Display a linear combination: Difference between revisions
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* you don't show null terms, unless the whole combination is null. For instance while the output "0" is fine, "e(0) + 0*e(3)" or "0 + e(1)" are wrong. |
* you don't show null terms, unless the whole combination is null. For instance while the output "0" is fine, "e(0) + 0*e(3)" or "0 + e(1)" are wrong. |
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* you don't show scalars when they are equal to one or minus one. For instance the string "1*e(3)" is wrong. |
* you don't show scalars when they are equal to one or minus one. For instance the string "1*e(3)" is wrong. |
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* you don't prefix by '-' if it follows a preceding term. Instead you use subtraction. Thus "e(4) - e(5)" is |
* you don't prefix by '-' if it follows a preceding term. Instead you use subtraction. Thus "e(4) - e(5)" is correct while "e(4) + -e(5)" is wrong. |
Revision as of 12:54, 11 October 2015
Display a linear combination is a draft programming task. It is not yet considered ready to be promoted as a complete task, for reasons that should be found in its talk page.
The purpose of this task is to display a finite linear combination in an infinite vector basis .
Write a function that, when given a finite list of scalars , creates a string representing the linear combination
Your output must comply to the following rules:
- you don't show null terms, unless the whole combination is null. For instance while the output "0" is fine, "e(0) + 0*e(3)" or "0 + e(1)" are wrong.
- you don't show scalars when they are equal to one or minus one. For instance the string "1*e(3)" is wrong.
- you don't prefix by '-' if it follows a preceding term. Instead you use subtraction. Thus "e(4) - e(5)" is correct while "e(4) + -e(5)" is wrong.