Circles of given radius through two points: Difference between revisions
Circles of given radius through two points (view source)
Revision as of 19:10, 3 March 2021
, 3 years agoAdded Delphi example
(OCaml implementation) |
MaiconSoft (talk | contribs) (Added Delphi example) |
||
Line 624:
ERROR: radius of zero
</pre>
=={{header|Delphi}}==
{{libheader| System.SysUtils}}
{{libheader| System.Types}}
{{libheader| System.Math}}
{{Trans|C}}
<lang Delphi>
program Circles_of_given_radius_through_two_points;
{$APPTYPE CONSOLE}
uses
System.SysUtils,
System.Types,
System.Math;
const
Cases: array[0..9] of TPointF = ((
x: 0.1234;
y: 0.9876
), (
x: 0.8765;
y: 0.2345
), (
x: 0.0000;
y: 2.0000
), (
x: 0.0000;
y: 0.0000
), (
x: 0.1234;
y: 0.9876
), (
x: 0.1234;
y: 0.9876
), (
x: 0.1234;
y: 0.9876
), (
x: 0.8765;
y: 0.2345
), (
x: 0.1234;
y: 0.9876
), (
x: 0.1234;
y: 0.9876
));
radii: array of double = [2.0, 1.0, 2.0, 0.5, 0.0];
procedure FindCircles(p1, p2: TPointF; radius: double);
var
separation, mirrorDistance: double;
begin
separation := p1.Distance(p2);
if separation = 0.0 then
begin
if radius = 0 then
write(format(#10'No circles can be drawn through (%.4f,%.4f)', [p1.x, p1.y]))
else
write(format(#10'Infinitely many circles can be drawn through (%.4f,%.4f)',
[p1.x, p1.y]));
exit;
end;
if separation = 2 * radius then
begin
write(format(#10'Given points are opposite ends of a diameter of the circle with center (%.4f,%.4f) and radius %.4f',
[(p1.x + p2.x) / 2, (p1.y + p2.y) / 2, radius]));
exit;
end;
if separation > 2 * radius then
begin
write(format(#10'Given points are farther away from each other than a diameter of a circle with radius %.4f',
[radius]));
exit;
end;
mirrorDistance := sqrt(Power(radius, 2) - Power(separation / 2, 2));
write(#10'Two circles are possible.');
write(format(#10'Circle C1 with center (%.4f,%.4f), radius %.4f and Circle C2 with center (%.4f,%.4f), radius %.4f',
[(p1.x + p2.x) / 2 + mirrorDistance * (p1.y - p2.y) / separation, (p1.y + p2.y)
/ 2 + mirrorDistance * (p2.x - p1.x) / separation, radius, (p1.x + p2.x) / 2
- mirrorDistance * (p1.y - p2.y) / separation, (p1.y + p2.y) / 2 -
mirrorDistance * (p2.x - p1.x) / separation, radius]));
end;
begin
for var i := 0 to 4 do
begin
write(#10'Case ', i + 1,')');
findCircles(cases[2 * i], cases[2 * i + 1], radii[i]);
end;
readln;
end.</lang>
=={{header|Elixir}}==
| |||