Count how many vowels and consonants occur in a string: Difference between revisions

=={{header|11l}}==

{{trans|Python}}

<lang 11l>F isvowel(c)

‘ true if c is an English vowel (ignore y) ’

R c C [‘a’, ‘e’, ‘i’, ‘o’, ‘u’, ‘A’, ‘E’, ‘I’, ‘O’, ‘U’]

F isletter(c)

‘ true if in English standard alphabet ’

R c C ‘a’..‘z’ | c C ‘A’..‘Z’

F isconsonant(c)

‘ true if an English consonant ’

R !isvowel(c) & isletter(c)

F vccounts(s)

‘ case insensitive vowel counts, total and unique ’

V a = Array(s.lowercase())

V au = Set(a)

R (sum( a.map(c -> Int(isvowel(c)))), sum( a.map(c -> Int(isconsonant(c)))),

sum(au.map(c -> Int(isvowel(c)))), sum(au.map(c -> Int(isconsonant(c)))))

V s = ‘Now is the time for all good men to come to the aid of their country.’

V (vcnt, ccnt, vu, cu) = vccounts(s)

print(‘String: ’s"\n Vowels: "vcnt‘ (distinct ’vu")\n Consonants: "ccnt‘ (distinct ’cu‘)’)</lang>

{{out}}

<pre>

String: Now is the time for all good men to come to the aid of their country.

Vowels: 22 (distinct 5)

Consonants: 31 (distinct 13)

</pre>