Count how many vowels and consonants occur in a string: Difference between revisions

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Now is the time for all good men to come to the aid of their country.
Now is the time for all good men to come to the aid of their country.
69 characters, 22 vowels, 31 consonants, 16 other
69 characters, 22 vowels, 31 consonants, 16 other
</pre>

=={{header|C}}==
<lang C>/*

https://rosettacode.org/wiki/Count_how_many_vowels_and_consonants_occur_in_a_string

*/

#include <stdio.h>

char vowels[] = {'a','e','i','o','u','\n'};

int len(char * str) {
int i = 0;
while (str[i] != '\n') i++;
return i;
}

int isvowel(char c){
int b = 0;
int v = len(vowels);
for(int i = 0; i < v;i++) {
if(c == vowels[i]) {
b = 1;
break;
}
}
return b;
}

int isletter(char c){
return ((c >= 'a') && (c <= 'z') || (c >= 'A') && (c <= 'Z'));
}

int isconsonant(char c){
return isletter(c) && !isvowel(c);
}

int cVowels(char * str) {
int i = 0;
int count = 0;
while (str[i] != '\n') {
if (isvowel(str[i])) {
count++;;
}
i++;
}
return count;
}

int cConsonants(char * str ) {
int i = 0;
int count = 0;
while (str[i] != '\n') {
if (isconsonant(str[i])) {
count++;
}
i++;
}
return count;
}

int main() {

char buff[] = "This is 1 string\n";
printf("%4d, %4d, %4d, %s\n", cVowels(buff), cConsonants(buff), len(buff), buff);

char buff2[] = "This is a second string\n";
printf("%4d, %4d, %4d, %s\n", cVowels(buff2), cConsonants(buff2), len(buff2), buff2);


printf("a: %d\n", isvowel('a'));
printf("b: %d\n", isvowel('b'));
printf("Z: %d\n", isconsonant('Z'));
printf("1: %d\n", isletter('1'));
}
</lang>
{{out}}
<pre>
3, 9, 16, This is 1 string

6, 13, 23, This is a second string

a: 1
b: 0
Z: 1
1: 0

</pre>
</pre>


Retrieved from "https://rosettacode.org/wiki/Count_how_many_vowels_and_consonants_occur_in_a_string"