Hash from two arrays: Difference between revisions

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(Added XPL0 example.)
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=={{header|langur}}==
=== the easy way ===
<syntaxhighlight lang="langur">writeln toHashhash w/a b c d/, [1, 2, 3, 4]</syntaxhighlight>
 
Note that w/a b c d/ is a semantic convenience equivalent to ["a", "b", "c", "d"].
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