the task (e.g. if the goal of a task is to explicitly show how to write a recursive function, replacing it with a faster iterative version obviously isn't a good idea). However, clarity is important, so the algorithmic performance should be weighted against it (also, the complexity of an algorithm shouldn't get too high IMHO; if you want to present complicated algorithms, there are other sites like literateprograms for that). Of course ultimately it's always the task which sets the rules. --Ce 15:21, 7 April 2008 (MDT)

## negative n errors

The task description contains: "Support for negative n errors is optional." Negative n isn't an error; while conventionally only the definition for positive n is given, the Fibonaccy sequence is actually defined for arbitrary n. You can rewrite the recursion formula Fn+1=Fn+Fn-1 as Fn-1=Fn+1-Fn and thus extend the recursive definition to negative values. This results in

${\displaystyle F0=0}$
${\displaystyle F-n=(-1)n+1Fn}$

If the word "errors" is removed from the description, it becomes reasonable. --Ce 14:40, 7 April 2008 (MDT)

I've now fixed that. --Ce 08:35, 14 October 2008 (UTC)

## Clarified?

In the task page there is the note "This task has been clarified. Its programming examples are in need of review...". I am not sure what exactly has been clarified, but at least the value of fibonacci(0) seems to be wrong in many language examples.

Should the language examples that have been fixed be marked somehow so that we will know when all the examples have been corrected? (Or perhaps mark all examples and then remove the mark when it has been checked.) --PauliKL 15:14, 14 April 2009 (UTC)

I just tried to fix what I could figure out based on that definition. Some of the iterative examples may still be partially wrong, but I think I got a lot of the recursive examples. --Mwn3d 18:17, 14 April 2009 (UTC)

## Rules abuse!

Take a look at the third example under BASIC, Iterative. I stretched the meaning of generate and just predetermined all the numbers that can be handled by my chosen data type (LONG; 32-bit signed, without support for Fn where n < 0) and dumped them into an array. Bam! Almost instant results! :-) -- Eriksiers 20:48, 7 August 2009 (UTC)

I don't think this (or other types of memoized solutions) violates the rules. It's a neat idea if your language uses a finite integer type. --Mwn3d 20:50, 7 August 2009 (UTC)
I was thinking more along the lines of the IOCCC award, "Worst Abuse of the Rules" -- the one given to the guy who turned in the empty source file and called it the world's smallest quine.
Anyway... what I posted can be applied to pretty much any data type, given time, space, and interest... although I wouldn't want to use it for, say, the limits of an 80-bit float. -- Eriksiers 20:56, 7 August 2009 (UTC)
Recursive? No! Iterative? No! It is best described as table lookup. (But I admire your cheek :-)   --Paddy3118 02:30, 8 August 2009 (UTC)
Table lookup! I knew there was a better place to put this than "iterative". Gonna change it. :-) -- Eriksiers 19:59, 9 August 2009 (UTC)

## Alternative

Fibonacci sequence can also be calculated using this formula.

${\displaystyle Fib[n]={\frac {(1+{\sqrt {5}})^{n}-(1-{\sqrt {5}})^{n}}{2^{n}{\sqrt {5}}}}}$

Size of the floating-point type (float, double, long double etc..) will limit how high n can be calulated.

--Spekkio 11:27, 25 November 2011 (UTC)

Thanks. Prompted by the above, I read this.

## Optional credits

I would've like to see an optional credit solution for allowing the specification of the starting (two) numbers.
This would've allowed the examples to also generate the Lucas numbers.

Fibonacci sequences
series name initial starting numbers
Fibonacci 0, 1
Lucas 2, 1

Another possibility would allow the specifiction of how many (previous) values to be summed.

Fibonacci sequences [sum of N numbers]
series name number of values to add OEIS entries
Lucas 2 A000032, A000204
Fibonacci 2 A000045
tribonacci 3 A000073, A000213
tetranacci 4 A000078, A000288
pentanacci 5 A001591, A000322
hexanacci 6 A001592, A000383
heptanacci 7 A122189, A060455
octanacci 8 A079262, A123536
nonanacci 9 A127193
decanacci 10 A127194
undecanacci 11 A127624
dodecanacci 12 A207539
13th-order 13 A163551

There may be more named Fibonacci numbers in this series of series. -- Gerard Schildberger 20:15, 24 May 2012 (UTC)

Note that there seems to be two definitions of the above series, the main difference is in how the initial numbers are specified. -- Gerard Schildberger 18:15, 25 May 2012 (UTC)

There seems to be enough in your proposal for a new task maybe called "Fibonacci-like sequences generator" in which the starting numbers/numbers of past numbers to sum to form the next, could be set.
It would also be good to maybe confirm some of the Lucas/Fibonacci identities mentioned in the Lucas wp article. --Paddy3118 20:33, 24 May 2012 (UTC)

## Fibonacci n-Step Numbers

The name is from MathWorld. I doodled the following: <lang python>>>> def fiblike(start): addnum = len(start) def fibber(n): try: return fibber.memo[n] except: ans = sum(fibber(i) for i in range(n-addnum, n)) fibber.memo.append(ans) return ans fibber.memo = start[:] return fibber

>>> f = fiblike([1,1]) >>> [f(i) for i in range(10)] [1, 1, 2, 3, 5, 8, 13, 21, 34, 55] >>> l = fiblike([2,1]) >>> [l(i) for i in range(10)] [2, 1, 3, 4, 7, 11, 18, 29, 47, 76] >>> f3= fiblike([1,1,2]) >>> [f3(i) for i in range(10)] [1, 1, 2, 4, 7, 13, 24, 44, 81, 149] >>> f4 = fiblike([1,1,2,4]) >>> [f4(i) for i in range(10)] [1, 1, 2, 4, 8, 15, 29, 56, 108, 208] >>> f5 = fiblike([1,1,2,4,8]) >>> [f5(i) for i in range(10)] [1, 1, 2, 4, 8, 16, 31, 61, 120, 236] >>> f6 = fiblike([1,1,2,4,8,16]) >>> [f6(i) for i in range(10)] [1, 1, 2, 4, 8, 16, 32, 63, 125, 248] >>> f7 = fiblike([1,1,2,4,8,16,32]) >>> [f7(i) for i in range(10)] [1, 1, 2, 4, 8, 16, 32, 64, 127, 253] >>> </lang>

I will try and write a task, although I have flu so it could be interesting! --Paddy3118 21:12, 24 May 2012 (UTC)

Gerard, I hope you like Fibonacci n-step number sequences and thanks for the inspiration! --Paddy3118 21:59, 24 May 2012 (UTC)
Hell's-Bells, ahhh likes all kinds!!   I have a handy-dandy, slicer-dicer, one-size-fits-all Swiss Army knife calculator (written in REXX), and among many other things, it has around a thousand different sequences, not the least of which are the Fibonacci-type sequences and other ilk.   And don't even get me started on the numerous prime/prime-ish sequences.   It's got more of 'em then ya can shake a stick at.   -- Gerard Schildberger 22:11, 24 May 2012 (UTC)
As an aside, to quote someone long ago:   the one language all programmers know is profanity.   -- Gerard Schildberger 22:11, 24 May 2012 (UTC)

Slightly off-topic, by what the hey!! What is the proper syntax for adding a trade-mark symbol after (say) Wolfram MathWorld? Is it:

• MathWorld ™
--or--
• MathWorld™

Does anyone think it would be a good idea to do a global change for the spelling of Mathworld --> MathWorld, and another change to add the trademark symbol (presumably by a superuser) ? -- Gerard Schildberger 20:32, 25 May 2012 (UTC)

Have they asked us to do that? The rules for trademarks are imposed by the trademark owner. Note also that they allow the use of their trademark in domain names (without capitalization and without any special trademark symbols). --Rdm 20:38, 25 May 2012 (UTC)
No, nobody asked. I understand domain names would be hard to add a trade-mark symbol, but RC uses/references/quotes that trademarked site a lot, and I thought it would be a show of "good faith" on RC's part to honor that site with at least a TM symbol. -- Gerard Schildberger 20:42, 25 May 2012 (UTC)

## ECMAScript 2015 (ES6) recursive implementations exploration

I wrote this little exploration of various recursive takes on Fib generation a while ago: http://pastebin.com/ExTuYkAE Among other things it takes time consumption and multiple uses into account. Might look a bit foreign to many as it uses the new ES6 fat arrow syntax for pretty much everything. If someone wants to incorporate it into the JavaScript section, be my guest!

## Ocaml matrix example remark

I notice someone edited the Ocaml matrix example to say 'actually O(n*n)'. I can't identify who that was now, but unless someone can explain/justify it I will remove it, as it seems to be incorrect. TobyK (talk)

## Two formulae in SuperCollider Recursive contribution invisible to most browsers

The two formulae in the preface to the Recursive section of the SuperCollider examples are invisible to most browsers. Perhaps they were edited and tested in FireFox ? The majority of browsers, including Chrome, IE/Edge, Safari etc, use the part of the HTML code which displays the server-side graphic file for each formula. Only a minority, which happens to include FireFox, locally process the MathML expression, and only then if requisite fonts are installed. As the MediaWiki processor generates separate code to support each approach, visibility of formulae in Firefox doesn't guarantee successful code compilation and visibility to the majority of browsers.

Redundant space inside [itex] tags can be one source of this problem. Perhaps the author can experiment and check the result in in Chrome, IE/Edge or Safari ? Hout (talk) 11:38, 15 October 2016 (UTC)

OK; I'll take a look into it Telephon. I can reproduce it, yes. I had just tried and it worked on Firefox. Is there an alternative that would work on other browsers?--Telephon (talk) 14:12, 15 October 2016 (UTC)