XML/Input: Difference between revisions
< XML
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m (Alphabetizing, highlighting) |
(→{{header|J}}: noted that XPath is implicitly discouraged as a soln, for some reason, so use SAX instead.) |
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=={{header|J}}== |
=={{header|J}}== |
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J's system includes XML processing libraries |
J's system includes several XML processing libraries. This task is probably best addressed using XPath (this is the type of problem XPath was designed to solve), but the task description implicitly discourages that method. So we can use the SAX library instead: |
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load'xml/sax' |
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saxclass 'Students' |
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XSL xslt XML |
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startElement =: ([: smoutput 'Name' getAttribute~ [)^:('Student'-:]) |
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cocurrent'base' |
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⚫ | |||
process_Students_ XML |
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April |
April |
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Bob |
Bob |
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Emily |
Emily |
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and the definition of <tt>XML</tt>: |
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XML =: noun define |
XML =: noun define |
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<Students> |
<Students> |
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<Student Name="Emily" /> |
<Student Name="Emily" /> |
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</Students> |
</Students> |
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) |
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⚫ | |||
XSL =: noun define |
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<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform" xmlns:h="http://www.w3.org/1999/xhtml"> |
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<xsl:output method="text" encoding="UTF-8" media-type="text/plain" /> |
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<xsl:template match="/"> |
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<xsl:apply-templates select="/Students/Student" /> |
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</xsl:template> |
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<xsl:template match="/Students/Student"> |
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<xsl:value-of select="@Name" /> |
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<!-- Platform-independent line breaks (instead of or something) --> |
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<xsl:text><![CDATA[ |
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]]></xsl:text> |
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</xsl:template> |
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</xsl:stylesheet> |
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) |
) |
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Revision as of 21:56, 23 January 2009
XML/Input
You are encouraged to solve this task according to the task description, using any language you may know.
You are encouraged to solve this task according to the task description, using any language you may know.
Given the below XML fragment, extract the list of names using whatever means desired. If the only viable method is to use XPath, refer the reader to the task XML_and_XPath.
<Students> <Student Name="April" /> <Student Name="Bob" /> <Student Name="Chad" /> <Student Name="Dave" /> <Student Name="Emily" /> </Students>
Expected Output
April Bob Chad Dave Emily
ActionScript
<actionscript> package {
import flash.display.Sprite;
public class XMLReading extends Sprite { public function XMLReading() { var xml:XML = <Students> <Student Name="April" /> <Student Name="Bob" /> <Student Name="Chad" /> <Student Name="Dave" /> <Student Name="Emily" /> </Students>; for each(var node:XML in xml..Student) { trace(node.@Name); } } }
} </actionscript>
J
J's system includes several XML processing libraries. This task is probably best addressed using XPath (this is the type of problem XPath was designed to solve), but the task description implicitly discourages that method. So we can use the SAX library instead:
load'xml/sax' saxclass 'Students' startElement =: ([: smoutput 'Name' getAttribute~ [)^:('Student'-:]) cocurrent'base' process_Students_ XML April Bob Chad Dave Emily
and the definition of XML:
XML =: noun define <Students> <Student Name="April" /> <Student Name="Bob" /> <Student Name="Chad" /> <Student Name="Dave" /> <Student Name="Emily" /> </Students> )
OCaml
# #directory "+site-lib/xml-light" (* or maybe just "+xml-light" *) ;; # #load "xml-light.cma" ;; # let x = Xml.parse_string " <Students> <Student Name=\"April\" /> <Student Name=\"Bob\" /> <Student Name=\"Chad\" /> <Student Name=\"Dave\" /> <Student Name=\"Emily\" /> </Students>" in Xml.iter (function (Xml.Element ("Student", [("Name", name)], [])) -> print_endline name | _ -> ()) x ;; April Bob Chad Dave Emily - : unit = ()
Visual Basic .NET
Dim xml = <Students>
<Student Name="April"/>
<Student Name="Bob"/>
<Student Name="Chad"/>
<Student Name="Dave"/>
<Student Name="Emily"/>
</Students>
Dim names = (From node In xml...<Student> Select node.@Name).ToArray
For Each name In names
Console.WriteLine(name)
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