Word frequency: Difference between revisions
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=={{header|Java}}==
This is relatively simple in Java.<br />
I used a ''URL'' class to download to content, a ''BufferedReader'' class to examine the text line-for-line, a ''Pattern'' and ''Matcher'' to identify words, and a ''Map'' to hold to values.
<syntaxhighlight lang="java">
import java.io.BufferedReader;
import java.io.IOException;
import java.io.InputStreamReader;
import java.net.URI;
import java.net.URISyntaxException;
import java.net.URL;
import java.util.ArrayList;
import java.util.Collections;
import java.util.HashMap;
import java.util.List;
import java.util.Map;
import java.util.regex.Matcher;
import java.util.regex.Pattern;
</syntaxhighlight>
<syntaxhighlight lang="java">
void printWordFrequency() throws URISyntaxException, IOException {
Map<String, Integer> map = new HashMap<>();
URL url = new URI("https://www.gutenberg.org/files/135/135-0.txt").toURL();
try (BufferedReader reader = new BufferedReader(new InputStreamReader(url.openStream()))) {
Pattern pattern = Pattern.compile("(\\w+)");
Matcher matcher;
String line;
String word;
while ((line = reader.readLine()) != null) {
matcher = pattern.matcher(line);
while (matcher.find()) {
word = matcher.group().toLowerCase();
if (map.containsKey(word)) {
map.put(word, map.get(word) + 1);
} else {
map.put(word, 1);
}
}
}
/* print out top 10 */
List<Map.Entry<String, Integer>> list = new ArrayList<>(map.entrySet());
list.sort(Map.Entry.comparingByValue());
Collections.reverse(list);
int count = 1;
for (Map.Entry<String, Integer> value : list) {
System.out.printf("%-20s%,7d%n", value.getKey(), value.getValue());
if (count++ == 10) break;
}
}
}
</syntaxhighlight>
<pre>
the 41,043
of 19,952
and 14,938
a 14,539
to 13,942
in 11,208
he 9,646
was 8,620
that 7,922
it 6,659
</pre>
<br />
An alternate demonstration
{{trans|Kotlin}}
<syntaxhighlight lang="java">import java.io.IOException;
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