Isqrt (integer square root) of X: Difference between revisions
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nip swap ] is sqrt
( sqrt+ returns the integer square root and remainder )
( i.e. isqrt+ of 28 is 5 remainder 3 as (5^2)+3 = 28 )
( To make it task compliant change the last line to )
( "nip nip ] is sqrt
66 times [ i^ sqrt+ drop echo sp ] cr cr
73 times
[ 7 i^ 1+ ** sqrt+ drop
number$ +commas 41 justify
echo$ cr
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