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Factors of an integer: Difference between revisions
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=={{header|Scala}}==
<lang Scala>▼
Brute force approach:
▲ def factors(num: Int) = {
(1 to num).filter { divisor =>
num % divisor == 0
}
Since factors can't be higher than sqrt(num), the code above can be edited as follows
<lang
(1 to sqrt(num)).filter { divisor =>
num % divisor == 0
}
}</lang>▼
▲</lang>
=={{header|Scheme}}==
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