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Factors of an integer: Difference between revisions
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(→{{Header|Haskell}}: using product instead of foldl) |
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for(n=1;n<=num;n++) if (num%n==0) ret ~= n;
}
</lang>
=={{header|Erlang}}==
<lang erlang>
factors(N) ->
[I || I <- lists:seq(1,N div 2), N rem I == 0]++[N].
</lang>
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