Day of the week: Difference between revisions

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(→‎{{header|Python}}: Updated output)
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<pre>
December 25th is a Sunday in: 2011 2016 2022 2033 2039 2044 2050 2061 2067 2072 2078 2089 2095 2101 2107 2112 2118
</pre>
 
=={{header|ALGOL-M}}==
<lang algol>
BEGIN
 
% CALCULATE P MOD Q %
INTEGER FUNCTION MOD(P, Q);
INTEGER P, Q;
BEGIN
MOD := P - Q * (P / Q);
END;
 
COMMENT
RETURN DAY OF WEEK (SUN=0, MON=1, ETC.) FOR A GIVEN
GREGORIAN CALENDAR DATE USING ZELLER'S CONGRUENCE;
INTEGER FUNCTION DAYOFWEEK(MO, DA, YR);
INTEGER MO, DA, YR;
BEGIN
INTEGER Y, C, Z;
IF MO < 3 THEN
BEGIN
MO := MO + 10;
YR := YR - 1;
END
ELSE MO := MO - 2;
Y := MOD(YR, 100);
C := YR / 100;
Z := (26 * MO - 2) / 10;
Z := Z + DA + Y + (Y / 4) + (C /4) - 2 * C + 777;
DAYOFWEEK := MOD(Z, 7);
END;
 
% MAIN PROGRAM STARTS HERE %
INTEGER YEAR, SUNDAY;
SUNDAY := 0;
WRITE("CHRISTMAS WILL FALL ON A SUNDAY IN THESE YEARS:");
FOR YEAR := 2008 STEP 1 UNTIL 2121 DO
BEGIN
IF DAYOFWEEK(12, 25, YEAR) = SUNDAY THEN
WRITE(YEAR);
END;
 
END
</lang>
{{out}}
<pre>
CHRISTMAS WILL FALL ON A SUNDAY IN THESE YEARS:
2011
2016
2022
2033
2039
2044
2050
2061
2067
2072
2078
2089
2095
2101
2107
2112
2118
</pre>
 
Line 3,703 ⟶ 3,768:
next year
end
</lang>
{{out}}
<pre>Christmas will fall on a Sunday in
211

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