Loops/Continue
You are encouraged to solve this task according to the task description, using any language you may know.
Show the following output using one loop.
1, 2, 3, 4, 5 6, 7, 8, 9, 10
Ada
Ada has no continue reserved word, nor does it need one. The continue reserved word is only syntactic sugar for operations that can be achieved without it as in the following example.
<lang ada> with Ada.Text_Io; use Ada.Text_Io;
procedure Loop_Continue is begin
for I in 1..10 loop
Put(Integer'Image(I));
if I mod 5 = 0 then
New_Line;
else
Put(",");
end if;
end loop;
end Loop_Continue; </lang>
ALGOL 68
ALGOL 68 has no continue reserved word, nor does it need one. The continue reserved word is only syntactic sugar for operations that can be achieved without it as in the following example:
FOR i FROM 1 TO 10 DO
print ((i,
IF i MOD 5 = 0 THEN
new line
ELSE
","
FI
))
OD
Output:
+1, +2, +3, +4, +5
+6, +7, +8, +9, +10
C
<lang c>for(int i = 1;i <= 10; i++){
printf("%d", i);
if(i % 5 == 0){
printf("\n");
continue;
}
printf(", ");
}</lang>
C++
<lang cpp>for(int i = 1;i <= 10; i++){
cout << i;
if(i % 5 == 0){
cout << endl;
continue;
}
cout << ", ";
}</lang>
ColdFusion
Remove the leading space from the line break tag.
<cfscript>
for( i = 1; i <= 10; i++ )
{
writeOutput( i );
if( 0 == i % 5 )
{
writeOutput( "< br />" );
continue;
}
writeOutput( "," );
}
</cfscript>
D
<lang d>for(int i = 1;i <= 10; i++){
writef(i);
if(i % 5 == 0){
writefln();
continue;
}
writef(", ");
}</lang>
Fortran
<lang fortran>do i = 1, 10
write(*, '(I0)', advance='no') i
if ( mod(i, 5) == 0 ) then
write(*,*)
cycle
end if
write(*, '(A)', advance='no') ', '
end do</lang>
J
J is array-oriented, so there is very little need for loops. For example, one could satisfy this task this way:
_2}."1'lq<, >'8!:2>:i.2 5
J does support loops for those times they can't be avoided (just like many languages support gotos for those time they can't be avoided).
3 : 0 ] 10
z=.''
for_i. 1 + i.y do.
z =. z , ": i
if. 0 = 5 | i do.
z 1!:2 ]2
z =. ''
continue.
end.
z =. z , ', '
end.
i.0 0
)
Though it's rare to see J code like this.
Java
<lang java>for(int i = 1;i <= 10; i++){
System.out.print(i);
if(i % 5 == 0){
System.out.println();
continue;
}
System.out.print(", ");
}</lang>
MAXScript
for i in 1 to 10 do
(
format "%" i
if mod i 5 == 0 then
(
format "\n"
continue
) continue
format ", "
)
Modula-3
Modula-3 defines the keyword RETURN as an exception, but when it is used with no arguments it works just like continue in C.
Note, however, that RETURN only works inside a procedure or a function procedure; use EXIT otherwise.
Module code and imports are omitted.
FOR i := 1 TO 10 DO
IO.PutInt(i);
IF i MOD 5 = 0 THEN
IO.Put("\n");
RETURN;
END;
IO.Put(", ");
END;
Perl
<lang perl>foreach (1..10) {
print $_;
if ($_ % 5 == 0) {
print "\n";
next;
}
print ', ';
}</lang>
PHP
<lang php>for ($i = 1; $i <= 10; $i++) {
echo $i;
if ($i % 5 == 0) {
echo "\n";
continue;
}
echo ', ';
}</lang>
Pop11
lvars i;
for i from 1 to 10 do
printf(i, '%p');
if i rem 5 = 0 then
printf('\n');
nextloop;
endif;
printf(', ')
endfor;
Python
<lang python>for i in xrange(1,11):
if i % 5 == 0:
print i
continue
print i, ",",</lang>
Ruby
<lang ruby>for i in 1..10 do
print i
if i % 5 == 0 then
puts
next
end
print ', '
end</lang>
UnixPipes
yes \ | cat -n | head -n 10 | xargs -n 5 echo | tr ' ' ,
Visual Basic .NET
For i = 1 To 10
Console.Write(i)
If i Mod 5 = 0 Then
Console.WriteLine()
Else
Console.Write(", ")
End If
Next