Factors of an integer: Difference between revisions
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=={{header|R}}==
===Array solution===
<lang
{
if(length(n) > 1)
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===Filter solution===
With identical output, a more idiomatic way is to use R's Filter.
<lang
#Vectorize is an interesting alternative to the previous solution's lapply.
manyFactors <- function(vec) Vectorize(factors)(vec)</lang>
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