Find square difference: Difference between revisions
Put PL/M into the correct right place
(Move PL/M into the right place.) |
(Put PL/M into the correct right place) |
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Line 224:
n > 500.5
n = 501
</pre>▼
=={{header|Python}}==▼
<lang python>▼
import math▼
print("working...")▼
limit1 = 6000▼
limit2 = 1000▼
oldSquare = 0▼
newSquare = 0▼
for n in range(limit1):▼
newSquare = n*n▼
if (newSquare - oldSquare > limit2):▼
print("Least number is = ", end = "");▼
print(int(math.sqrt(newSquare)))▼
break▼
oldSquare = n*n▼
print("done...")▼
print()▼
</lang>▼
{{out}}▼
<pre>▼
working...▼
Least number is = 501▼
done...▼
</pre>
Line 297 ⟶ 270:
THE LOWEST N WHERE THE SQUARES OF N AND N-1 DIFFER BY MORE THAN 32000 IS: 16001
THE LOWEST N WHERE THE SQUARES OF N AND N-1 DIFFER BY MORE THAN 65000 IS: 32501
▲</pre>
▲=={{header|Python}}==
▲<lang python>
▲import math
▲print("working...")
▲limit1 = 6000
▲limit2 = 1000
▲oldSquare = 0
▲newSquare = 0
▲for n in range(limit1):
▲ newSquare = n*n
▲ if (newSquare - oldSquare > limit2):
▲ print("Least number is = ", end = "");
▲ print(int(math.sqrt(newSquare)))
▲ break
▲ oldSquare = n*n
▲print("done...")
▲print()
▲</lang>
▲{{out}}
▲<pre>
▲working...
▲Least number is = 501
▲done...
</pre>
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