Count how many vowels and consonants occur in a string: Difference between revisions
Thundergnat (talk | contribs) m →{{header|Ring}}: more verbiage |
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=={{header|Ring}}==
<lang ring>
load "stdlib.ring"
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for n = 1 to len(str)
strc = str[n]
if isvowel(str[n]) = 1
vowel += 1
ok
else not isvowel(str[n]) and ascii(str[n]) > 64 and ascii(str[n]) < 123▼
if isconsonant(strc)
cons += 1
ok
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see "In string occur " + cons + " consonants" + nl
see "done..." + nl
func isconsonant(c)
bool1 = not isvowel(c)
bool2 = (ascii(c) > 64 and ascii(c) < 91)
if bool1 and (bool2 or bool3)
return 1
else
return 0
ok
</lang>
{{out}}
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Input string = "Forever Ring Programming Language"
In string occur 11 vowels
In string occur
done...
</pre>
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Revision as of 16:00, 26 July 2021
- Task
- Count how many vowels and consonants occur in a string
Factor
<lang factor>USING: ascii combinators io kernel math.statistics prettyprint sequences ;
CONSTANT: vowels "aeiouAEIOU"
- letter-type ( char -- str )
{ { [ dup vowels member? ] [ drop "vowel" ] } { [ Letter? ] [ "consonant" ] } [ "other" ] } cond ;
"Forever Factor programming language" "Now is the time for all good men to come to the aid of their country." [ dup ... " -> " write [ letter-type ] histogram-by . nl ] bi@</lang>
- Output:
"Forever Factor programming language" -> H{ { "other" 3 } { "consonant" 20 } { "vowel" 12 } } "Now is the time for all good men to come to the aid of their country." -> H{ { "other" 16 } { "consonant" 31 } { "vowel" 22 } }
Go
Same approach as the Wren entry. <lang go>package main
import (
"fmt" "strings"
)
func main() {
const ( vowels = "aeiou" consonants = "bcdfghjklmnpqrstvwxyz" ) strs := []string{ "Forever Go programming language", "Now is the time for all good men to come to the aid of their country.", } for _, str := range strs { fmt.Println(str) str = strings.ToLower(str) vc, cc := 0, 0 vmap := make(map[rune]bool) cmap := make(map[rune]bool) for _, c := range str { if strings.ContainsRune(vowels, c) { vc++ vmap[c] = true } else if strings.ContainsRune(consonants, c) { cc++ cmap[c] = true } } fmt.Printf("contains (total) %d vowels and %d consonants.\n", vc, cc) fmt.Printf("contains (distinct %d vowels and %d consonants.\n\n", len(vmap), len(cmap)) }
}</lang>
- Output:
Forever Go programming language contains (total) 11 vowels and 17 consonants. contains (distinct 5 vowels and 8 consonants. Now is the time for all good men to come to the aid of their country. contains (total) 22 vowels and 31 consonants. contains (distinct 5 vowels and 13 consonants.
Raku
Note that the task does not ask for the total count of vowels and consonants, but for how many occur.
<lang perl6>my @vowels = <a e i o u>; my @consonants = ;
sub letter-check ($string) {
my $letters = $string.lc.comb.Set; "{sum $letters{@vowels}} vowels and {sum $letters{@consonants}} consonants occur in the string \"$string\"";
}
say letter-check "Forever Ring Programming Language";</lang>
- Output:
5 vowels and 8 consonants occur in the string "Forever Ring Programming Language"
Ring
<lang ring> load "stdlib.ring" see "working..." + nl str = '"' + "Forever Ring Programming Language" + '"' vowel = 0 cons =0
for n = 1 to len(str)
strc = str[n] if isvowel(str[n]) = 1 vowel += 1 ok if isconsonant(strc) cons += 1 ok
next
see "Input string = " + str + nl see "In string occur " + vowel + " vowels" + nl see "In string occur " + cons + " consonants" + nl see "done..." + nl
func isconsonant(c)
bool1 = not isvowel(c) bool2 = (ascii(c) > 64 and ascii(c) < 91) bool3 = (ascii(c) > 96 and ascii(c) < 123) if bool1 and (bool2 or bool3) return 1 else return 0 ok
</lang>
- Output:
working... Input string = "Forever Ring Programming Language" In string occur 11 vowels In string occur 19 consonants done...
Wren
In the absence of any indications to the contrary, we take a simplistic view of only considering English ASCII vowels (not 'y') and consonants. <lang ecmascript>import "/str" for Str
var vowels = "aeiou" var consonants = "bcdfghjklmnpqrstvwxyz"
var strs = [
"Forever Wren programming language", "Now is the time for all good men to come to the aid of their country."
]
for (str in strs) {
System.print(str) str = Str.lower(str) var vc = 0 var cc = 0 var vmap = {} var cmap = {} for (c in str) { if (vowels.contains(c)) { vc = vc + 1 vmap[c] = true } else if (consonants.contains(c)) { cc = cc + 1 cmap[c] = true } } System.print("contains (total) %(vc) vowels and %(cc) consonants.") System.print("contains (distinct) %(vmap.count) vowels and %(cmap.count) consonants.\n")
}</lang>
- Output:
Forever Wren programming language contains (total) 11 vowels and 19 consonants. contains (distinct) 5 vowels and 9 consonants. Now is the time for all good men to come to the aid of their country. contains (total) 22 vowels and 31 consonants. contains (distinct) 5 vowels and 13 consonants.