Exponentiation with infix operators in (or operating on) the base: Difference between revisions
Exponentiation with infix operators in (or operating on) the base (view source)
Revision as of 20:44, 5 March 2021
, 3 years agoAdd QB64
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x = 5, p = 2, power(-x,p) = 25, -power(x,p) = -25
x = 5, p = 3, power(-x,p) = -125, -power(x,p) = -125
</pre>
=={{header|QB64}}==
<lang qb64>For x = -5 To 5 Step 10
For p = 2 To 3
Print "x = "; x; " p ="; p; " ";
Print Using "-x^p is ####"; -x ^ p;
Print Using ", -(x)^p is ####"; -(x) ^ p;
Print Using ", (-x)^p is ####"; (-x) ^ p;
Print Using ", -(x^p) is ####"; -(x ^ p)
Next
Next</lang>
{{out}}
<pre>
x = -5 p = 2 -x^p is -25, -(x)^p is -25, (-x)^p is 25, -(x^p) is -25
x = -5 p = 3 -x^p is 125, -(x)^p is 125, (-x)^p is 125, -(x^p) is 125
x = 5 p = 2 -x^p is -25, -(x)^p is -25, (-x)^p is 25, -(x^p) is -25
x = 5 p = 3 -x^p is -125, -(x)^p is -125, (-x)^p is -125, -(x^p) is -125
</pre>
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