Horner's rule for polynomial evaluation: Difference between revisions

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(I meant the coeff of x^2 to be ''minus'' 4, not 4. Also made Python func version work with version 3.0)
(Added Fortran)
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<br>C.f: [[Formal power series]]
<br>C.f: [[Formal power series]]
=={{header|Fortran}}==
{{works with|Fortran|90 and later}}
<lang fortran>program test_horner

implicit none

write (*, '(f5.1)') horner ((/-19.0, 7.0, -4.0, 6.0/), 3.0)

contains

function horner (coeffs, x) result (res)

implicit none
real, dimension (:), intent (in) :: coeffs
real, intent (in) :: x
real :: res
integer :: i

res = 0.0
do i = size (coeffs), 1, -1
res = res * x + coeffs (i)
end do

end function horner

end program test_horner</lang>
Output:
<lang>128.0</lang>
=={{header|Java}}==
=={{header|Java}}==
{{works with|Java|1.5+}}
{{works with|Java|1.5+}}

Revision as of 07:27, 31 March 2010

Horner's rule for polynomial evaluation is a draft programming task. It is not yet considered ready to be promoted as a complete task, for reasons that should be found in its talk page.

A fast scheme for evaluating a polynomial such as:

when
.
Is to arrange the computation as follows:

And compute the result from the innermost brackets outwards as:

coefficients = [-19, 7, -4, 6] # list coefficients of all x^0..x^n in order
x = 3
reversedcoeffs = reverse(coefficients)
accumulator = reversedcoeffs[0]
for (i=1; i<length(reversedcoffs); i++){
  accumulator = ( accumulator * x ) + reversedcoeffs[i]
}
# accumulator now has the answer

Task Description

Create a routine that takes a list of coefficients of a polynomial in order of increasing powers of x; together with a value of x to compute its value at, and return the value of the polynomial at that value using Horner's rule.


C.f: Formal power series

Fortran

Works with: Fortran version 90 and later

<lang fortran>program test_horner

 implicit none
 write (*, '(f5.1)') horner ((/-19.0, 7.0, -4.0, 6.0/), 3.0)

contains

 function horner (coeffs, x) result (res)
   implicit none
   real, dimension (:), intent (in) :: coeffs
   real, intent (in) :: x
   real :: res
   integer :: i
   res = 0.0
   do i = size (coeffs), 1, -1
     res = res * x + coeffs (i)
   end do
 end function horner

end program test_horner</lang> Output: <lang>128.0</lang>

Java

Works with: Java version 1.5+

<lang java5>import java.util.ArrayList; import java.util.Collections; import java.util.List;

public class Horner {

   public static void main(String[] args){
       List<Double> coeffs = new ArrayList<Double>();
       coeffs.add(-19.0);
       coeffs.add(7.0);
       coeffs.add(-4.0);
       coeffs.add(6.0);
       System.out.println(polyEval(coeffs, 3));
   }
   public static double polyEval(List<Double> coefficients, double x) {
       Collections.reverse(coefficients);
       Double accumulator = coefficients.get(0);
       for (int i = 1; i < coefficients.size(); i++) {
           accumulator = (accumulator * x) + (Double) coefficients.get(i);
       }
       return accumulator;
   }

}</lang> Output:

128.0

Python

<lang python>>>> def horner(coeffs, x): acc = coeffs[-1] for c in reversed(coeffs[:-1]): acc = acc * x + c return acc

>>> horner( (-19, 7, -4, 6), 3) 128</lang>

Functional version

<lang python>>>> try: from functools import reduce except: pass

>>> def horner(coeffs, x): return reduce(lambda acc, c: acc * x + c, reversed(coeffs))

>>> horner( (-19, 7, -4, 6), 3) 128</lang>