Four is the number of letters in the ...: Difference between revisions

Content added Content deleted
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Base.eltype(iter::CountLetters) = Int
Base.eltype(iter::CountLetters) = Int

function firstN(n = 201)
countlet = CountLetters()
print("It is interesting how identical lengths align with 20 columns.\n 1: 4")
iter_result = iterate(countlet)
itercount = 2
while iter_result != nothing
(wlen, state) = iter_result
print(lpad(string(wlen), 4))
if itercount % 20 == 0
print("\n$(itercount+1):")
elseif itercount == n
break
end
iter_result = iterate(countlet, state)
itercount += 1
end
println()
end


function sumwords(iterations)
function sumwords(iterations)
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"last word \"$lastword\" with $(length(lastword)) letters.")
"last word \"$lastword\" with $(length(lastword)) letters.")
end</lang> {{output}} <pre>
end</lang> {{output}} <pre>
It is interesting how identical lengths align with 20 columns.
1: 4 2 3 6 2 7 2 3 5 4 2 4 8 3 2 3 6 5 2 3
21: 5 3 2 3 6 3 2 3 5 5 2 3 5 3 2 3 7 5 2 3
41: 6 4 2 3 5 4 2 3 5 3 2 3 8 4 2 3 7 5 2 3
61: 10 5 2 3 10 3 2 3 9 5 2 3 9 3 2 3 11 4 2 3
81: 10 3 2 3 10 5 2 3 9 4 2 3 11 5 2 3 12 3 2 3
101: 11 5 2 3 12 3 2 3 11 5 2 3 11 3 2 3 13 5 2 3
121: 12 4 2 3 11 4 2 3 9 3 2 3 11 5 2 3 12 4 2 3
141: 11 5 2 3 12 3 2 3 11 5 2 3 11 5 2 3 13 4 2 3
161: 12 3 2 3 11 5 2 3 8 3 2 3 10 4 2 3 11 3 2 3
181: 10 5 2 3 11 4 2 3 10 4 2 3 10 3 2 3 12 5 2 3
201: 11
2202 words -> 2202 iterations, 14035 letters total, last word "ninety-ninth" with 12 letters.
2202 words -> 2202 iterations, 14035 letters total, last word "ninety-ninth" with 12 letters.
1000 words -> 1000 iterations, 6290 letters total, last word "in" with 2 letters.
1000 words -> 1000 iterations, 6290 letters total, last word "in" with 2 letters.
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