Word wheel: Difference between revisions
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Write a program to solve the above "word wheel" puzzle. Specifically: |
Write a program to solve the above "word wheel" puzzle. Specifically: |
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:* Find all words of 3 or more letters using only the letters in the string "ndeokgelw". |
:* Find all words of 3 or more letters using only the letters in the string "ndeokgelw". |
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:* For this task we'll use lowercase English letters exclusively. |
:* For this task we'll use lowercase English letters exclusively. |
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A "word" is defined to be any string contained in the file located at http://wiki.puzzlers.org/pub/wordlists/unixdict.txt. |
A "word" is defined to be any string contained in the file located at http://wiki.puzzlers.org/pub/wordlists/unixdict.txt. |
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dictionary please state which one you have used. |
<br>If you prefer to use a different dictionary, please state which one you have used. |
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<br><br> |
<br><br> |
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Revision as of 18:48, 5 July 2020
A "word wheel" is a type of word game commonly found on the "puzzle" page of newspapers. You are presented with nine letters arranged in a circle or 3×3 grid. The objective is to find as many words as you can using only the letters contained in the wheel or grid. Each word must contain the letter in the centre of the wheel or grid. Usually there will be a minimum word length of 3 or 4 characters. Each letter may only be used as many times as it appears in the wheel or grid.
For example:
N D E O K G E L W
- Task
Write a program to solve the above "word wheel" puzzle. Specifically:
- Find all words of 3 or more letters using only the letters in the string "ndeokgelw".
- All words must contain the central letter "k".
- Each letter may be used only as many times as it appears in the string.
- For this task we'll use lowercase English letters exclusively.
A "word" is defined to be any string contained in the file located at http://wiki.puzzlers.org/pub/wordlists/unixdict.txt.
If you prefer to use a different dictionary, please state which one you have used.
C
<lang c>#include <stdbool.h>
- include <stdio.h>
- define MAX_WORD 80
- define LETTERS 26
bool is_letter(char c) { return c >= 'a' && c <= 'z'; }
int index(char c) { return c - 'a'; }
void word_wheel(const char* letters, char central, int min_length, FILE* dict) {
int max_count[LETTERS] = { 0 };
for (const char* p = letters; *p; ++p) {
char c = *p;
if (is_letter(c))
++max_count[index(c)];
}
char word[MAX_WORD + 1] = { 0 };
while (fgets(word, MAX_WORD, dict)) {
int count[LETTERS] = { 0 };
for (const char* p = word; *p; ++p) {
char c = *p;
if (c == '\n') {
if (p >= word + min_length && count[index(central)] > 0)
printf("%s", word);
} else if (is_letter(c)) {
int i = index(c);
if (++count[i] > max_count[i]) {
break;
}
} else {
break;
}
}
}
}
int main(int argc, char** argv) {
const char* dict = argc == 2 ? argv[1] : "unixdict.txt";
FILE* in = fopen(dict, "r");
if (in == NULL) {
perror(dict);
return 1;
}
word_wheel("ndeokgelw", 'k', 3, in);
fclose(in);
return 0;
}</lang>
- Output:
eke elk keel keen keg ken keno knee kneel knew know knowledge kong leek week wok woke
C++
The puzzle parameters are hard-coded but could easily be replaced by e.g. command line arguments. <lang cpp>#include <array>
- include <iostream>
- include <fstream>
- include <map>
- include <string>
- include <vector>
// A multiset specialized for strings consisting of lowercase // letters ('a' to 'z'). class letterset { public:
explicit letterset(const std::string& str) {
count_.fill(0);
for (char c : str)
++count_[index(c)];
}
bool contains(const letterset& set) const {
for (size_t i = 0; i < count_.size(); ++i) {
if (set.count_[i] > count_[i])
return false;
}
return true;
}
unsigned int count(char c) const {
return count_[index(c)];
}
bool is_valid() const {
return count_[0] == 0;
}
private:
static bool is_letter(char c) { return c >= 'a' && c <= 'z'; }
static int index(char c) { return is_letter(c) ? c - 'a' + 1 : 0; }
// elements 1..26 contain the number of times each lowercase
// letter occurs in the word
// element 0 is the number of other characters in the word
std::array<unsigned int, 27> count_;
};
template <typename iterator, typename separator> std::string join(iterator begin, iterator end, separator sep) {
std::string result;
if (begin != end) {
result += *begin++;
for (; begin != end; ++begin) {
result += sep;
result += *begin;
}
}
return result;
}
int main(int argc, char** argv) {
const int min_length = 3;
const char* letters = "ndeokgelw";
const char central_letter = 'k';
const char* dict(argc == 2 ? argv[1] : "unixdict.txt");
std::ifstream in(dict);
if (!in) {
std::cerr << "Cannot open file " << dict << '\n';
return 1;
}
letterset set(letters);
std::string word;
std::map<size_t, std::vector<std::string>> words;
while (getline(in, word)) {
if (word.size() < min_length)
continue;
letterset subset(word);
if (subset.count(central_letter) > 0 && set.contains(subset)) {
words[word.size()].push_back(word);
}
}
for (const auto& p : words) {
const auto& v = p.second;
auto n = v.size();
std::cout << "Found " << n << " " << (n == 1 ? "word" : "words")
<< " of length " << p.first << ": "
<< join(v.begin(), v.end(), ", ") << '\n';
}
return 0;
}</lang>
- Output:
Found 5 words of length 3: eke, elk, keg, ken, wok Found 10 words of length 4: keel, keen, keno, knee, knew, know, kong, leek, week, woke Found 1 word of length 5: kneel Found 1 word of length 9: knowledge
Factor
<lang factor>USING: assocs io.encodings.ascii io.files kernel math math.statistics prettyprint sequences sorting ;
! Only consider words longer than two letters and words that ! contain elt.
- pare ( elt seq -- new-seq )
[ [ member? ] keep length 2 > and ] with filter ;
- words ( input-str path -- seq )
[ [ midpoint@ ] keep nth ] [ ascii file-lines pare ] bi* ;
- ?<= ( m n/f -- ? ) dup f = [ nip ] [ <= ] if ;
! Can we make sequence 1 with the elements in sequence 2?
- can-make? ( seq1 seq2 -- ? )
[ histogram ] bi@ [ swapd at ?<= ] curry assoc-all? ;
- solve ( input-str path -- seq )
[ words ] keepd [ can-make? ] curry filter ;
"ndeokgelw" "unixdict.txt" solve [ length ] sort-with .</lang>
- Output:
{
"eke"
"elk"
"keg"
"ken"
"wok"
"keel"
"keen"
"keno"
"knee"
"knew"
"know"
"kong"
"leek"
"week"
"woke"
"kneel"
"knowledge"
}
Go
<lang go>package main
import (
"bytes" "fmt" "io/ioutil" "log" "sort" "strings"
)
func main() {
b, err := ioutil.ReadFile("unixdict.txt")
if err != nil {
log.Fatal("Error reading file")
}
letters := "deegklnow"
words := bytes.Split(b, []byte{'\n'})
var found []string
for _, word := range words {
le := len(word)
if le > 2 && le <= 9 && bytes.IndexByte(word, 'k') >= 0 {
lets := letters
ok := true
for i := 0; i < le; i++ {
c := word[i]
ix := sort.Search(len(lets), func(i int) bool { return lets[i] >= c })
if ix < len(lets) && lets[ix] == c {
lets = lets[0:ix] + lets[ix+1:]
} else {
ok = false
break
}
}
if ok {
found = append(found, string(word))
}
}
}
fmt.Println("The following", len(found), "words are the solutions to the puzzle:")
fmt.Println(strings.Join(found, "\n"))
}</lang>
- Output:
The following 17 words are the solutions to the puzzle: eke elk keel keen keg ken keno knee kneel knew know knowledge kong leek week wok woke
Haskell
<lang haskell>import System.IO (readFile) import Data.Char (toLower) import Data.List (sort)
gridWords :: [String] -> [String] -> [String] gridWords grid =
filter (((&&) . (2 <) . length) <*> (((&&) . elem mid) <*> wheelFit wheel)) where cs = toLower <$> concat grid wheel = sort cs mid = cs !! 4
wheelFit :: String -> String -> Bool wheelFit wheel word = go wheel (sort word)
where
go _ [] = True
go [] _ = False
go (w:ws) ccs@(c:cs)
| w == c = go ws cs
| otherwise = go ws ccs
main :: IO () main = do
s <- readFile "unixdict.txt" mapM_ putStrLn $ gridWords ["NDE", "OKG", "ELW"] (lines s)</lang>
- Output:
eke elk keel keen keg ken keno knee kneel knew know knowledge kong leek week wok woke
JavaScript
A version using local access to the dictionary, through the macOS JavaScript for Automation API.
<lang JavaScript>(() => {
'use strict';
// main :: IO ()
const main = () =>
console.log(unlines(
gridWords(['NDE', 'OKG', 'ELW'])(
lines(readFile('unixdict.txt'))
)
));
// gridWords :: [String] -> [String] -> [String]
const gridWords = grid =>
lexemes => {
const
wheel = sort(toLower(concat(grid))),
wSet = new Set(wheel),
mid = wheel[4];
return lexemes.filter(w => {
const cs = chars(w);
return 2 < cs.length && cs.every(
c => wSet.has(c)
) && elem(mid)(cs) && (
wheelFit(wheel, cs)
);
});
};
// wheelFit :: [Char] -> [Char] -> Bool
const wheelFit = (wheel, word) => {
const go = (ws, cs) =>
0 === cs.length ? (
true
) : 0 === ws.length ? (
false
) : ws[0] === cs[0] ? (
go(ws.slice(1), cs.slice(1))
) : go(ws.slice(1), cs);
return go(wheel, sort(word));
};
// ----------------- GENERIC FUNCTIONS -----------------
// chars :: String -> [Char]
const chars = s =>
s.split();
// concat :: a -> [a] // concat :: [String] -> String const concat = xs => ( ys => 0 < ys.length ? ( ys.every(Array.isArray) ? ( [] ) : ).concat(...ys) : ys )(list(xs));
// elem :: Eq a => a -> [a] -> Bool
const elem = x =>
// True if xs contains an instance of x.
xs => xs.some(y => x === y);
// lines :: String -> [String]
const lines = s =>
// A list of strings derived from a single
// newline-delimited string.
0 < s.length ? (
s.split(/[\r\n]/)
) : [];
// list :: StringOrArrayLike b => b -> [a]
const list = xs =>
// xs itself, if it is an Array,
// or an Array derived from xs.
Array.isArray(xs) ? (
xs
) : Array.from(xs || []);
// readFile :: FilePath -> IO String
const readFile = fp => {
// The contents of a text file at the
// path file fp.
const
e = $(),
ns = $.NSString
.stringWithContentsOfFileEncodingError(
$(fp).stringByStandardizingPath,
$.NSUTF8StringEncoding,
e
);
return ObjC.unwrap(
ns.isNil() ? (
e.localizedDescription
) : ns
);
};
// sort :: Ord a => [a] -> [a]
const sort = xs => list(xs).slice()
.sort((a, b) => a < b ? -1 : (a > b ? 1 : 0));
// toLower :: String -> String
const toLower = s =>
// Lower-case version of string.
s.toLocaleLowerCase();
// unlines :: [String] -> String
const unlines = xs =>
// A single string formed by the intercalation
// of a list of strings with the newline character.
xs.join('\n');
// MAIN --- return main();
})();</lang>
- Output:
eke elk keel keen keg ken keno knee kneel knew know knowledge kong leek week wok woke
Julia
<lang julia>using Combinatorics
const tfile = download("http://wiki.puzzlers.org/pub/wordlists/unixdict.txt") const wordlist = Dict(w => 1 for w in split(read(tfile, String), r"\s+"))
function wordwheel(wheel, central)
returnlist = String[]
for combo in combinations([string(i) for i in wheel])
if central in combo && length(combo) > 2
for perm in permutations(combo)
word = join(perm)
if haskey(wordlist, word) && !(word in returnlist)
push!(returnlist, word)
end
end
end
end
return returnlist
end
println(wordwheel("ndeokgelw", "k"))
</lang>
- Output:
["ken", "keg", "eke", "elk", "wok", "keno", "knee", "keen", "knew", "kong", "know", "woke", "keel", "leek", "week", "kneel", "knowledge"]
Python
<lang python>import urllib.request from collections import Counter
GRID = """
N D E
O K G
E L W
"""
def getwords(url='http://wiki.puzzlers.org/pub/wordlists/unixdict.txt'):
"Return lowercased words of 3 to 9 characters" words = urllib.request.urlopen(url).read().decode().strip().lower().split() return (w for w in words if 2 < len(w) < 10)
def solve(grid, dictionary):
gridcount = Counter(grid)
mid = grid[4]
return [word for word in dictionary
if mid in word and not (Counter(word) - gridcount)]
if __name__ == '__main__':
chars = .join(GRID.strip().lower().split())
found = solve(chars, dictionary=getwords())
print('\n'.join(found))</lang>
- Output:
eke elk keel keen keg ken keno knee kneel knew know knowledge kong leek week wok woke
Or, using a local copy of the dictionary, and a recursive test of wheel fit:
<lang python>Word wheel
from os.path import expanduser
- gridWords :: [String] -> [String] -> [String]
def gridWords(grid):
The subset of words in ws which contain the
central letter of the grid, and can be completed
by single uses of some or all of the remaining
letters in the grid.
def go(ws):
cs = .join(grid).lower()
wheel = sorted(cs)
wset = set(wheel)
mid = cs[4]
return [
w for w in ws
if 2 < len(w) and (mid in w) and (
all(c in wset for c in w)
) and wheelFit(wheel, w)
]
return go
- wheelFit :: String -> String -> Bool
def wheelFit(wheel, word):
True if a given word can be constructed
from (single uses of) some subset of
the letters in the wheel.
def go(ws, cs):
return True if not cs else (
False if not ws else (
go(ws[1:], cs[1:]) if ws[0] == cs[0] else (
go(ws[1:], cs)
)
)
)
return go(wheel, sorted(word))
- -------------------------- TEST --------------------------
- main :: IO ()
def main():
Word wheel matches for a given grid in a copy of
http://wiki.puzzlers.org/pub/wordlists/unixdict.txt
print('\n'.join(
gridWords(['NDE', 'OKG', 'ELW'])(
readFile('~/unixdict.txt').splitlines()
)
))
- ------------------------ GENERIC -------------------------
- readFile :: FilePath -> IO String
def readFile(fp):
The contents of any file at the path
derived by expanding any ~ in fp.
with open(expanduser(fp), 'r', encoding='utf-8') as f:
return f.read()
- MAIN ---
if __name__ == '__main__':
main()</lang>
- Output:
eke elk keel keen keg ken keno knee kneel knew know knowledge kong leek week wok woke
Raku
Everything is adjustable through command line parameters.
Defaults to task specified wheel, unixdict.txt, minimum 3 letters.
Using Terminal::Boxer from the Raku ecosystem.
<lang perl6>use Terminal::Boxer;
my %*SUB-MAIN-OPTS = :named-anywhere;
unit sub MAIN ($wheel = 'ndeokgelw', :$dict = './unixdict.txt', :$min = 3);
my $must-have = $wheel.comb[4].lc;
my $has = $wheel.comb».lc.Bag;
my %words; $dict.IO.slurp.words».lc.map: {
next if not .contains($must-have) or .chars < $min;
%words{.chars}.push: $_ if .comb.Bag ⊆ $has;
};
say "Using $dict, minimum $min letters.";
print rs-box :3col, :3cell, :indent("\t"), $wheel.comb».uc;
printf "%d letters: %s\n", .key, .value.sort.join(', ') for %words.sort; </lang>
- Output:
<lang>raku word-wheel.raku</lang>
Using ./unixdict.txt, minimum 3 letters. ╭───┬───┬───╮ │ N │ D │ E │ ├───┼───┼───┤ │ O │ K │ G │ ├───┼───┼───┤ │ E │ L │ W │ ╰───┴───┴───╯ 3 letters: eke, elk, keg, ken, wok 4 letters: keel, keen, keno, knee, knew, know, kong, leek, week, woke 5 letters: kneel 9 letters: knowledge
- Larger dictionary
Using the much larger dictionary words.txt file from https://github.com/dwyl/english-words
<lang>raku word-wheel.raku --dict=./words.txt</lang>
Using ./words.txt, minimum 3 letters. ╭───┬───┬───╮ │ N │ D │ E │ ├───┼───┼───┤ │ O │ K │ G │ ├───┼───┼───┤ │ E │ L │ W │ ╰───┴───┴───╯ 3 letters: dkg, dkl, eek, egk, eke, ekg, elk, gok, ked, kee, keg, kel, ken, keo, kew, kln, koe, kol, kon, lek, lgk, nek, ngk, oke, owk, wok 4 letters: deek, deke, doek, doke, donk, eked, elke, elko, geek, genk, gonk, gowk, keel, keen, keld, kele, kend, keno, keon, klee, knee, knew, know, koel, koln, kone, kong, kwon, leek, leke, loke, lonk, okee, oken, week, welk, woke, wolk, wonk 5 letters: dekle, dekow, gleek, kedge, kendo, kleon, klong, kneed, kneel, knowe, konde, oklee, olnek, woken 6 letters: gowked, keldon, kelwen, knowle, koleen 8 letters: weeklong 9 letters: knowledge
- Exercise adjustable parameters
<lang>raku word-wheel.raku iuymslleb --dict=./words.txt --min=4</lang>
Using ./words.txt, minimum 4 letters. ╭───┬───┬───╮ │ I │ U │ Y │ ├───┼───┼───┤ │ M │ S │ L │ ├───┼───┼───┤ │ L │ E │ B │ ╰───┴───┴───╯ 4 letters: bels, beys, bise, blus, bmus, bsem, bsie, bslm, bsme, bums, busy, buys, byes, eisb, elis, ells, elms, elsi, elsy, elys, emus, emys, ills, ilse, imsl, isle, islm, islu, ismy, leis, leys, libs, lies, lise, lues, luis, lums, lyes, lyse, mels, mibs, mils, mise, misy, msie, musb, muse, sbli, sell, semi, siey, sile, sill, sime, sium, slbm, sleb, sley, slim, slub, slue, slum, suey, suiy, sull, sumi, sumy, syli, syll, uims 5 letters: belis, bells, belus, bemis, biles, bills, bisme, blues, bulls, bulse, busey, buyse, eblis, ellis, embus, emuls, eulis, ileus, illus, ilyse, isbel, iseum, lesiy, lesli, lesly, lieus, liles, limbs, limes, limsy, lisle, lubes, luise, lusby, lyles, melis, mells, miles, mills, misly, mlles, mules, mulls, mulse, musie, musil, myles, mysel, sebum, selby, selim, selli, selly, sibel, sible, sibyl, silly, silyl, simul, slily, slime, slimy, smell, smile, smily, sully, sybil, syble, yells, yills, ylems, yules, yusem 6 letters: bellis, bisley, bluesy, blueys, bluism, blumes, bulies, bullis, busily, elymus, embusy, illyes, imbues, libels, libuse, limbus, limeys, milles, milsey, muesli, muleys, musily, mysell, sibell, sibley, simule, slimly, smelly, smiley, umbels, umbles 7 letters: besully, bullies, bullism, elysium, illumes, mulleys, sibylle, silybum, sublime, sybille 8 letters: bullyism, semibull 9 letters: sublimely
REXX
Quite a bit of boilerplate was included in this REXX example.
No assumption was made as the "case" of the words (upper/lower/mixed case). Duplicate words were detected and
eliminated (god and God), as well as words that didn't contain all Roman (Latin) letters.
The number of minimum letters can be specified, as well as the dictionary fileID and the letters in the word wheel (grid).
Additional information is also provided concerning how many words have been skipped due to the various filters. <lang rexx>/*REXX pgm finds (dictionary) words which can be found in a specified word wheel (grid).*/ parse arg grid minL iFID . /*obtain optional arguments from the CL*/ if grid==|grid=="," then grid= 'ndeokgelw' /*Not specified? Then use the default.*/ if minL==|minL=="," then minL= 3 /* " " " " " " */ if iFID==|iFID=="," then iFID= 'UNIXDICT.TXT' /* " " " " " " */ oMinL= minL; minL= abs(minL) /*if negative, then don't show a list. */ gridU= grid; upper gridU /*get an uppercase version of the grid.*/ Lg= length(grid); Hg= Lg % 2 + 1 /*get length of grid & the middle char.*/ ctr= substr(grid, Hg, 1); upper ctr /*get uppercase center letter in grid. */ wrds= 0 /*# words that are in the dictionary. */ wees= 0 /*" " " " too short. */ bigs= 0 /*" " " " too long. */ dups= 0 /*" " " " duplicates. */ ills= 0 /*" " " contain "not" letters.*/ good= 0 /*" " " contain center letter. */ say ' Reading the file: ' iFID @.= . /*uppercase non─duplicated dict. words.*/ $= /*the list of dictionary words in grid.*/
do recs=0 while lines(iFID)\==0 /*process all words in the dictionary. */
_= linein(iFID) /*read a word (line of text) from dict.*/
u= space(_, 0); upper u; L= length(u) /*elide superfluous blanks from a word.*/
L= length(u) /*obtain the length of the word. */
if @.u\==. then do; dups= dups+1; iterate; end /*is this a duplicate? */
if L<minL then do; wees= wees+1; iterate; end /*is the word too short? */
if L>Lg then do; bigs= bigs+1; iterate; end /*is the word too long? */
if \datatype(u,'U') then do; ills= ills+1; iterate; end /*has word non─letters? */
@.u= /*signify that U is a dictionary word*/
wrds= wrds + 1 /*bump the number of "good" dist. words*/
if pos(ctr, u)==0 then iterate /*word doesn't have center grid letter.*/
good= good + 1 /*bump # center─letter words in dict. */
if verify(u, gridU)\==0 then iterate /*word contains a letter not in grid. */
if pruned(u, gridU) then iterate /*have all the letters not been found? */
$= $ u /*add this word to the "found" list. */
end /*recs*/
say say ' number of records (lines) in the dictionary: ' right( commas(recs), 9) say ' number of ill─formed words in the dictionary: ' right( commas(ills), 9) say ' number of duplicate words in the dictionary: ' right( commas(dups), 9) say ' number of too─small words in the dictionary: ' right( commas(wees), 9) say ' number of too─long words in the dictionary: ' right( commas(bigs), 9) say ' number of acceptable words in the dictionary: ' right( commas(wrds), 9) say ' number center─letter words in the dictionary: ' right( commas(good), 9) say ' the minimum length of words that can be used: ' right( commas(minL), 9) say ' the word wheel (grid) being used: ' grid say ' center of the word wheel (grid) being used: ' right('↑', Hg) say; #= words($); $= strip($) say ' number of word wheel words in the dictionary: ' right( commas(# ), 9) if #==0 | oMinL<0 then exit # say say ' The list of word wheel words found:'; say copies('─', length($)); say lower($) exit # /*stick a fork in it, we're all done. */ /*──────────────────────────────────────────────────────────────────────────────────────*/ lower: arg aa; @='abcdefghijklmnopqrstuvwxyz'; @u=@; upper @u; return translate(aa,@,@U) commas: parse arg _; do jc=length(_)-3 to 1 by -3; _=insert(',', _, jc); end; return _ /*──────────────────────────────────────────────────────────────────────────────────────*/ pruned: procedure; parse arg aa,gg /*obtain word to be tested, & the grid.*/
do n=1 for length(aa); p= pos( substr(aa,n,1), gg); if p==0 then return 1
gg= overlay(., gg, p) /*"rub out" the found character in grid*/
end /*n*/; return 0 /*signify that the AA passed the test*/</lang>
- output when using the default inputs:
Reading the file: UNIXDICT.TXT
number of records (lines) in the dictionary: 25,105
number of ill─formed words in the dictionary: 123
number of duplicate words in the dictionary: 0
number of too─small words in the dictionary: 159
number of too─long words in the dictionary: 4,158
number of acceptable words in the dictionary: 20,664
number center─letter words in the dictionary: 1,630
the minimum length of words that can be used: 3
the word wheel (grid) being used: ndeokgelw
center of the word wheel (grid) being used: ↑
number of word wheel words in the dictionary: 17
The list of word wheel words found:
─────────────────────────────────────────────────────────────────────────────────────
eke elk keel keen keg ken keno knee kneel knew know knowledge kong leek week wok woke
Note: my "personal" dictionary that I built (over 915,000 words), there are 178 words that are in the (above) word wheel.
- output when using the inputs: satRELinp -3
(I am trying for a maximum word wheel count for the UNIXDICT dictionary;
the negative minimum word length indicates to not list the words found.)
Thanks to userid Paddy3118, a better grid was found.
Reading the file: UNIXDICT.TXT
number of records (lines) in the dictionary: 25,105
number of ill─formed words in the dictionary: 123
number of duplicate words in the dictionary: 0
number of too─small words in the dictionary: 159
number of too─long words in the dictionary: 4,158
number of acceptable words in the dictionary: 20,664
number center─letter words in the dictionary: 11,623
the minimum length of words that can be used: 3
the word wheel (grid) being used: satRELinp
center of the word wheel (grid) being used: ↑
number of word wheel words in the dictionary: 234
Wren
<lang ecmascript>import "io" for File import "/sort" for Find
var letters = ["d", "e", "e", "g", "k", "l", "n", "o","w"]
var words = File.read("unixdict.txt").split("\n") var found = [] for (word in words) {
if (word.count > 2 && word.count <= 9 && word.indexOf("k") >= 0) {
var lets = letters.toList
var ok = true
for (c in word) {
var ix = Find.first(lets, c)
if (ix == - 1) {
ok = false
break
}
lets.removeAt(ix)
}
if (ok) found.add(word)
}
}
System.print("The following %(found.count) words are the solutions to the puzzle:") System.print(found.join("\n"))</lang>
- Output:
The following 17 words are the solutions to the puzzle: eke elk keel keen keg ken keno knee kneel knew know knowledge kong leek week wok woke