Bitwise operations

Bitwise operations
You are encouraged to solve this task according to the task description, using any language you may know.

Basic Data Operation
This is a basic data operation. It represents a fundamental action on a basic data type.

You may see other such operations in the Basic Data Operations category, or:

Integer Operations
Arithmetic | Comparison

Boolean Operations
Bitwise | Logical

String Operations
Concatenation | Interpolation | Comparison | Matching

Memory Operations
Pointers & references | Addresses

Write a function to perform a bitwise AND, OR, and XOR on two integers and perform a bitwise NOT on the first number.

Ada

The following program performs all required operations and prints the resulting values in base 2 for easy checking of the bit values.

with Ada.Text_Io; use Ada.Text_Io;

procedure Bitwise is
   type Byte is mod 2**8;
   package Byte_Io is new Ada.Text_Io.Modular_Io(Byte);
   
   A : Byte := 255;
   B : Byte := 170;
begin
   Put("A and B = "); Byte_Io.Put(Item => A and B, Base => 2); New_Line;
   Put("A or B  = "); Byte_IO.Put(Item => A or B, Base => 2); New_Line;
   Put("A xor B = "); Byte_Io.Put(Item => A xor B, Base => 2); New_Line;
   Put("Not A   = "); Byte_IO.Put(Item => not A, Base => 2); New_Line;
end bitwise;

The output of this program is:

A and B = 2#10101010#
A or B  = 2#11111111#
A xor B = 2#1010101#
Not A   = 2#0#

BASIC

Compiler: QuickBasic 4.5

SUB bitwise (a, b)
  PRINT a AND b
  PRINT a OR b
  PRINT a XOR b
  PRINT NOT a
END SUB

C

void bitwise(int a, int b)
{
  printf("a and b: %d\n", a & b);
  printf("a or b: %d\n", a | b);
  printf("a xor b: %d\n", a ^ b);
  printf("not a: %d\n", ~a);
}

Forth

: bitwise ( a b -- )
  cr ." a = " over . ." b = " dup .
  cr ." a and b = " 2dup and .
  cr ." a  or b = " 2dup  or .
  cr ." a xor b = " over xor .
  cr ." not a = " invert . ;

Haskell

The operations in Data.Bits work on Int, Integer, and any of the sized integer and word types.

import Data.Bits

a = 255
b = 170

a_and_b = a .&. b
a_or_b  = a .|. b
a_xor_b = a `xor` b
not_a   = complement a

Java

public static void bitwise(int a, int b){
  System.out.println("a AND b: " + (a & b));
  System.out.println("a OR b: "+ (a | b));
  System.out.println("a XOR b: "+ (a ^ b));
  System.out.println("NOT a: " + ~a);
}

The call:

bitwise(4, 7);

will output:

a AND b: 4
a OR b: 7
a XOR b: 3
NOT a: -5