24 game/Solve: Difference between revisions
< 24 game
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answer = input("Expression %i: " % trial) |
answer = input("Expression %i: " % trial) |
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chk = check(answer, digits) |
chk = check(answer, digits) |
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if answer |
if answer == '?': |
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answer = solve(digits) |
answer = solve(digits) |
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break |
break |
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if answer.lower() == 'q': |
if answer.lower() == 'q': |
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break |
break |
||
if answer |
if answer == '!': |
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digits = choose4() |
digits = choose4() |
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print ("New digits:", ' '.join(digits)) |
print ("New digits:", ' '.join(digits)) |
Revision as of 08:04, 1 November 2009
24 game/Solve
You are encouraged to solve this task according to the task description, using any language you may know.
You are encouraged to solve this task according to the task description, using any language you may know.
Write a function that given four digits subject to the rules of the 24 game, computes an expression to solve the game if possible.
Show examples of solutions generated by the function
Python
The function is called solve, and is integrated into the game player. The docstring of the solve function shows examples of its use when isolated at the Python command line. <lang Python>
The 24 Game Player
Given any four digits in the range 1 to 9, which may have repetitions, Using just the +, -, *, and / operators; and the possible use of brackets, (), show how to make an answer of 24.
An answer of "q" will quit the game. An answer of "!" will generate a new set of four digits. An answer of "?" will compute an expression for the current digits. Otherwise you are repeatedly asked for an expression until it evaluates to 24
Note: you cannot form multiple digit numbers from the supplied digits, so an answer of 12+12 when given 1, 2, 2, and 1 would not be allowed.
from __future__ import division, print_function from itertools import permutations, combinations, product, \
chain
from pprint import pprint as pp import random, ast, re import sys
if sys.version_info[0] < 3:
input = raw_input from itertools import izip_longest as zip_longest
else:
from itertools import zip_longest
def choose4():
'four random digits >0 as characters' return [str(random.randint(1,9)) for i in range(4)]
def welcome(digits):
print (__doc__) print ("Your four digits: " + ' '.join(digits))
def check(answer, digits):
allowed = set('() +-*/\t'+.join(digits)) ok = all(ch in allowed for ch in answer) and \ all(digits.count(dig) == answer.count(dig) for dig in set(digits)) \ and not re.search('\d\d', answer) if ok: try: ast.parse(answer) except: ok = False return ok
def solve(digits):
"""\ >>> solve(list('3246')) Solution found: 2 + 3 * 6 + 4 '2 + 3 * 6 + 4' >>> solve(list('4788')) Solution found: ( 4 + 7 - 8 ) * 8 '( 4 + 7 - 8 ) * 8' >>> solve(list('3322')) Solution found: ( 2 + 2 * 3 ) * 3 '( 2 + 2 * 3 ) * 3' >>> solve(list('1111')) No solution found for: 1 1 1 1 '!' >>> solve(list('123456')) Solution found: 1 + 2 + 3 * ( 4 + 5 ) - 6 '1 + 2 + 3 * ( 4 + 5 ) - 6' >>> """ digilen = len(digits) # length of an exp without brackets exprlen = 2 * digilen - 1 # permute all the digits digiperm = sorted(set(permutations(digits))) # All the possible operator combinations opcomb = list(product('+-*/', repeat=digilen-1)) # All the bracket insertion points: brackets = [()] + [(x,y) for x in range(0, exprlen, 2) for y in range(x+4, exprlen+2, 2) if (x,y) != (0,exprlen+1)] for d in digiperm: for ops in opcomb: ex = list(chain.from_iterable(zip_longest(d, ops, fillvalue=))) for b in brackets: exp = ex[::] if b: exp.insert(b[0], '(') exp.insert(b[1], ')') txt = .join(exp) try: num = eval(txt) except ZeroDivisionError: continue if num == 24: ans = ' '.join(exp).rstrip() print ("Solution found:",ans) return ans print ("No solution found for:", ' '.join(digits)) return '!'
def main():
digits = choose4() welcome(digits) trial = 0 answer = chk = ans = False while not (chk and ans == 24): trial +=1 answer = input("Expression %i: " % trial) chk = check(answer, digits) if answer == '?': answer = solve(digits) break if answer.lower() == 'q': break if answer == '!': digits = choose4() print ("New digits:", ' '.join(digits)) continue if not chk: print ("The input '%s' was wonky!" % answer) else: ans = eval(answer) print (" = ", ans) if ans == 24: print ("Thats right!") print ("Thank you and goodbye")
main()</lang>
Sample Output
The 24 Game Player Given any four digits in the range 1 to 9, which may have repetitions, Using just the +, -, *, and / operators; and the possible use of brackets, (), show how to make an answer of 24. An answer of "q" will quit the game. An answer of "!" will generate a new set of four digits. An answer of "?" will compute an expression for the current digits. Otherwise you are repeatedly asked for an expression until it evaluates to 24 Note: you cannot form multiple digit numbers from the supplied digits, so an answer of 12+12 when given 1, 2, 2, and 1 would not be allowed. Your four digits: 6 7 9 5 Expression 1: ? Solution found: 6 - ( 5 - 7 ) * 9 Thank you and goodbye