Count how many vowels and consonants occur in a string: Difference between revisions

=={{header|Python}}==

{{tr|Julia}}

<lang python>def isvowel(c):

""" true if c is an English vowel (ignore y) """

return c in ['a', 'e', 'i', 'o', 'u', 'A', 'E', "I", 'O', 'U']

def isletter(c):

""" true if in English standard alphabet """

return 'a' <= c <= 'z' or 'A' <= c <= 'Z'

def isconsonant(c):

""" true if an English consonant """

return not isvowel(c) and isletter(c)

def vccounts(s):

""" case insensitive vowel counts, total and unique """

a = list(s.lower())

au = set(a)

return sum([isvowel(c) for c in a]), sum([isconsonant(c) for c in a]), \

sum([isvowel(c) for c in au]), sum([isconsonant(c) for c in au])

def testvccount():

teststrings = [

"Forever Python programming language",

"Now is the time for all good men to come to the aid of their country."]

for s in teststrings:

vcnt, ccnt, vu, cu = vccounts(s)

print(f"String: {s}\n Vowels: {vcnt} (distinct {vu})\n Consonants: {ccnt} (distinct {cu})\n")

testvccount()

</lang>{{out}}<pre>

String: Forever Python programming language

Vowels: 11 (distinct 5)

Consonants: 21 (distinct 11)

String: Now is the time for all good men to come to the aid of their country.

Vowels: 22 (distinct 5)

Consonants: 31 (distinct 13)

</pre>