Hash from two arrays: Difference between revisions

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 Using the "zipwith" meta-operator on the <tt>=></tt> pair composer:
-{{works with|rakudo|2015-09-13}}
+{{works with|rakudo|2018.03}}
 <lang perl6>my @keys = <a b c d e>;
 my @values = ^5;
-my %hash = @keys Z=> @values;</lang>
+my %hash = @keys Z=> @values;
-Alternatively, by assigning to a hash slice:
+#Alternatively, by assigning to a hash slice:
-<lang perl6>my %hash;
-%hash{@keys} = @values;</lang>
+%hash{@keys} = @values;
-Or to create an anonymous hash:
+# Or to create an anonymous hash:
-<lang perl6>%( @keys Z=> @values )</lang>
+%( @keys Z=> @values );
-All of these zip forms trim the result to the length of the shorter of their two input lists. If you wish to enforce equal lengths, you can use a strict hyperoperator instead:
-<lang perl6>{ @keys »=>« @values }  # Will fail if the lists differ in length</lang>
+# All of these zip forms trim the result to the length of the shorter of their two input lists.
+# If you wish to enforce equal lengths, you can use a strict hyperoperator instead:
+quietly # suppress warnings about unused hash
+{ @keys »=>« @values };  # Will fail if the lists differ in length</lang>
 =={{header|Phix}}==