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Count how many vowels and consonants occur in a string: Difference between revisions
Count how many vowels and consonants occur in a string (view source)
Revision as of 02:43, 11 October 2021
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Now is the time for all good men to come to the aid of their country.
69 characters, 22 vowels, 31 consonants, 16 other
</pre>
=={{header|C}}==
<lang C>/*
https://rosettacode.org/wiki/Count_how_many_vowels_and_consonants_occur_in_a_string
*/
#include <stdio.h>
char vowels[] = {'a','e','i','o','u','\n'};
int len(char * str) {
int i = 0;
while (str[i] != '\n') i++;
return i;
}
int isvowel(char c){
int b = 0;
int v = len(vowels);
for(int i = 0; i < v;i++) {
if(c == vowels[i]) {
b = 1;
break;
}
}
return b;
}
int isletter(char c){
return ((c >= 'a') && (c <= 'z') || (c >= 'A') && (c <= 'Z'));
}
int isconsonant(char c){
return isletter(c) && !isvowel(c);
}
int cVowels(char * str) {
int i = 0;
int count = 0;
while (str[i] != '\n') {
if (isvowel(str[i])) {
count++;;
}
i++;
}
return count;
}
int cConsonants(char * str ) {
int i = 0;
int count = 0;
while (str[i] != '\n') {
if (isconsonant(str[i])) {
count++;
}
i++;
}
return count;
}
int main() {
char buff[] = "This is 1 string\n";
printf("%4d, %4d, %4d, %s\n", cVowels(buff), cConsonants(buff), len(buff), buff);
char buff2[] = "This is a second string\n";
printf("%4d, %4d, %4d, %s\n", cVowels(buff2), cConsonants(buff2), len(buff2), buff2);
printf("a: %d\n", isvowel('a'));
printf("b: %d\n", isvowel('b'));
printf("Z: %d\n", isconsonant('Z'));
printf("1: %d\n", isletter('1'));
}
</lang>
{{out}}
<pre>
3, 9, 16, This is 1 string
6, 13, 23, This is a second string
a: 1
b: 0
Z: 1
1: 0
</pre>
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