Find square difference: Difference between revisions

Content added Content deleted
(Move PL/M into the right place.)
(Put PL/M into the correct right place)
Line 224: Line 224:
n > 500.5
n > 500.5
n = 501
n = 501
</pre>

=={{header|Python}}==
<lang python>
import math
print("working...")
limit1 = 6000
limit2 = 1000
oldSquare = 0
newSquare = 0

for n in range(limit1):
newSquare = n*n
if (newSquare - oldSquare > limit2):
print("Least number is = ", end = "");
print(int(math.sqrt(newSquare)))
break
oldSquare = n*n

print("done...")
print()
</lang>
{{out}}
<pre>
working...
Least number is = 501
done...
</pre>
</pre>


Line 297: Line 270:
THE LOWEST N WHERE THE SQUARES OF N AND N-1 DIFFER BY MORE THAN 32000 IS: 16001
THE LOWEST N WHERE THE SQUARES OF N AND N-1 DIFFER BY MORE THAN 32000 IS: 16001
THE LOWEST N WHERE THE SQUARES OF N AND N-1 DIFFER BY MORE THAN 65000 IS: 32501
THE LOWEST N WHERE THE SQUARES OF N AND N-1 DIFFER BY MORE THAN 65000 IS: 32501
</pre>

=={{header|Python}}==
<lang python>
import math
print("working...")
limit1 = 6000
limit2 = 1000
oldSquare = 0
newSquare = 0

for n in range(limit1):
newSquare = n*n
if (newSquare - oldSquare > limit2):
print("Least number is = ", end = "");
print(int(math.sqrt(newSquare)))
break
oldSquare = n*n

print("done...")
print()
</lang>
{{out}}
<pre>
working...
Least number is = 501
done...
</pre>
</pre>