Display a linear combination: Difference between revisions

Line 36:
<br><br>
 
=={{header|C}}==
Accepts vector coefficients from the command line, prints usage syntax if invoked with no arguments. This implementation can handle floating point values but displays integer values as integers. All test case results shown with invocation.
<lang C>
/*Abhishek Ghosh, 24th September 2017*/
 
#include<stdlib.h>
#include<stdio.h>
 
int main(int argC, char* argV[])
{
int i,zeroCount= 0,firstNonZero = -1;
double* vector;
if(argC == 1){
printf("Usage : %s <Vector component coefficients seperated by single space>",argV[0]);
}
else{
printf("Vector for [");
for(i=1;i<argC;i++){
printf("%s,",argV[i]);
}
printf("\b] -> ");
vector = (double*)malloc((argC-1)*sizeof(double));
for(i=1;i<=argC;i++){
vector[i-1] = atof(argV[i]);
if(vector[i-1]==0.0)
zeroCount++;
if(vector[i-1]!=0.0 && firstNonZero==-1)
firstNonZero = i-1;
}
 
if(zeroCount == argC){
printf("0");
}
else{
for(i=0;i<argC;i++){
if(i==firstNonZero && vector[i]==1)
printf("e%d ",i+1);
else if(i==firstNonZero && vector[i]==-1)
printf("- e%d ",i+1);
else if(i==firstNonZero && vector[i]<0 && fabs(vector[i])-abs(vector[i])>0.0)
printf("- %lf e%d ",fabs(vector[i]),i+1);
else if(i==firstNonZero && vector[i]<0 && fabs(vector[i])-abs(vector[i])==0.0)
printf("- %ld e%d ",labs(vector[i]),i+1);
else if(i==firstNonZero && vector[i]>0 && fabs(vector[i])-abs(vector[i])>0.0)
printf("%lf e%d ",vector[i],i+1);
else if(i==firstNonZero && vector[i]>0 && fabs(vector[i])-abs(vector[i])==0.0)
printf("%ld e%d ",vector[i],i+1);
else if(fabs(vector[i])==1.0 && i!=0)
printf("%c e%d ",(vector[i]==-1)?'-':'+',i+1);
else if(i!=0 && vector[i]!=0 && fabs(vector[i])-abs(vector[i])>0.0)
printf("%c %lf e%d ",(vector[i]<0)?'-':'+',fabs(vector[i]),i+1);
else if(i!=0 && vector[i]!=0 && fabs(vector[i])-abs(vector[i])==0.0)
printf("%c %ld e%d ",(vector[i]<0)?'-':'+',labs(vector[i]),i+1);
}
}
}
free(vector);
return 0;
}
</lang>
Output:
<pre>
C:\rossetaCode>vectorDisplay.exe 1 2 3
Vector for [1,2,3] -> e1 + 2 e2 + 3 e3
C:\rossetaCode>vectorDisplay.exe 0 0 0
Vector for [0,0,0] -> 0
C:\rossetaCode>vectorDisplay.exe 0 1 2 3
Vector for [0,1,2,3] -> e2 + 2 e3 + 3 e4
C:\rossetaCode>vectorDisplay.exe 1 0 3 4
Vector for [1,0,3,4] -> e1 + 3 e3 + 4 e4
C:\rossetaCode>vectorDisplay.exe 1 2 0
Vector for [1,2,0] -> e1 + 2 e2
C:\rossetaCode>vectorDisplay.exe 0 0 0
Vector for [0,0,0] -> 0
C:\rossetaCode>vectorDisplay.exe 0
Vector for [0] -> 0
C:\rossetaCode>vectorDisplay.exe 1 1 1
Vector for [1,1,1] -> e1 + e2 + e3
C:\rossetaCode>vectorDisplay.exe -1 -1 -1
Vector for [-1,-1,-1] -> - e1 - e2 - e3
C:\rossetaCode>vectorDisplay.exe -1 -2 0 -3
Vector for [-1,-2,0,-3] -> - e1 - 2 e2 - 3 e4
C:\rossetaCode>vectorDisplay.exe -1
Vector for [-1] -> - e1
</pre>
=={{header|EchoLisp}}==
<lang scheme>
503

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