Factors of an integer: Difference between revisions
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(Added an APL implementation) |
(→{{header|C sharp|C#}}: add chapel version) |
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Found: 307. 32434243 / 307 = 105649 |
Found: 307. 32434243 / 307 = 105649 |
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Done.</pre> |
Done.</pre> |
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=={{header|Chapel}}== |
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Inspired by the Clojure solution: |
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<lang chapel>iter factors(n) { |
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for i in 1..floor(sqrt(n)):int { |
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if n % i == 0 then { |
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yield i; |
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yield n / i; |
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} |
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} |
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}</lang> |
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=={{header|Clojure}}== |
=={{header|Clojure}}== |