Welch's t-test: Difference between revisions

Content added Content deleted
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denominator = 1.0;
denominator = 1.0;
for (unsigned int n = 1; n < 300000; n++) {
for (unsigned int n = 1; n < 300000; n++) {
denominator *= (1 / (1+ a*0.5/(n*(a+0.5+n))));
denominator /= (1+ a*0.5/(n*(a+0.5+n)));
}
}
denominator = (a+0.5)*denominator/(a*0.5);
denominator = (a+0.5)*denominator/(a*0.5);