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Line 34: =={{header\|11l}}== <~~lang~~syntaxhighlight lang="11l">print(5 ^ 3 ^ 2) print((5 ^ 3) ^ 2) print(5 ^ (3 ^ 2))</~~lang~~syntaxhighlight> {{out}} <pre> Line 42: 15625 1.95313e+06 </pre> =={{header\|Action!}}== There is no power operator in Action! Power function for REAL type is used. But the precision is insufficient. {{libheader\|Action! Tool Kit}} <syntaxhighlight lang="action!">INCLUDE "D2:REAL.ACT" ;from the Action! Tool Kit PROC Main() REAL r2,r3,r5,tmp1,tmp2 Put(125) PutE() ;clear screen IntToReal(2,r2) IntToReal(3,r3) IntToReal(5,r5) PrintE("There is no power operator in Action!") PrintE("Power function for REAL type is used.") PrintE("But the precision is insufficient.") Power(r5,r3,tmp1) Power(tmp1,r2,tmp2) Print("(5^3)^2=") PrintRE(tmp2) Power(r3,r2,tmp1) Power(r5,tmp1,tmp2) Print("5^(3^2)=") PrintRE(tmp2) RETURN</syntaxhighlight> {{out}} [https://gitlab.com/amarok8bit/action-rosetta-code/-/raw/master/images/Exponentiation_order.png Screenshot from Atari 8-bit computer] <pre> There is no power operator in Action! Power function for REAL type is used. But the precision is insufficient. (5^3)^2=15624.9977 5^(3^2)=1953124.17 </pre> Line 47 ⟶ 84: 532 is not a valid Ada expression. Parenthesis are mandatory. <~~lang~~syntaxhighlight ~~Ada~~lang="ada">with Ada.Text_IO; procedure Exponentation_Order is Line 55 ⟶ 92: Put_Line ("(53)2 : " & Natural'((53)2)'Image); Put_Line ("5(32) : " & Natural'(5(32))'Image); end Exponentation_Order;</~~lang~~syntaxhighlight> {{out}} Line 63 ⟶ 100: =={{header\|ALGOL 68}}== Algol 68 provides various alternative symbols for the exponentiation operator generally, "", "^" and "UP" can be used. <~~lang~~syntaxhighlight lang="algol68">print( ( "532: ", 532, newline ) ); print( ( "(53)2: ", (53)2, newline ) ); print( ( "5(32): ", 5(32), newline ) )</~~lang~~syntaxhighlight> {{out}} <pre> Line 71 ⟶ 108: (53)2: +15625 5(32): +1953125 </pre> =={{header\|ALGOL-M}}== The eponentiation operator in ALGOL-M works only on integer operands. <syntaxhighlight lang = "ALGOL"> begin write("532 = ", 532); write("(53)2 = ", (53)2); write("5(32) = ", 5(32)); end </syntaxhighlight> {{out}} The third expression results in a value that exceeds the maximum integer value of 16383. Sadly, ALGOL-M emits no warning or error message when this occurs but simply gives the wrong answer. <pre> 532 = 15625 (53)2 = 15625 5(32) = -12955 </pre> =={{header\|ALGOL W}}== The Algol W exponentiation operator always produces a real result and requires an integer right operand, hence the round functions in the following. <~~lang~~syntaxhighlight lang="algolw">begin write( "532: ", round( 5 3 2 ) ); write( "(53)2: ", round( ( 5 3 ) 2 ) ); write( "5(32): ", round( 5 round( 3 2 ) ) ) end.</~~lang~~syntaxhighlight> {{out}} <pre> Line 102 ⟶ 158: AppleScript's compiler inserts its own parentheses with 5 ^ 3 ^ 2. <~~lang~~syntaxhighlight lang="applescript">set r1 to 5 ^ 3 ^ 2 -- Changes to 5 ^ (3 ^ 2) when compiled. set r2 to (5 ^ 3) ^ 2 set r3 to 5 ^ (3 ^ 2) Line 108 ⟶ 164: return "5 ^ 3 ^ 2 = " & r1 & " (5 ^ 3) ^ 2 = " & r2 & " 5 ^ (3 ^ 2) = " & r3</~~lang~~syntaxhighlight> {{output}} Line 114 ⟶ 170: (5 ^ 3) ^ 2 = 1.5625E+4 5 ^ (3 ^ 2) = 1.953125E+6"</pre> =={{header\|Arturo}}== <syntaxhighlight lang="rebol">print 5^3^2 print (5^3)^2 print 5^(3^2)</syntaxhighlight> {{out}} <pre>1953125 15625 1953125</pre> =={{header\|AWK}}== <syntaxhighlight lang="awk"> ~~<lang AWK>~~ # syntax: GAWK -f EXPONENTIATION_ORDER.AWK BEGIN { Line 124 ⟶ 192: exit(0) } </syntaxhighlight> ~~</lang>~~ <p>output:</p> <pre> Line 133 ⟶ 201: =={{header\|BASIC}}== ==={{header\|~~Sinclair ZX81~~Applesoft BASIC}}=== <syntaxhighlight lang="gwbasic">?"5^3^2 = "5 ^ 3 ^ 2 CHR$ (13)"(5^3)^2 = "(5 ^ 3) ^ 2 CHR$ (13)"5^(3^2) = "5 ^ (3 ^ 2);</syntaxhighlight> ~~<lang basic>10 PRINT "532 = ";532~~ ~~20 PRINT "(53)2 = ";(53)2~~ ~~30 PRINT "5(32) = ";5(32)</lang>~~ {{out}} <pre>5^3^2 = 15625 (5^3)^2 = 15625 5^(3^2) = 1953125.01</pre> ==={{header\|BASIC256}}=== {{works with\|QBasic}} {{works with\|FreeBASIC}} {{works with\|True BASIC}} {{works with\|Run BASIC}} <syntaxhighlight lang="freebasic">print "5^3^2 = "; 5^3^2 print "(5^3)^2 = "; (5^3)^2 print "5^(3^2) = "; 5^(3^2) end</syntaxhighlight> {{out}} <pre>5^3^2 = 15625 (5^3)^2 = 15625 5^(3^2) = 1953125</pre> ==={{header\|BBC BASIC}}=== <~~lang~~syntaxhighlight lang="bbcbasic">PRINT "5^3^2 = "; 5^3^2 PRINT "(5^3)^2 = "; (5^3)^2 PRINT "5^(3^2) = "; 5^(3^2)</~~lang~~syntaxhighlight> {{out}} <pre>5^3^2 = 15625 (5^3)^2 = 15625 5^(3^2) = 1953125</pre> ==={{header\|Chipmunk Basic}}=== {{works with\|Chipmunk Basic\|3.6.4}} <syntaxhighlight lang="qbasic">10 print "5^3^2 = "5^3^2 20 print "(5^3)^2 = "(5^3)^2 30 print "5^(3^2) = "5^(3^2)</syntaxhighlight> {{out}} <pre>5^3^2 = 15625 (5^3)^2 = 15625 5^(3^2) = 1953125</pre> ==={{header\|GW-BASIC}}=== {{works with\|Applesoft BASIC}} {{works with\|Chipmunk Basic}} {{works with\|MSX_BASIC}} {{works with\|PC-BASIC\|any}} {{works with\|QBasic}} <syntaxhighlight lang="qbasic">10 PRINT "5^3^2 =" 5^3^2 20 PRINT "(5^3)^2 =" (5^3)^2 30 PRINT "5^(3^2) =" 5^(3^2)</syntaxhighlight> {{out}} <pre>5^3^2 = 15625 Line 152 ⟶ 255: ==={{header\|IS-BASIC}}=== <~~lang~~syntaxhighlight ISlang="is-~~BASIC~~basic">100 PRINT "5^3^2 =";5^3^2 110 PRINT "(5^3)^2 =";(5^3)^2 120 PRINT "5^(3^2) =";5^(3^2)</~~lang~~syntaxhighlight> {{out}} <pre>5^3^2 = 15625 (5^3)^2 = 15625 5^(3^2) = 1953125</pre> ==={{header\|MSX Basic}}=== <syntaxhighlight lang="qbasic">10 PRINT "5^3^2 =" 5^3^2 20 PRINT "(5^3)^2 =" (5^3)^2 30 PRINT "5^(3^2) =" 5^(3^2)</syntaxhighlight> {{out}} <pre>5^3^2 = 15625 (5^3)^2 = 15625 5^(3^2) = 1953125</pre> ==={{header\|PureBasic}}=== In the PureBasic it is impossible to show the result of: 5^3^2 <syntaxhighlight lang="vb">OpenConsole() PrintN("(5^3)^2 = " + Str(Pow(Pow(5, 3), 2))) PrintN("5^(3^2) = " + Str(Pow(5, (Pow(3, 2))))) CloseConsole()</syntaxhighlight> {{out}} <pre>(5^3)^2 = 15625 5^(3^2) = 1953125</pre> ==={{header\|QBasic}}=== {{works with\|QBasic\|1.1}} {{works with\|QuickBasic\|4.5}} {{works with\|FreeBASIC}} {{works with\|True BASIC}} {{works with\|BASIC256}} {{works with\|Run BASIC}} <syntaxhighlight lang="qbasic">PRINT "5^3^2 ="; 5^3^2 PRINT "(5^3)^2 ="; (5^3)^2 PRINT "5^(3^2) ="; 5^(3^2) END</syntaxhighlight> {{out}} <pre>5^3^2 = 15625 (5^3)^2 = 15625 5^(3^2) = 1953125</pre> ==={{header\|Run BASIC}}=== {{works with\|QBasic}} {{works with\|FreeBASIC}} {{works with\|True BASIC}} {{works with\|BASIC256}} <syntaxhighlight lang="freebasic">print "5^3^2 = "; 5^3^2 print "(5^3)^2 = "; (5^3)^2 print "5^(3^2) = "; 5^(3^2) end</syntaxhighlight> {{out}} <pre>5^3^2 = 15625 (5^3)^2 = 15625 5^(3^2) = 1953125</pre> ==={{header\|True BASIC}}=== {{works with\|QBasic}} {{works with\|FreeBASIC}} {{works with\|BASIC256}} {{works with\|Run BASIC}} <syntaxhighlight lang="qbasic">PRINT "5^3^2 ="; 5^3^2 PRINT "(5^3)^2 ="; (5^3)^2 PRINT "5^(3^2) ="; 5^(3^2) END</syntaxhighlight> {{out}} <pre>5^3^2 = 15625 (5^3)^2 = 15625 5^(3^2) = 1953125</pre> ==={{header\|XBasic}}=== {{works with\|Windows XBasic}} <syntaxhighlight lang="qbasic">PROGRAM "Exponentiation order" VERSION "0.0000" DECLARE FUNCTION Entry () FUNCTION Entry () PRINT "5^3^2 ="; 532 PRINT "(5^3)^2 ="; (53)2 PRINT "5^(3^2) ="; 5(32) END FUNCTION END PROGRAM</syntaxhighlight> {{out}} <pre>5^3^2 = 15625 (5^3)^2 = 15625 5^(3^2) = 1953125</pre> ==={{header\|Yabasic}}=== {{works with\|QBasic}} {{works with\|FreeBASIC}} {{works with\|True BASIC}} {{works with\|BASIC256}} <syntaxhighlight lang="freebasic">print "5^3^2 = ", 5^3^2 print "(5^3)^2 = ", (5^3)^2 print "5^(3^2) = ", 5^(3^2) end</syntaxhighlight> {{out}} <pre>5^3^2 = 15625 (5^3)^2 = 15625 5^(3^2) = 1953125</pre> ==={{header\|Sinclair ZX81 BASIC}}=== <syntaxhighlight lang="basic">10 PRINT "532 = ";532 20 PRINT "(53)2 = ";(53)2 30 PRINT "5(32) = ";5(32)</syntaxhighlight> {{out}} <pre>532 = 15625 (53)2 = 15625 5(32) = 1953125</pre> =={{header\|Bracmat}}== <~~lang~~syntaxhighlight ~~Bracmat~~lang="bracmat">put$str$("5^3^2: " 5^3^2 "\n(5^3)^2: " (5^3)^2 "\n5^(3^2): " 5^(3^2) \n) </~~lang~~syntaxhighlight> {{out}} <pre>5^3^2: 1953125 Line 170 ⟶ 377: C does not have an exponentiation operator. The caret operator '^' performs xor bitwise operation in C. The function pow in the standard C Math library takes two arguments. <~~lang~~syntaxhighlight Clang="c">#include<stdio.h> #include<math.h> Line 179 ⟶ 386: return 0; }</~~lang~~syntaxhighlight> {{out}} Line 188 ⟶ 395: =={{header\|C++}}== <~~lang~~syntaxhighlight lang="cpp">#include <iostream> #include <cmath> Line 196 ⟶ 403: return EXIT_SUCCESS; }</~~lang~~syntaxhighlight> With permissive flag: <~~lang~~syntaxhighlight lang="cpp">#include <iostream> #include <cmath> Line 211 ⟶ 418: return EXIT_SUCCESS; }</~~lang~~syntaxhighlight> {{out}} Line 219 ⟶ 426: </pre> =={{header\|C sharp\|C#}}== <~~lang~~syntaxhighlight lang="csharp">using System; namespace exponents Line 240 ⟶ 447: } } </syntaxhighlight> ~~</lang>~~ {{out}} <pre> Line 250 ⟶ 457: Clojure uses prefix notation and expt only takes 2 arguments for exponentiation, so "532" isn't represented. <~~lang~~syntaxhighlight lang="clojure">(use 'clojure.math.numeric-tower) ;; (53)2 (expt (expt 5 3) 2) ; => 15625 Line 262 ⟶ 469: ;; 5(32) alternative: evaluating right-to-left with reduce requires a small modification (defn rreduce [f coll] (reduce #(f %2 %) (reverse coll))) (rreduce expt [5 3 2]) ; => 1953125</~~lang~~syntaxhighlight> =={{header\|CLU}}== <syntaxhighlight lang="clu">start_up = proc () po: stream := stream$primary_output() stream$putl(po, "532 = " \|\| int$unparse(532)) stream$putl(po, "(53)2 = " \|\| int$unparse((53)2)) stream$putl(po, "5(32) = " \|\| int$unparse(5(32))) end start_up</syntaxhighlight> {{out}} <pre>532 = 1953125 (53)2 = 15625 5(32) = 1953125</pre> =={{header\|Common Lisp}}== Because Common Lisp uses prefix notation and <code>expt</code> accepts only two arguments, it doesn't have an expression for <code>532</code>. Just showing expressions for the latter two. <~~lang~~syntaxhighlight lang="lisp">(expt (expt 5 3) 2) (expt 5 (expt 3 2))</~~lang~~syntaxhighlight> {{out}} <pre>15625 Line 273 ⟶ 493: =={{header\|D}}== <~~lang~~syntaxhighlight lang="d">void main() { import std.stdio, std.math, std.algorithm; Line 280 ⟶ 500: writefln("5 ^^ (3 ^^ 2) = %7d", 5 ^^ (3 ^^ 2)); writefln("[5, 3, 2].reduce!pow = %7d", [5, 3, 2].reduce!pow); }</~~lang~~syntaxhighlight> {{out}} <pre>5 ^^ 3 ^^ 2 = 1953125 Line 286 ⟶ 506: 5 ^^ (3 ^^ 2) = 1953125 [5, 3, 2].reduce!pow = 15625</pre> =={{header\|Delphi}}== {{works with\|Delphi\|6.0}} {{libheader\|Math,SysUtils,StdCtrls}} Delphi doesn't have exponentiation but it does have the "Power" function in the math library <syntaxhighlight lang="Delphi"> procedure ExponentDemo(Memo: TMemo); begin Memo.Lines.Add('5^3^2 = '+FloatToStrF(Power(5,Power(3,2)),ffNumber,18,0)); Memo.Lines.Add('(5^3)^2 = '+FloatToStrF(Power(Power(5,3),2),ffNumber,18,0)); Memo.Lines.Add('5^(3^2) = '+FloatToStrF(Power(5,Power(3,2)),ffNumber,18,0)); end; </syntaxhighlight> {{out}} <pre> 5^3^2 = 1,953,125 (5^3)^2 = 15,625 5^(3^2) = 1,953,125 </pre> =={{header\|Dart}}== <syntaxhighlight lang="dart">import 'dart:math' show pow; void main() { print('(5 ^ 3) ^ 2 = ${pow(pow(5, 3), 2)}'); print('5 ^ (3 ^ 2) = ${pow(5, (pow(3, 2)))}'); }</syntaxhighlight> {{out}} <pre>(5 ^ 3) ^ 2 = 15625 5 ^ (3 ^ 2) = 1953125</pre> =={{header\|EasyLang}}== <syntaxhighlight> print "(5 ^ 3) ^ 2 = " & pow (pow 5 3) 2 print "5 ^ (3 ^ 2) = " & pow 5 pow 3 2 </syntaxhighlight> =={{header\|EchoLisp}}== <~~lang~~syntaxhighlight lang="scheme"> ;; the standard and secure way is to use the (expt a b) function (expt 5 (expt 3 2)) ;; 5 ( 3 2) Line 305 ⟶ 565: (5 (3 2)) → 1953125 </syntaxhighlight> ~~</lang>~~ =={{header\|Factor}}== Factor is a stack language where expressions take the form of reverse Polish notation, so there is no ambiguity here. It is up to you, the programmer, to perform operations in the order you intend. <~~lang~~syntaxhighlight lang="factor">USING: formatting math.functions ; 5 3 2 ^ ^ Line 315 ⟶ 575: 5 3 ^ 2 ^ "5 3 ^ 2 ^ %d\n" printf</~~lang~~syntaxhighlight> {{out}} <pre> Line 324 ⟶ 584: Factor also has syntax for infix arithmetic via the the <code>infix</code> vocabulary. <~~lang~~syntaxhighlight lang="factor">USING: formatting infix ; [infix 532 infix] Line 333 ⟶ 593: [infix 5(32) infix] "5(32) = %d\n" printf</~~lang~~syntaxhighlight> {{out}} <pre> Line 342 ⟶ 602: =={{header\|Fortran}}== <~~lang~~syntaxhighlight ~~Fortran~~lang="fortran">write(, "(a, i0)") "532 = ", 532 write(, "(a, i0)") "(53)2 = ", (53)2 write(, "(a, i0)") "5(32) = ", 5(32)</~~lang~~syntaxhighlight> {{out}} <pre>532 = 1953125 Line 351 ⟶ 611: =={{header\|FreeBASIC}}== <~~lang~~syntaxhighlight lang="freebasic">' FB 1.05.0 ' The exponentation operator in FB is ^ rather than . Line 361 ⟶ 621: Print "(5^3)^2 =>"; (5^3)^2 Print "5^(3^2) =>"; 5^(3^2) Sleep</~~lang~~syntaxhighlight> {{out}} Line 373 ⟶ 633: Frink correctly follows standard mathematical notation that exponent towers are performed from "top to bottom" or "right to left." <~~lang~~syntaxhighlight ~~Frink~~lang="frink">println["5^3^2 = " + 5^3^2] println["(5^3)^2 = " + (5^3)^2] println["5^(3^2) = " + 5^(3^2)] </syntaxhighlight> ~~</lang>~~ {{out}} Line 383 ⟶ 643: (5^3)^2 = 15625 5^(3^2) = 1953125 </pre> =={{header\|FutureBasic}}== FB is translated into C which does not have an exponentiation operator. The caret operator '^' performs xor bitwise operation. FB also has an fn pow function, translated from the the standard C Math library, which takes two arguments. <syntaxhighlight lang="futurebasic"> print "(5^3)^2 = "; (5^3)^2 print "5^(3^2) = "; 5^(3^2) print print "fn pow( fn pow(5,3), 2 ) = "; fn pow( fn pow(5,3), 2 ) print "fn pow( 5, fn pow(3,2 ) ) = "; fn pow( 5, fn pow(3,2 ) ) HandleEvents </syntaxhighlight> {{output}} <pre> (5^3)^2 = 15625 5^(3^2) = 1953125 fn pow( fn pow(5,3), 2 ) = 15625 fn pow( 5, fn pow(3,2 ) ) = 1953125 </pre> =={{header\|Go}}== <~~lang~~syntaxhighlight Golang="go">package main import "fmt" Line 399 ⟶ 679: fmt.Printf("(5^3)^2 = %.0f\n", b) fmt.Printf("5^(3^2) = %.0f\n", c) }</~~lang~~syntaxhighlight> {{out}} Line 411 ⟶ 691: Solution: <~~lang~~syntaxhighlight lang="groovy">println(" 5 * 3 2 == " + 532) println("(5 3) 2 == " + (53)2) println(" 5 (3 2)== " + 5(32))</~~lang~~syntaxhighlight> Output: Line 474 ⟶ 754: J uses the same evaluation order for exponentiation as it does for assignment. That is to say: the bottom up view is right-to-left and the top-down view is left-to-right. <~~lang~~syntaxhighlight Jlang="j"> 5^3^2 1.95312e6 (5^3)^2 15625 5^(3^2) 1.95312e6</~~lang~~syntaxhighlight> ---- Line 491 ⟶ 771: jq's built-in for exponentiation is an arity-two function and thus no ambiguity arising from infix-notation is possible. Here's an example: <~~lang~~syntaxhighlight lang="jq">jq -n 'pow(pow(5;3);2)' 15625</~~lang~~syntaxhighlight> For chaining, one could use `reduce`: <~~lang~~syntaxhighlight lang="jq"> def pow: reduce .[1:] as $i (.[0]; pow(.;$i)) [5,3,2] \| pow</~~lang~~syntaxhighlight> Result: 15625 Line 505 ⟶ 785: {{works with\|Julia\|0.6}} <~~lang~~syntaxhighlight lang="julia">@show 5 ^ 3 ^ 2 # default: power operator is read right-to-left @show (5 ^ 3) ^ 2 @show 5 ^ (3 ^ 2) @show reduce(^, [5, 3, 2]) @show foldl(^, [5, 3, 2]) # guarantees left associativity @show foldr(^, [5, 3, 2]) # guarantees right associativity</~~lang~~syntaxhighlight> {{out}} Line 522 ⟶ 802: =={{header\|Kotlin}}== Kotlin does not have a dedicated exponentiation operator and we would normally use Java's Math.pow function instead. However, it's possible to define an infix function which would look like an operator and here we do so for integer base and exponent. For simplicity we disallow negative exponents altogether and consider 0 0 == 1. Associativity would, of course, be the same as for a normal function call. <~~lang~~syntaxhighlight lang="scala">// version 1.0.5-2 infix fun Int.ipow(exp: Int): Int = when { Line 544 ⟶ 824: println("(53)2 = ${(5 ipow 3) ipow 2}") println("5(32) = ${5 ipow (3 ipow 2)}") }</~~lang~~syntaxhighlight> {{out}} Line 557 ⟶ 837: Because lambdatalk uses prefix notation and {pow a b} accepts only two arguments, it doesn't have an expression for 532. Just showing expressions for the latter two. <~~lang~~syntaxhighlight lang="scheme"> '{pow {pow 5 3} 2} -> {pow {pow 5 3} 2} '{pow 5 {pow 3 2}} -> {pow 5 {pow 3 2}} </syntaxhighlight> ~~</lang>~~ =={{header\|langur}}== <syntaxhighlight lang="langur">writeln " 5^3^2: ", 5^3^2 writeln "(5^3)^2: ", (5^3)^2 writeln "5^(3^2): ", 5^(3^2) </syntaxhighlight> {{out}} <pre> 5^3^2: 1953125 (5^3)^2: 15625 5^(3^2): 1953125 </pre> =={{header\|Latitude}}== <~~lang~~syntaxhighlight lang="latitude">5 ^ 3 ^ 2. ;; 1953125 (5 ^ 3) ^ 2. ;; 15625 5 ^ (3 ^ 2). ;; 1953125</~~lang~~syntaxhighlight> =={{header\|Lua}}== <~~lang~~syntaxhighlight ~~Lua~~lang="lua">print("5^3^2 = " .. 5^3^2) print("(5^3)^2 = " .. (5^3)^2) print("5^(3^2) = " .. 5^(3^2))</~~lang~~syntaxhighlight> {{out}} <pre>5^3^2 = 1953125 Line 580 ⟶ 872: =={{header\|Maple}}== <~~lang~~syntaxhighlight ~~Maple~~lang="maple">5^3^2; (5^3)^2; 5^(3^2);</~~lang~~syntaxhighlight> {{Out\|Output}} <pre>Error, ambiguous use of `^`, please use parentheses Line 589 ⟶ 881: =={{header\|Mathematica}} / {{header\|Wolfram Language}}== <~~lang~~syntaxhighlight ~~Mathematica~~lang="mathematica">a = "5^3^2"; Print[a <> " = " <> ToString[ToExpression[a]]] b = "(5^3)^2"; Print[b <> " = " <> ToString[ToExpression[b]]] c = "5^(3^2)"; Print[c <> " = " <> ToString[ToExpression[c]]]</~~lang~~syntaxhighlight> {{out}} <pre>5^3^2 = 1953125 Line 603 ⟶ 895: As with other postfix languages, there is no ambiguity because all operators have the same precedence. {{works with\|min\|0.19.6}} <~~lang~~syntaxhighlight lang="min">5 3 2 pow pow "5 3 2 ^ ^ " print! puts! 5 3 pow 2 pow "5 3 ^ 2 ^ " print! puts!</~~lang~~syntaxhighlight> {{out}} <pre> 5 3 2 ^ ^ 1953125.0 5 3 ^ 2 ^ 15625.0 </pre> =={{header\|MiniScript}}== REPL output. {{out}} <pre> ]5^3^2 15625 ](5^3)^2 15625 ]5^(3^2) 1953125 </pre> =={{header\|Nanoquery}}== Nanoquery uses the '^' operator, which performs exponentiation in order like multiplication. Parenthesis are often needed to perform operations like 5^3^2 correctly. <~~lang~~syntaxhighlight ~~Nanoquery~~lang="nanoquery">% println 5^3^2 15625 % println (5^3)^2 15625 % println 5^(3^2) 1953125</~~lang~~syntaxhighlight> =={{header\|Nim}}== <~~Lang~~syntaxhighlight ~~Nim~~lang="nim">import math, sequtils echo "5^3^2 = ", 5^3^2 Line 630 ⟶ 934: echo "5^(3^2) = ", 5^(3^2) echo "foldl([5, 3, 2], a^b) = ", foldl([5, 3, 2], a^b) echo "foldr([5, 3, 2], a^b) = ", foldr([5, 3, 2], a^b)</~~lang~~syntaxhighlight> {{out}} Line 641 ⟶ 945: =={{header\|OCaml}}== OCaml language has '' as an exponentiation symbol for floating point integers <syntaxhighlight lang="ocaml"> ~~<OCaml code>~~ # 5. 3. 2. ;; # 5. ( 3. 2.) ;; #(5. 3. ) 2. ;; </syntaxhighlight> {{out}} <pre> Line 656 ⟶ 960: =={{header\|PARI/GP}}== Exponentiation is right-associative in GP. <~~lang~~syntaxhighlight lang="parigp">f(s)=print(s" = "eval(s)); apply(f, ["5^3^2", "(5^3)^2", "5^(3^2)"]);</~~lang~~syntaxhighlight> {{out}} <pre>5^3^2 = 1953125 Line 664 ⟶ 968: =={{header\|Perl}}== <~~lang~~syntaxhighlight lang="perl">say "$_ = " . eval($_) for qw/532 (53)2 5(32)/;</~~lang~~syntaxhighlight> {{out}} <pre> Line 675 ⟶ 979: {{libheader\|Phix/basics}} Phix has a power function rather than an infix power operator, hence there is no possible confusion. <!--<~~lang~~syntaxhighlight ~~Phix~~lang="phix">--> <span style="color: #0000FF;">?<span style="color: #7060A8;">power<span style="color: #0000FF;">(<span style="color: #7060A8;">power<span style="color: #0000FF;">(<span style="color: #000000;">5<span style="color: #0000FF;">,<span style="color: #000000;">3<span style="color: #0000FF;">)<span style="color: #0000FF;">,<span style="color: #000000;">2<span style="color: #0000FF;">)</span> <span style="color: #0000FF;">?<span style="color: #7060A8;">power<span style="color: #0000FF;">(<span style="color: #000000;">5<span style="color: #0000FF;">,<span style="color: #7060A8;">power<span style="color: #0000FF;">(<span style="color: #000000;">3<span style="color: #0000FF;">,<span style="color: #000000;">2<span style="color: #0000FF;">)<span style="color: #0000FF;">) <!--</~~lang~~syntaxhighlight>--> {{out}} <pre> 15625 1953125 </pre> =={{header\|Picat}}== <syntaxhighlight lang="picat">main => X = 532, Y = (53)2, Z = 5(32), print("532 = "), println(X), print("(53)2 = "), println(Y), print("5(32) = "), print(Z). </syntaxhighlight> {{out}} <pre> 532 = 1953125 (53)2 = 15625 5(32) = 1953125 </pre> =={{header\|PicoLisp}}== The PicoLisp '' exponentiation function takes 2 arguments <~~lang~~syntaxhighlight ~~PicoLisp~~lang="picolisp">: ( ( 5 3) 2) -> 15625 : ( 5 ( 3 2)) -> 1953125</~~lang~~syntaxhighlight> =={{header\|PL/I}}== <syntaxhighlight lang="pli">exponentiation: procedure options(main); put skip edit('532 = ', 532) (A,F(7)); put skip edit('(53)2 = ', (53)2) (A,F(7)); put skip edit('5(32) = ', 5(32)) (A,F(7)); end exponentiation;</syntaxhighlight> {{out}} <pre>532 = 15625 (53)2 = 15625 5(32) = 1953125</pre> =={{header\|Python}}== <~~lang~~syntaxhighlight lang="python">>>> 532 1953125 >>> (53)2 Line 706 ⟶ 1,037: >>> reduce(pow, (5, 3, 2)) 15625 >>> </~~lang~~syntaxhighlight> =={{header\|Quackery}}== Line 729 ⟶ 1,060: It turns out that the parser is so blind to "" that we cannot even quote it. The following are identical: <~~lang~~syntaxhighlight rlang="rsplus">print(quote(53)) print(quote(5^3))</~~lang~~syntaxhighlight> Another method is to use "^" as if it is an ordinary function of two arguments. It appears that "" does not support this. As there is no potential for ambiguity in the operator precedence, we will not print this result below. For example: <~~lang~~syntaxhighlight rlang="rsplus">'^'('^'(5, 3), 2)</~~lang~~syntaxhighlight> is clearly (5^3)^2 i.e. 15625, whereas <~~lang~~syntaxhighlight rlang="rsplus">'^'(5, '^'(3, 2))</~~lang~~syntaxhighlight> is clearly 5^(3^2) i.e. 1953125. As for actually solving the task, the requirement that each output be on a new line causes us a surprising amount of difficulty. To avoid repeating ourselves, we must almost resort to metaprogramming: <~~lang~~syntaxhighlight rlang="rsplus">inputs <- alist(5^3^2, (5^3)^2, 5^(3^2), 532, (53)2, 5(32)) invisible(sapply(inputs, function(x) cat(deparse(x), "returns: ", eval(x), "\n")))</~~lang~~syntaxhighlight> Alternatively, we could print out a matrix or data frame: <~~lang~~syntaxhighlight rlang="rsplus">print(matrix(sapply(inputs, eval), dimnames = list(inputs, "Outputs"))) print(data.frame(Inputs = sapply(inputs, deparse), Outputs = sapply(inputs, eval))))</~~lang~~syntaxhighlight> {{out}} <pre>> print(quote(53)) Line 765 ⟶ 1,096: (5^3)^2 15625 5^(3^2) 1953125 > print(data.frame(Inputs = sapply(inputs, deparse), Outputs = sapply(inputs, eval))) Inputs Outputs 1 5^3^2 1953125 Line 775 ⟶ 1,106: =={{header\|Racket}}== <~~lang~~syntaxhighlight lang="racket">#lang racket ;; 532 depends on associativity of : Racket's (scheme's) prefix function ;; calling syntax only allows for pairs of arguments for expt. Line 796 ⟶ 1,127: (require (only-in srfi/1 reduce reduce-right)) (reduce expt 1 '(5 3 2)) (reduce-right expt 1 '(5 3 2))</~~lang~~syntaxhighlight> {{out}} <pre>prefix Line 814 ⟶ 1,145: Note that the reduction forms automatically go right-to-left because the base operator is right-associative. Most other operators are left-associative and would automatically reduce left-to-right instead. <syntaxhighlight lang="raku" ~~perl6~~line>use MONKEY-SEE-NO-EVAL; sub demo($x) { say " $x\t───► ", EVAL $x } Line 828 ⟶ 1,159: demo '(5³)²'; demo '5³²'; </syntaxhighlight> ~~</lang>~~ {{out}} Line 842 ⟶ 1,173: The Unicode exponent form without parentheses ends up raising to the 32nd power. Nor are you even allowed to parenthesize it the other way: <tt>5(³²)</tt> would be a syntax error. Despite all that, for programs that do a lot of squaring or cubing, the postfix forms can enhance both readability and concision. =={{header\|Red}}== In Red, operators simply evaluate left to right. As this differs from mathematical order of operations, Red provides the <code>math</code> function which evaluates a block using math rules instead of Red's default evaluation. One could also use the <code>power</code> function, sidestepping the issue of evaluation order entirely. All three approaches are shown. <syntaxhighlight lang="rebol">Red["Exponentiation order"] exprs: [ [5 3 2] [(5 3) 2] [5 (3 2)] [power power 5 3 2] ;-- functions too [power 5 power 3 2] ] foreach expr exprs [ print [mold/only expr "=" do expr] if find expr ' [ print [mold/only expr "=" math expr "using math"] ] ]</syntaxhighlight> {{out}} <pre> 5 3 2 = 15625 5 3 2 = 1953125 using math (5 3) 2 = 15625 (5 3) 2 = 15625 using math 5 (3 2) = 1953125 5 (3 2) = 1953125 using math power power 5 3 2 = 15625 power 5 power 3 2 = 1953125 </pre> =={{header\|REXX}}== <~~lang~~syntaxhighlight lang="rexx">/REXX program demonstrates various ways of multiple exponentiations. / /┌────────────────────────────────────────────────────────────────────┐ │ The REXX language uses * for exponentiation. │ Line 854 ⟶ 1,215: say ' (53)2 ───► ' (53)2 say ' 5(32) ───► ' 5(32) /stick a fork in it, we're done./</~~lang~~syntaxhighlight> '''output''' <pre> Line 866 ⟶ 1,227: In the Ring it is impossible to show the result of: 5^3^2 <~~lang~~syntaxhighlight lang="ring"> see "(5^3)^2 =>" + pow(pow(5,3),2) + nl see "5^(3^2) =>" + pow(5,pow(3,2)) + nl </syntaxhighlight> ~~</lang>~~ Output: <pre> (5^3)^2 =>15625 5^(3^2) =>1953125 </pre> =={{header\|RPL}}== When using reverse Polish notation, there is no parenthesis: the user must decide the exponentiation order. When using algebraic notation: '5^3^2' →NUM '(5^3)^2' →NUM '5^(3^2)' →NUM {{out}} <pre> 3: 15625 2: 15625 1: 1953125 </pre> =={{header\|Ruby}}== <~~lang~~syntaxhighlight lang="ruby">ar = ["532", "(53)2", "5(32)", "[5,3,2].inject(:)"] ar.each{\|exp\| puts "#{exp}:\t#{eval exp}"} </syntaxhighlight> ~~</lang>~~ {{out}} <pre> Line 890 ⟶ 1,264: =={{header\|Rust}}== <~~lang~~syntaxhighlight lang="rust">fn main() { println!("532 = {:7}", 5u32.pow(3).pow(2)); println!("(53)2 = {:7}", (5u32.pow(3)).pow(2)); println!("5(32) = {:7}", 5u32.pow(3u32.pow(2))); }</~~lang~~syntaxhighlight> {{out}} <pre> Line 900 ⟶ 1,274: (53)2 = 15625 5(32) = 1953125 </pre> =={{header\|S-BASIC}}== The exponentiation operator ^ works on both integer and real operands. Numeric constants in expressions are taken to be of type real, which is useful here, because the third result exceeds S-BASIC's manximum integer value of 32767. <syntaxhighlight lang = "BASIC"> print "5^3^2 : "; 5 ^ 3 ^ 2 print "(5^3)^2 : "; (5 ^ 3) ^ 2 print "5^(3^2) : "; 5 ^ (3 ^ 2) end </syntaxhighlight> {{out}} <pre> 5^3^2 : 15625 (5^3)^2 : 15625 5^(3^2) : 1.95312E+6 </pre> Line 906 ⟶ 1,296: =={{header\|Seed7}}== <~~lang~~syntaxhighlight lang="seed7">$ include "seed7_05.s7i"; const proc: main is func Line 913 ⟶ 1,303: writeln("(53)2 = " <& (53)2); writeln("5(32) = " <& 5(32)); end func;</~~lang~~syntaxhighlight> {{out}} Line 924 ⟶ 1,314: =={{header\|Sidef}}== In Sidef, the whitespace between the operands and the operator controls the precedence of the operation. <~~lang~~syntaxhighlight lang="ruby">var a = [ '532', '(53)2', Line 936 ⟶ 1,326: a.each {\|e\| "%-12s == %s\n".printf(e, eval(e)) }</~~lang~~syntaxhighlight> {{out}} <pre> Line 949 ⟶ 1,339: =={{header\|Simula}}== <~~lang~~syntaxhighlight ~~Simula~~lang="simula">OutText("5 3 2: "); OutInt(5 3 2, 0); Outimage; OutText("(53)2: "); OutInt((53)2, 0); Outimage; OutText("5(32): "); OutInt(5(32), 0); Outimage</~~lang~~syntaxhighlight> {{out}} <pre>5 3 2: 15625 Line 960 ⟶ 1,350: Works in Smalltalk/X ¹ <p>Smalltalk strictly evaluates left to right; operators are not known to the language/parser, but instead message sends to the receiver on the left side (aka: virtual function calls) . <~~lang~~syntaxhighlight lang="smalltalk">Transcript show:'532 => '; showCR: 532. Transcript show:'(53)2 => '; showCR: (53)2. Transcript show:'5(32) => '; showCR: 5(32).</~~lang~~syntaxhighlight> {{out}} <pre> Line 973 ⟶ 1,363: =={{header\|Stata}}== <~~lang~~syntaxhighlight lang="stata">. di (5^3^2) 15625 Line 980 ⟶ 1,370: . di (5^(3^2)) 1953125</~~lang~~syntaxhighlight> Likewise in Mata: <~~lang~~syntaxhighlight lang="stata">. mata (5^3^2) 15625 Line 991 ⟶ 1,381: . mata (5^(3^2)) 1953125</~~lang~~syntaxhighlight> =={{header\|Swift}}== Swift doesn't have an exponentiation operator, however it's possible to define one, including the precedence and associativity. <syntaxhighlight lang="swift">precedencegroup ExponentiationPrecedence { associativity: left higherThan: MultiplicationPrecedence } infix operator : ExponentiationPrecedence @inlinable public func ** <T: BinaryInteger>(lhs: T, rhs: T) -> T { guard lhs != 0 else { return 1 } var x = lhs var n = rhs var y = T(1) while n > 1 { switch n & 1 { case 0: n /= 2 case 1: y = x n = (n - 1) / 2 case _: fatalError() } x = x } return x * y } print(5 3 2) print((5 3) 2) print(5 (3 2))</syntaxhighlight> {{out}} <pre>15625 15625 1953125</pre> =={{header\|Tcl}}== <~~lang~~syntaxhighlight lang="tcl">foreach expression {532 (53)2 5(32)} { puts "${expression}:\t[expr $expression]" }</~~lang~~syntaxhighlight> {{out}} <pre> Line 1,006 ⟶ 1,445: =={{header\|VBA}}== <~~lang~~syntaxhighlight lang="vb">Public Sub exp() Debug.Print "5^3^2", 5 ^ 3 ^ 2 Debug.Print "(5^3)^2", (5 ^ 3) ^ 2 Debug.Print "5^(3^2)", 5 ^ (3 ^ 2) End Sub</~~lang~~syntaxhighlight>{{out}} <pre>5^3^2 15625 (5^3)^2 15625 Line 1,017 ⟶ 1,456: =={{header\|VBScript}}== <syntaxhighlight lang="vb"> ~~<lang vb>~~ WScript.StdOut.WriteLine "5^3^2 => " & 5^3^2 WScript.StdOut.WriteLine "(5^3)^2 => " & (5^3)^2 WScript.StdOut.WriteLine "5^(3^2) => " & 5^(3^2) </syntaxhighlight> ~~</lang>~~ {{Out}} Line 1,031 ⟶ 1,470: =={{header\|Verbexx}}== <~~lang~~syntaxhighlight lang="verbexx">// Exponentiation order example: @SAY "532 = " ( 532 ); Line 1,041 ⟶ 1,480: 532 = 1953125 (53)2 = 15625 5(32) = 1953125</~~lang~~syntaxhighlight> =={{header\|Wren}}== {{libheader\|Wren-fmt}} Wren doesn't have an exponentiation operator as such but the Num class has a ''pow'' method which does the same thing. <~~lang~~syntaxhighlight ~~ecmascript~~lang="wren">import "./fmt" for Fmt var ops = [ "532", "(53)2", "5(32)" ] var results = [ 5.pow(3).pow(2), (5.pow(3)).pow(2), 5.pow(3.pow(2)) ] for (i in 0...ops.count) { ~~System~~Fmt.print("~~%(Fmt.s(~~$-99s -> $d", ops[i])), ~~-> %(~~results[i])") }</~~lang~~syntaxhighlight> {{out}} Line 1,059 ⟶ 1,498: (53)2 -> 15625 5(32) -> 1953125 </pre> =={{header\|XPL0}}== XPL0 doesn't have an exponentiation operator, but it does have a Pow intrinsic (in the 32-bit versions). <syntaxhighlight lang "XPL0">[Format(1, 0); Text(0, "532 = "); RlOut(0, Pow(5., Pow(3., 2.))); CrLf(0); \right associative Text(0, "(53)2 = "); RlOut(0, Pow(Pow(5., 3.), 2.)); CrLf(0); Text(0, "5(32) = "); RlOut(0, Pow(5., Pow(3., 2.))); CrLf(0); ]</syntaxhighlight> {{out}} <pre> 532 = 1953125 (53)2 = 15625 5(32) = 1953125 </pre> Line 1,064 ⟶ 1,517: {{trans\|C}} zkl does not have an exponentiation operator but floats have a pow method. <~~lang~~syntaxhighlight lang="zkl">println("5 ^ 3 ^ 2 = %,d".fmt((5.0).pow((3.0).pow(2)))); println("(5 ^ 3) ^ 2 = %,d".fmt((5.0).pow(3).pow(2))); println("5 ^ (3 ^ 2) = %,d".fmt((5.0).pow((3.0).pow(2))));</~~lang~~syntaxhighlight> {{out}} <pre>