Babbage problem: Difference between revisions

m (RE)
Line 194:
findBabbageNumber :: Integer
findBabbageNumber = head $ filter myCondition [1..]
where
squarestring :: Integer -> String
squarestring d = show ( d ^ 2 )
myCondition :: Integer -> Bool
myCondition n = dropmod ( ( length $ squarestring n )^ - 62 ) (squarestring n )1000000 == "269696"
 
--print out the result
262

edits