De Polignac numbers: Difference between revisions

=={{header|Julia}}==

* Needs Primes.jl

<syntaxhighlight lang="julia">

using Primes

using Printf

function isdepolignac(n::Integer)

iseven(n) && return false

twopows = Iterators.map(x -> 2^x, 0:floor(Int, log2(n)))

return !any(twopows) do twopow

isprime(n - twopow)

end

end

function depolignacs()

naturals = Iterators.countfrom()

return Iterators.filter(isdepolignac, naturals)

end

for (i, dep) in Iterators.enumerate(depolignacs())

if i == 1

println("The first 50 de Polignac numbers:")

end

if i <= 50

@printf "%4d" dep

i % 10 == 0 ? println() : print(" ")

end

if i == 50

println()

end

if i == 1000

println("The 1000th de Polignac number is $dep")

println()

end

if i == 10000

println("The 10000th de Polignac number is $dep")

break

end

end

</syntaxhighlight>

<pre>

The first 50 de Polignac numbers:

1 127 149 251 331 337 373 509 599 701

757 809 877 905 907 959 977 997 1019 1087

1199 1207 1211 1243 1259 1271 1477 1529 1541 1549

1589 1597 1619 1649 1657 1719 1759 1777 1783 1807

1829 1859 1867 1927 1969 1973 1985 2171 2203 2213

The 1000th de Polignac number is 31941

The 10000th de Polignac number is 273421

</pre>