Factors of an integer: Difference between revisions

m (→‎optimized version: aligned a comment.)
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let factors n =
List.filter (fun v -> (n mod v) = 0) (range n)</lang>
 
=={{header|Oforth}}==
 
<lang Oforth>Integer method: factors { self seq filter(#[ self swap rem 0 &== ]) }
 
120 factors println</lang>
 
{{out}}
<pre>
[1, 2, 3, 4, 5, 6, 8, 10, 12, 15, 20, 24, 30, 40, 60, 120]
</pre>
 
=={{header|Oz}}==
1,015

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